Wad is the upload path?

i want to upload document to the site but i cannot determine where is the path and it alway show me tt system cannot find the file specific. my tomcat is put in C:\Program Files\Apache Group\Tomcat 4.1\webapps\ROOT. so can any kind ppl out there pls tell me wad the path is.thank
<%@ page import="java.sql.*" %>
<%@ page import="java.io.*" %>
<%
String connectionURL = "jdbc:mysql://localhost:3306/Project";
Connection connection = null;
Statement statement = null;
ResultSet rs = null;
%>
<HTML>
<HEAD> <TITLE>Success</TITLE> </HEAD>
<BODY>
     <table width="480" border="0">
<tr>
<td width="160" height="46"><div align="center"><strong><font size="2" face="Arial, Helvetica, sans-serif"><img src="images/addDoc.gif" width="160" height="28" border="0"></font></strong></div></td>
<td width="160"><div align="center"><strong><font size="2" face="Arial, Helvetica, sans-serif"><img src="images/deleteDoc.gif" width="160" height="28" border="0"></font></strong></div></td>
<td width="160"><div align="center"><strong><img src="images/adminMode.gif" width="160" height="28" border="0"></strong></div></td>
</tr>
</table>
          <table width="650" border="0" cellspacing="4" cellpadding="1">
          <tr>
          <td valign="top"> <p><strong><font color="#000000" size="2" face="Verdana, Arial, Helvetica, sans-serif">
     Confirmation file uploaded:</font></strong><br>
     </td>
</tr>
</table>
<%
String contentType = request.getContentType();
System.out.println("Content type is :: " +contentType);
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
String file = new String(dataBytes);
String saveFile = request.getParameter("saveFile");
saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
//out.print(dataBytes);
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
//out.println(boundary);
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
String webpath = "SC37/";
String filename = saveFile;
String path="Apache Group/Tomcat 4.1/webapps/ROOT/";
//saveFile = "/export/home/cheeloong/jakarta-tomcat-5.0.28/webapps/biome/ITSCdoc/" +saveFile;
saveFile= path + webpath + filename;
FileOutputStream fileOut = new FileOutputStream(saveFile);
//fileOut.write(dataBytes);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
%>
     <form name="test_form" action="ConfirmInsertDoc.jsp" method="POST">
     <table border="0" width="650" cellpadding="0" cellspacing="2">
<tr>
<td width="241"><strong><font size="2" face="Arial, Helvetica, sans-serif"><span class="style3">Document
     Title<span class=style7><font color=#FF0000>*</font> </span></span></font></strong></td>
<td width="303"><textarea name=docTitle cols=25 rows=4 id=textarea></textarea></td>
</tr>
<tr>
     <td width="245"><strong><font size="2" face=Arial, Helvetica, sans-serif><span class=style3>Document
Id<span class=style7><font color=#FF0000>*</font></span> </span></font></strong>
<font size=2 face=Arial, Helvetica, sans-serif color=#FF0000><span class=style3>
<b>ISO/IEC JTC1/SC37 N</b></font></td>
     <td><input name=docId type=Number id=docId2 size=20></td>
</tr>
<tr>
     <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>Document
     Date<span class=style7><font color=#FF0000>*</font></span><font color=#FF0000>
     (DD-MM-YYYY)</font></span></font></strong></td>
     <td><input name="docDate" type=Text id=docDate2>
     <A HREF="javascript:void(0)" onClick="showCalendar(test_form.docDate,'dd/mm/yyyy','Choose date')">
               <IMG SRC="images/CAL-icon.gif" BORDER="0" width="16" height="16" alt="Click Here to use a calendar">
               </A></td>
</tr>
<tr>
               <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>Document
     Due Date<span class=style7><font color=#FF0000>*</font></span>
     <font color=#FF0000>(DD-MM-YYYY)</font> </span></font></strong></td>
     <td><input name="dueDate" type=TEXT id=dueDate2>
     <A HREF="javascript:void(0)" onClick="showCalendar(test_form.dueDate,'dd/mm/yyyy','Choose date')">
               <IMG SRC="images/CAL-icon.gif" BORDER="0" width="16" height="16" alt="Click Here to use a calendar">
               </A>
     </td>
</tr>
     <tr>
          <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>
     Document Type<span class=style7><font color=#FF0000>*</font></span>
     </span></font></strong></td>
     <td><input name=docType type=TEXT id=docType2 size=20></td>
     </tr>
     <tr>
     <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>Description<span class=style7><font color=#FF0000>*</font></span>
     </span></font></strong></td>
     <td><textarea name="description" cols=25 rows=4 id=textarea2></textarea></td>
</tr>
     <tr>
          <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>Source<span class=style7><font color=#FF0000>*</font></span></span></font></strong></td>
     <td><input name=source type=TEXT id=source2 size=30></td>
     </tr>
          
<tr>
<td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style3>Filename<span class=style7>
<font color=#FF0000>*</font></span></span></font></strong>
</td>
<td><font color=#FF0000><%=filename%></font></td>
</tr>
<input name="filename" type="HIDDEN" value="<%=filename%>" >

<tr>
     <td><strong><font size=2 face=Arial, Helvetica, sans-serif>
     <input name=Submit type=Submit value=Add>
     <input name=Reset type=reset value=Reset>
     </font></strong></td>
     </tr>
     <tr>
          <td><strong><font size=2 face=Arial, Helvetica, sans-serif><span class=style9><font color=#FF0000 size=1>*
          </font></span></font></strong>
          <font color=#FF0000 size=1 face=Arial, Helvetica, sans-serif><span class=style9>Compulsory
               Field</span></font></td>
     </tr>
</table>
</form>
<%
     %>
</BODY>
</HTML>

Yes, but it was broken by one the SPs. I think it has since been fixed.
Peace,
Cameron Purdy
Tangosol, Inc.
Clustering Weblogic? You're either using Coherence, or you should be!
Download a Tangosol Coherence eval today at http://www.tangosol.com/
"Ben Wheeler" <[email protected]> wrote in message
news:[email protected]..
>
>
>

Similar Messages

Unable to see the logical path and file created in FILE tcode from AL11 and unable to upload the file to this path from front end

Hi Experts,
I have created the logical path and filename in FILE tcode.I am trying to upload the pdf file to application server by using this path.But
I am getting message like "Unable to open the file".Even I cannot find the this path in AL11 tcode.Kindly anyone advise how to upload pdf file using
custom path and file created from FILE tcode.
Thanks & Regards,
Anusha.

Hi Anusha,
Please give as below.
I forget to say you cannot open the PDF in AL11 and for that you need some configuration, i think it can be done using content server,not sure completely please wait for some more suggestions.
Regards,
Pavan

How to the link/path of the file being uploaded

Hi all,
I am uploading a CSV file in apex3.2 and would like to store the actual path of the file into a custom table. I get the file name as F26222/my_filename.csv from the FILE BROWSE apex item. How can I capture the path also?
Thanks in advance.
Movva

cmovva wrote:
Hi all,
I am uploading a CSV file in apex3.2 and would like to store the actual path of the file into a custom table. I get the file name as F26222/my_filename.csv from the FILE BROWSE apex item. How can I capture the path also?For security/privacy reasons recent versions of browsers by default do not send local file path information from File Browse items to the server, nor expose the file path in the control's JavaScript methods. Firefox, Safari and Chrome only provide the filename. IE6 & IE7 still yield the path in Windows format. IE8 and Opera have adopted an irritating approach of replacing the path with a wholly imaginary "C:\fakepath\"—and this monstrosity has sadly had to be enshrined in the HTML5 spec...
Changing IE's security config setting “Include local directory path when uploading files” enables the path to be exposed in IE8, but unless you're working in an intranet environment where: IE is the only browser used; it's possible to make remote changes to this setting on every desktop; and this won't break/expose anything else, then trying to achieve this is pointless.
For more information see:
http://lists.whatwg.org/htdig.cgi/whatwg-whatwg.org/2009-March/018980.html
http://blogs.msdn.com/ie/archive/2009/03/20/rtm-platform-changes.aspx
http://developers.whatwg.org/number-state.html#file-upload-state
Please search the forum thoroughly before posting: this is the umpteenth time I've provided this information. There's even another live thread on the same topic: +{thread:id=2316750}+

Is it possible to set default path and filename to the upload UI element ?

Hello All,
Can some advise on if its possible to set a default path and filename to the upload ui element ? I will like to set a default path and filename to be uploaded to the upload UI. The user will then have the option of using that path or clicking on the browse to set another location.
Any suggestions or advise ? Thank you very much.
from
Kwok Wei

Hello VS,
So to confirm, from your opinion, you feel that its not possible to have my upload UI elememt to be displyed on the screen with the path and filename preloaded ?
Btw, do you have an email that I can reach you at ?
from
Kwok Wei

How to get the pull path name from a file upload window

Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,

Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
     org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
     org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
     org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
     org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

How to read the complete path in file upload UI

Hi,
I want to know how to read the complete path in file upload UI in java web dynpro.
I have created 1 file upload UI and than when i do browse and select some file say small.jpg from my local PC, desktop , its path is coming in file upload UI like E:\small.jpg,
I want to know how to get this path in java webdynpro code.
please let me know..

Hi Satyam,
In webdynpro java, first file stores in server location then it reads from server.
Create a button with upload and write this code OnAction
Resource is the attribute name in context of type com.sap.ide.webdynpro.uielementdefinitions.Resource, this attribute is for Resource property for Upload UI Element.
Then in OnAction of button
InputStream text = null;
       int temp=0;
       try{
            File file = new File(wdContext.currentContextElement().getResource().getResourceName().toString());
           String path = file.getAbsolutePath();
            wdComponentAPI.getMessageManager().reportSuccess(path);
       }catch(Exception e){
            e.printStackTrace();
    //@@end
Regards,
Pradeep
Edited by: pradeep_546 on May 11, 2011 12:22 PM

How to get the document path of the pictures uploaded for products?

Hi Gurus,
How to get the document path of the pictures uploaded for products uploaded through tcode COMMPR01?
Many Thanks,
Neeraj

client path.
I need to get the client path in order to download files form server to client.
Best regards,
Huy.

How to respecify the fixed path when use mm01 to upload the attachment

Now I'm need to upload some pictures to the material when I use the transcation MM01, but I don't know the default path , I guess it appoint the the database directory,
I want to respecify the path, Can anybody tell me the detailed solution
Thanks a lot.

Hi ,
you can use the .dtprofile under the home directory of each user to set the PATH variable for the users. To set the PATH for the root, you can also use /etc/profile. For each user you can also use .login
(for csh shell) and .profile(for sh & ksh shells) under their home directory to set the path variable.
regards

How to populate the whole path of the button in a field when the button is clicked.

Hi,
I have around 5 uploads in my file. I kept a hidden field on the header of the form. When ever i click on the upload button, the path of it needs to be populated in the hidden text field.
by using this.parent we can get the parent name of the element.
is there any method similar to the above one to get the whole path of the button????????

Try putting this script in the click event of the button
Hidden_Text_Field_Path.rawValue=this.somExpression;
This ought to work using either FormCalc or JavaScript. I'm not sure from your description whether you will need to use the full path name for the hidden text field or use a relative one, but that's not too hard to deal with.

LSMW: Error concerning the logical path in Specify Files step

Hi,
I am trying on an ECC 6.0 EHP6 system to upload (open) POs from an existing SAP ERP system. Since I faced some complications in batch input recording method, I decided to go with the standard batch/direct input method.
I selected object 0085 (Purchase Order) and method 0001 (Purchase Order). The program that is used is RM06EEI0. I followed all the usual steps, but in the "Specify Files" step I get the message:
'****.lsmw.conv' does not exist; edit the logical path using transaction FILE
Being aware of both the FILE and SF01 transactions, I created the logical path and file (through the FILE transaction). However, after the modification, I get the message:
Logical file '****' is not assigned to physical file '****.lsmw.conv'
There is also the related SAP Note 753511 (Logical and physical path and file name in transaction LSMW) that refers to this case.

Hi,
Click on specify file radio button>Legacy data-on the PC Front end
where input file location like C:\mydocument\desktop\test.txt
and give input in Name field: mydocument
in delimiter section > select Tabular
File structure section> tick on Field order matches source structure definition
File type: Record end marker(Text file)
then press enter key and other steps as same.
Second thing you said that you have used Batch input recording
after creation and recording finish , scroll the page below on recording and put a cursor unwanted field and remove unwanted input field.
I hope your problem will resolve. you can find the steps pdf on Google search try now.
Thanks
Sanjeet Kumar

How to specify the directory in which we want to store the uploaded files

Hello !!
I am using apache commonfile upload for uploading my files.I followed the user guide and tried to run a program,but my problem is I am not able to understand as to how to mention the directory in which the uploaded file will be saved..My code is given below :
package r;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.sql.*;
import java.util.*;
import org.apache.commons.fileupload.*;
import org.apache.commons.fileupload.servlet.*;
import org.apache.commons.fileupload.disk.*;
import org.apache.commons.io.*;
import java.lang.Exception;
public class fileupload extends HttpServlet
     public void doGet(HttpServletRequest request,HttpServletResponse response)throws IOException,ServletException
               // Check that we have a file upload request
              boolean isMultipart = ServletFileUpload.isMultipartContent(request);
             System.out.println(isMultipart);
             if (ServletFileUpload.isMultipartContent(request))
             // Create a factory for disk-based file items
               FileItemFactory factory = new DiskFileItemFactory();
               // Create a new file upload handler
               ServletFileUpload upload = new ServletFileUpload(factory);
               // Parse the request
               try {
                         List items= upload.parseRequest(request);
                         Iterator iter = items.iterator();
                         while (iter.hasNext())
                               FileItem item = (FileItem) iter.next();
                             if (item.isFormField()) //NORMAL FORM FIELD
                             String name = item.getFieldName();
                              String value = item.getString();
                              System.out.println(value);
                              else
                             String fileName = item.getName();
                             System.out.println(fileName);
                                String contentType = item.getContentType();
                              File saveTo = new File("/info/upload_files/myFile.jpeg");
                         try
                                   item.write(saveTo);
                                   System.out.println("File written" );
                         catch(Exception e)
                                     System.out.println("File not written");
                               // InputStream fs= item.getInputStream();
                               fileName = FilenameUtils.getName(fileName);
                                System.out.println(fileName);
                    }//end of try
          catch (Exception e) { }
     public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException
             doGet(request,response);
The problem is that the control doesn't reach the try statement and I get " File not written" on the console because it enters catch everytime..Please tell me how the path to the directory should be given...Rest of the code is working fine

No, the problem is that when an Exception is thrown, you ignore it completely and throw away all the information associated with it. That leaves you to guess at what the problem is. So instead of answering your guess at a good question, I'm going to suggest that in all of your catch blocks you put this code:e.printStackTrace();Then you can look at the output in the log file and see what the problem is. Start from there.

To Delete the uploaded file in Application Server

Hi Friends,
I developed an BSP Application displaying the results from ITAB though Iterator, for which , each row there is feature to upload a particular file in the Application Server, where I stored the file path into a database table field. .When I delete the the row, I am successfully get rid of the entire row including the file path.
My Question.
1. How to delete the uploaded file of the Application Server ?
Please mail me in this regard.
Regards
CSM Reddy

Hi,
you have the keyword and you have the documentation. What is your problem?
Search in the forums with keyword "delete dataset", there are lots of threads about this.
Example
Deletion of dataset in applicaiton server
deleting file from AL11 Tcode
Best regards
Renald

Issue with Getting the file path from InputFile component

Hi,
One of our requirement is like below:
I am working on ADF 11g (latest release R1) page. User will select the file and when he/she clicks on the Save button we need to store the file path in the database.
In the database file_path is varchar2(300). We need to store just the file path. I am using InputFile component but filepath is not getting inserted.
This is really urgent. It would be really appreciate if anyone can guide me on this.
Thanks
MC

Hi Mahesh,
I have manage to store the file path from the InputFile component in Jdev 11g. I found the file upload script from this forum and manage to alter it so that i could save the file path to the database. But my problem is to retrieve it back to view as a document. Hope this will help you :)
This is an example of what I have manage to save to my DB :
(CLOB) //192.168.238.53/c$/Research/Docs/0906160744/EyeCandyLog.txt
In my form, I save the file path first before I update the other fields. My code is something like this :
public void uploadFile(ValueChangeEvent valueChangeEvent) {
// Add event code here...
InputStream in;
FileOutputStream out;
if(tanda == 0){
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
id = rS01Proposal.dptProposalid();
tanda = tanda + 1;
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
System.out.println("id"+id);
proposal = id.substring(6);
System.out.println("proposal"+proposal);
UploadedFile file = (UploadedFile)valueChangeEvent.getNewValue();
String fileUploadLoc = "//192.168.238.53/c$/Research/Docs/"+id+"/";//The place where file will saved
//create upload directory
boolean exists = (new File(fileUploadLoc)).exists();
if (!exists) {
(new File(fileUploadLoc)).mkdirs();
if (file != null && file.getLength() > 0) {
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage("File Uploaded " + file.getFilename() +
" (" + file.getLength() + " bytes)");
*// extracting the file message to get the path*
context.addMessage(valueChangeEvent.getComponent().getClientId(context), message);
columnL = valueChangeEvent.getComponent().getClientId(context);
column = columnL.substring(9);
System.out.println(column);
columnLengkap = "RS01"+column.toUpperCase();
System.out.println("columnLengkap"+columnLengkap);
*try {*
out = new FileOutputStream(fileUploadLoc + "" + file.getFilename());
in = file.getInputStream();
*for (int bytes = 0; bytes < file.getLength(); bytes++) {*
out.write(in.read());
in.close();
out.close();
} catch (IOException e) {
e.printStackTrace();
} else {
String filename = file != null ? file.getFilename() : null;
String byteLength = file != null ? "" + file.getLength() : "0";
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage(FacesMessage.SEVERITY_WARN, " " + " " +
filename + " (" + byteLength + " bytes)",
null);
context.addMessage(valueChangeEvent.getComponent().getClientId(context),
message);
System.out.println(fileUploadLoc+file.getFilename());
a = fileUploadLoc+file.getFilename();
b = b + 1;
if (flagInsert == 0){
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
rS01Proposal.insertDoc(id,proposal,columnLengkap,a);
flagInsert = flagInsert + 1;
System.out.println("tanda"+ tanda);
//session
ProposalSession.storeCurrentProposalId(id);
} catch (Exception ex) {
ex.printStackTrace();
}else{
// update proses
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
rS01Proposal.updateDoc(id,proposal,columnLengkap,a);
flagInsert = flagInsert + 1;
//session
ProposalSession.storeCurrentProposalId(id);
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
}

How to get the complete path of the file that is selected using FormFile

i m working on struts..
i hv used FormFile like
<html:file property="xsdpath" value="Browse" />
need to get the whole path that i will select using browse button
for example d:\foldername\filename.java
but FormFile Api has a method getFileName(); which returns the filename, for getting the absolute path wat has to be done.
please reply bak soon
thanks in advance

here i use formfile <html:file> just to allow the
user to select a xml file .
so i need to get the whole path of the selectedfile
to parse the xml file.No you dont.
You would definitely benefit from further reading on
file upload.
<html:file> tag renders an HTML <input> element of
type file.
When a user uploads a file, this file is sent as a
stream of data, which a program (jsp/servlet) on the
server, reads and stores the data back in the form
of a file on the server.
Any server program that needs to parse the file,
should do so on the file stored on the server.
There's no point in knowing the absolute path of the
file on the client machine. If a server program can
parse a file on the client machine, why upload the
file in first case ? Get the drift ?
i also want to show my user the path he hadselected.
If you have such a requirement, then yes.
But it sounds weird to me. If you see my response
above, you will realize that the server has a copy of
the client's file uploaded and then parsed. What if
the client has changed his file after upload ?
cheers,
ram.I also have a requirement to get the whole filepath of the file selected and place this information into a table. From FormFile I can only retreive the absolute filename
Any suggestions would be helpful.
Thanks, dam

How to get the full path of a file

    If the user selects a file through a browse button, Is there a way, I can get the full path of the file. The file can be from his local hard drive as well.. Can someone advise

To upload multiple files (example is for 3), try something like this.
== Form section ==
There would be three(3) file form fields for the selection of a file/document to upload, which
each being uniquely named.
<div style="clear: both;">
<cfinput type="file" name="upload_01" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_02" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_03" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
== Processing section ==
Checks to see if any files / documents were selected for upload. If none were, then
displays an alert indicating as such. If at least one file/document was selected, then
the process would process the upload.
<cfif isdefined('form.upload_01') and trim(form.upload_01) eq "" and
isdefined('form.upload_02') and trim(form.upload_02) eq "" and
isdefined('form.upload_03') and trim(form.upload_03) eq ""
>
    <p>Did not select any files to upload</p>
<cfelse>
    <cfif isdefined('form.upload_01') and trim(form.upload_01) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_01"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_01_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_01_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_02') and trim(form.upload_02) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_02"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_02_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_02_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_03') and trim(form.upload_03) neq "">
    <cffile
        action="upload"
        destination="C:\path\to\upload\files\to"
        filefield="upload_03"
        nameconflict="overwrite"
        accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
        <cfcookie name="upload_03_doc" value="#cffile.serverfile#">
        <cfcookie name="upload_03_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cflocation url="completed.cfm" addtoken="no">
</cfif>
== Completed section ==
Can confirm to the person what files were actually uploaded, by displaying file name and file extension.
You can you use the file extension information to display a respective icon for the file type.
<cfoutput>
<cfif isdefined('cookie.upload_01_doc')>
01. #cookie.upload_01_doc# - #cookie.upload_01_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_02_doc')>
02. #cookie.upload_02_doc# - #cookie.upload_02_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_03_doc')>
03. #cookie.upload_03_doc# - #cookie.upload_03_doc_ext#<br /></cfif>
</cfoutput>
Leonard B

Wad is the upload path?

Similar Messages

Maybe you are looking for