What is the public IP in this case?!!

I have an ASA firewall,i also have a Motorola router that is actually a modem and a router and an access point in the same time (3 in 1) ;however iam only intending to use the Motorola internal ports to connect to the external ASA port, when i finish the NAT rules (which translating the internal ASA network into the outside network which is 192.168.0.0/24 which is the internal network for the Motorola router) which one is the public IP address in this case?? i mean i might not be able to get to the ASA's internal IP from the Internet because it is the internal network for the Motorola...so in this case is my only public IP on the Internet in the Motorola's external IP ? which is the ISP's IP address provided???
I am really lost on this one, any help here is much appreciated.
Thanks

Hi,
Seems to me that your public IP address will be configured on the Motorola device. In most cases the device will probably be using DHCP to get the public IP address from the ISP and therefore the IP might sometimes change. Though naturally it might be a static public IP address as I don't know the thing is handled in your case.
If you wish to have a host/server reachable from the Internet then you would probably have to configure somekind of Static PAT (Port Forward) on the Motorola device or perhaps even Static NAT the public IP address from to the external IP of the ASA (from the network 192.168.0.0/24) so that all traffic that is allowed on the Motorola device will be forwarded to the ASA (because of the 1:1 Static NAT mapping of the IP addresses)
If you need to reach your internal network remotely and dont need to host anything directly to the public network then you might be able to set up VPN Client connection to the ASA.
If you dont know the public IP address then if its a DHCP IP address from the ISP you can always check your current public IP address through some site. I for example tend to go to www.ripe.net . It shows your current IP address on the site. Naturally there should be multiple other sites that show this information.
If your public IP address is static then the ISP probably has provided you some documentation which mentions the public IP address assigned to you when you got the Internet connection.
Also you might not need to configure NAT at all on the ASA since its not an edge device. You could simply let the internal networks of ASA and the Motorola device to communicate with their original IP addresses. This would naturally require that the Motorola device has a route for the ASA internal network on it pointing towards the external IP address of the ASA.
- Jouni

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BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64biI have executed the following query on a specific index that I suspected to be smashed and got the following result
select
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from (
      select   sys_op_lbid (154813, 'L', jus.rowid) block_id,
             count (*)                            keys_per_leaf
      from xxx_table jus
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group by keys_per_leaf
order by keys_per_leaf;
keys_per_leaf     blocks
1     80
2     1108
3     2816
4     3444
5     3512
6     2891
7     2579
8     2154
9     1943
10     1287
11     1222
12     1011
13     822
14     711
15     544
16     508
17     414
18     455
19     425
20     417
21     338
22     337
23     327
24     288
25     267
26     295
27     281
28     266
29     249
30     255
31     237
32     259
33     257
34     232
35     211
36     209
37     204
38     216
39     189
40     194
41     187
42     200
43     183
44     167
45     186
46     179
47     179
48     179
49     171
50     164
51     174
52     157
53     181
54     192
55     178
56     162
57     155
58     160
59     153
60     151
61     133
62     177
63     156
64     167
65     162
66     171
67     154
68     162
69     163
70     153
71     189
72     166
73     164
74     142
75     177
76     148
77     161
78     164
79     133
80     158
81     176
82     189
83     347
84     369
85     239
86     239
87     224
88     227
89     214
90     190
91     230
92     229
93     377
94     276
95     196
96     218
97     217
98     227
99     230
100     251
101     266
102     298
103     276
104     288
105     638
106     1134
107     1152
229     1
230     1      This is a 5 columns unique key index on (id number, dat date, id2 number, dat2 date type number).
Furthermore, a space analysis of this index using dbms_space.space_usage gives the following picture
Number of blocks with at least 0 to 25% free space            = 0                   -------> total bytes = 0
Number of blocks with at least 25-50% free space              = 75                 -------> total bytes = ,5859375
Number of Blocks with with at least 50 to 75% free space = 0                   -------> Total Bytes = 0
number of blocks with at least 75 to 100% free space        = 0                   -------> total bytes = 0
Number of full blocks with no free space                              = 99848           -------> total bytes = 780,0625
Total blocks ______________________________
99923
Total size MB______________________________
799,384It seems for me that this index needs to be either coalesced or compressed.
Then, what would be the best option in your opinion?
Thanks in advance
Mohamed Houri
Edited by: Mohamed Houri on 12-janv.-2011 1:18

So let me continue my case
I first compressed the index as follows
alter index my_index rebuild compress 2;which immediately presents two new situations
(a) index space
Number of blocks with at least 0 to 25% free space    = 0                -------> total bytes = 0
Number of blocks with at least 25-50% free space      = 40              -------> total bytes =, 3125
Number of Blocks with at least 50 to 75% free space   = 0                -------> total Bytes = 0
Number of blocks with at least 75 to 100% free space = 0                -------> total bytes = 0
Number of full blocks with no free space                = 32361           -------> total bytes = 252, 8203125
Total blocks ______________________________
32401
Total size Mb______________________________
259,208meaning that the compress command freed up 67487 leaf blocks and reduced the size of the index from to 799,384 MB to 259,208 MB.
It also shows a relative nice pictue of number of keys per leaf block (when compared to the previous situation)
(b) on the number of key per leaf block
KEYS_PER_LEAF     BLOCKS
4     1
6     1
13     1
15     1
25     1
62     1
63     1
88     1
97     1
122     1
123     3
124     6
125     4
126     2
289     4489
290     3887
291     3129
292     2273
293     1528
294     913
295     442
296     152
297     50
298     7
299     1      In a second step, I have coalesced the index as follows
alter index my_index coalesce;which produces the new figure
Number of blocks with at least 0 to 25% free space     = 0          -------> total bytes = 0
Number of blocks with at least 25-50% free space      = 298        -------> total bytes = 2,328125
Number of Blocks with at least 50 to 75% free space   = 0           -------> Total Bytes = 0
Number of blocks with at least 75 to 100% free space = 0            -------> total bytes = 0
Number of full blocks with no free space = 32375                    -------> total bytes = 252, 9296875
Total blocks ______________________________
32673
Total size MB______________________________
261,384meaning the the coalesce command has made
(a)     298-40 = 258 new blocks with 25-50% of free space
(b)     32375-32361 = 14 new additional blocks which have been made full
(c)     The size of the index increased by 2,176MB (261,384-259,208)
While the number of key per leaf block keeps in the same situation
KEYS_PER_LEAF     BLOCKS
4     2
5     3
9     1
10     2
12     1
13     1
19     1
31     1
37     1
61     1
63     1
73     1
85     1
88     1
122     1
123     4
124     4
125     3
126     1
289     4492
290     3887
291     3125
292     2273
293     1525
294     913
295     441
296     152
297     50
298     7
299     1      Could you please through some light on the difference between the compress and the coalesce on the effect they have made on
(a) the number of keys per leaf blocks within my index
(b) the space and size of my index?
Best regards
Mohamed Houri

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