Where is IMAQ AVI Get Filter Names VI?

I have LabVIEW 6.1 with NI IMAQ 2.6 and NI Vision 6.0.5. I'm trying to create a compressed AVI file from a camera source, and the help file states that there's something called the IMAQ AVI Get Filter Names VI that will return the filters I can use for AVI compression. This VI isn't there in my installation, though.
Am I doing something wrong, or do I need to download something else?

Try looking in the folder C:\Program Files\National Instruments\LabVIEW 6.1\examples\Vision\2. Functions\AVI for the AVI Compressor Comparison.llb example program. This uses the AVI Get Filter Names VI. If this is not available, then you need to upgrade to Vision 7.0 in order to get the functionality to read AVIs into LabVIEW.
Hope this helps-
Julie

Similar Messages

Imaq avi get info do not retrieve any info

Hi everyone,
I have some trouble with the vision VI IMAQ AVI get info,
everything was working well then I don't know what happened but the VI does not retrieve any information on any files, and I get the following error:
Error -1074395993 occurred at IMAQ AVI Open
Possible reason(s):
IMAQ Vision: File I/O error.
I need the framerate, Width, height and number of frame from this VI or else I cannot develop my application.
it only returns 0 on all values but the number of frames which is not correct 4294967295
I am thinking I might have broken the vision library.
Thanks for your help.

Sorry for the multiple message,
I have found why it did not work it was not the imaq get file info but the IMAQ AVI Open VI that does not like the path string given by the open/Create/Replace File VI.
If you have any idea why it would be appreciated.
Thanks.
Attachments:
Open Avi.vi ‏22 KB

Where does InDesign CS4 get the name for the .icml file when using "Add to Assignment"?

I'm trying to figure out a larger problem with InDesign and InCopy files and was curious about where the names comes from. When I add a story to an assignment it doesn't ask me for a name. It seems it is using a name from sometime in the document's past.

Found it...
${bindings.XXXXXX.path}Found it when trying out LOV's... The messageLovInput node uses it to populate it's id.
Regards,
Robert

IMAQ AVI read frame performance

I've been playing around with the read AVI with buffer example in the Developer Community. It reads all the frames of an AVI into memory and then plays them back at the appropriate frame rate. This works ok with very small AVI files but with anything larger it gets slower and slower until it almost stops loading the AVI. At that point it seems to be loading less than 5 frames per second and is killing my cpu. I have plenty of free RAM during this.
https://decibel.ni.com/content/docs/DOC-8479
This is the case with the play AVI example that comes with Labview too (without a buffer) which just loads and plays one frame at a time. Can someone suggest a way to improve the performance of an AVI player in Labview? My ultimate goal is to read an AVI and detect changes in motion of objects by comparing two frames at a time. These AVIs are going to be at least 5 minutes in duration at a frame rate of 30 fps.
I'm using Labview 2009 with the Vision Developer installed.
Attachments:
image_png.png ‏77 KB

VTKim wrote:
Hi,
One thing we could implement is a compression filter that is on the IMAQ AVI Create VI used in conjunction with the IMAQ AVI Get Filter Names VI. Also, what is the RAM available on your computer and what size images are you acquiring and saving to AVI? Thanks!
Kim
Thanks for replying. I'm running labview 2009 on a dual core pentium 2.3 GHz with 4 Gigs of ram. It typically has 2 Gigs free while running the program.
I'm not tryingt write an AVI, I'm trying to read an AVI. The frames are 352 x 240 in size. I've tried several read AVI examples and they all act the same way. They slow down quickly and the hard drive and CPU are really cranking away.

"IMAQ AVI Create" not found under menuitem "AVI" (IMAQ 2.6)

Does anyone know why the Libs. "IMAQ AVI Create ,IMAQ AVI Open ,IMAQ AVI Read Frame ,IMAQ AVI Get Filter Names" are not located in the "AVI" menu ? (IMAQ 2.6)
Thanks Mario

The AVI VIs should be located there, if they are not there was probably a problem with your installation. Launch the installer again by going to Add/Remove Programs and selecting National Instruments Software. From there another menu will open showing most of your NI software. Select on NI-IMAQ 2.6 and select modify. Double check that support for your version of LabVIEW is selected, and proceed with the rest of the install. If you are still having problems, I suggest calling going to www.ni.com/support and getting a hold of NI Tech support.

How to get sequence name in run time.

hi
I have several sub sequence called in the main sequence in TestStand. Those sub sequences have different sequence names, which i wanted to display by string indicator on the Labview Operator Interface. Is there a simple way to show the current calling sub sequence name during run time(run main).
thanks.
Message Edited by Appledoll on 07-12-2007 10:12 AM

Hi,
The easiest way is to use the NameOf() function. In this case where you wish to get the name of the current sequence the syntax NameOf(RunState.Sequence) yields the name. I attach a very simple example also.
Getting the Name of Any TestStand Property Programmatically in TestStand
Hope this helps
Pelle S
District Sales Manager
National Instruments Sweden
Attachments:
Get sequence name.vi ‏15 KB

Error in reciever file adapter , where i am getting file name dynamically

hi all,
error in reciever file adapter , where i am getting file name dynamically, please help me in this isssue , i am trying for a long time
MP: Exception caught with cause com.sap.aii.af.ra.ms.api.RecoverableException: Exception in XML Parser (format problem?):'java.lang.Exception: Message processing failed in XML parser: 'Conversion configuration error: Unknown structure 'ns0:MT_eINVOICE_RECV' found in document', probably configuration error in file adapter (XML parser error)': java.lang.Exception: Exception in XML Parser (format problem?):'java.lang.Exception: Message processing failed in XML parser: 'Conversion configuration error: Unknown structure 'ns0:MT_eINVOICE_RECV' found in document', probably configuration error in file adapter (XML parser error)'

i am getting new error
MP: Exception caught with cause com.sap.aii.af.ra.ms.api.RecoverableException: Channel has not been correctly initialized and cannot process messages
this is my strcuture
and i have changed my structure
<HEADER>
<ADDRESS1/>
<ADDRESS2/>
<ADDRESS3/>
<ADDRESS4/>
</HEADER>
<HEADER_GST>
<TAX1/>
<TAX2/>
<TAX3/>
</HEADER_GST>
<LINE>
<QTY/>
<UOM/>
<UNIT_AMT/>
<CHARGE_TO_DT/>
</LINE>
<FILENAME>
<FILENAME/>
</FILENAME>
i have given the recordset structure as
HEADER,HEADER_GST,LINE,FILE

Running iTunes 11.0.3 64bit Windows 7. The "join Tracks" line has disappeared from the box that opens when you click "options" after inserting a CD. Only 2 lines show up: "Get track names" and "Submit CD Track names". Where did "Join Tracks" go?

Running iTunes 11.0.3 64bit Windows 7. The "join Tracks" line has disappeared from the box that opens when you click "options" after inserting a CD. Only 2 lines show up: "Get track names" and "Submit CD Track names". Where did "Join Tracks" go?

i have the same problem no radio stations at all bit shabby hate technolgy now adays

Where is the command in itunes 11 to "get track names again"?

Actually, I need to get track names more than once AFTER I have ripped the CD.
My situation: I ripped a CD, got the message "multiple matches were found online for this cd" (I need this case, 4) and chose the wrong one so that all the tracks are named untitled.
Later (with no CD) I selected the mp3 track (In the Recently Added playlist) right-clicked and chose "Get Track Names" and chose the 2nd of 4 matches, but this was also wrong. Now, if I right-click and choose "Get Track Names" I can see a very brief cddb lookup in the top center (status?) window, but I don't get the dialog box offering the 4 cddb matches any more.
So now I still don't have the right track names and I can find no way to do another cddb lookup without inserting the original CD. Shouldn't there be a way?
Thanks I need advance,
Steve I need Berkeley

No, the old album list view is not an option in iTunes 11...
You can restore much of the look & feel of the previous version with these shortcuts:
ALT to temporarily display the menu bar
CTRL+B to show or hide the menu bar
CTRL+S to show or hide the sidebar
CTRL+/ to show or hide the status bar (won't hide for me on Win XP)
Click the magnifying glass top right and untick Search Entire Library to restore the old search behaviour
Use View > Hide <Media Kind> in the cloud or Edit > Preferences > Store and untick Show iTunes in the cloud purchases to hide the cloud items. The second method eliminates the cloud status column (and may let iTunes start up more quickly)
If you don't like having different coloured background & text in the Album view use Edit > Preferences > General and untick Use custom colours for open albums, movies, etc.
If you still feel the need to roll back to iTunes 10.7 first download a copy of the 32 bit installer or 64 bit installer as appropriate, uninstall iTunes and supporting software, i.e. Apple Application Support & Apple Mobile Device Support. Reboot. Restore the pre-upgrade version of your library database as per the diagram below, then install iTunes 10.7.
See iTunes Folder Watch for a tool to scan the media folder and catch up with any changes made since the backup file was created.
tt2

How to get mangled names?

I have a need to use one of Sun Studio C++ features, i.e.,  #pragma align.
But I noted that if I use "#pragma align" in a namespace, I must name variables with their mangled names.
See the link below:
http://dsc.sun.com/sunstudio/documentation/ss12u1/mr/READMEs/c++.html#cpragma
I do know there is a tool (c++filt) to demangling names, but I have no idea what kind of tools can help me
to get mangled names.
Regards.

To find the mangled name of a symbol, run "nm -C" on an object file (.o, .so, or a.out) that contains a definition of or reference to the symbol. To reduce the amount of output, grep for the unmangled name. Here is an example:
% cat foo.cc
int bar(int);
int foo(int i) { return bar(i); }
double foo(double d) { return d; }
% CC -c foo.cc
% nm -C foo.o | grep foo
foo.o:
[8]     |        80|      60|FUNC |GLOB |0    |2      |double foo(double)
                                                       [__1cDfoo6Fd_d_]
[1]     |         0|       0|FILE |LOCL |0    |ABS    |foo.cc
[10]    |        16|      44|FUNC |GLOB |0    |2      |int foo(int)
                                                       [__1cDfoo6Fi_i_]
% nm -C foo.o | grep bar
[9]     |         0|       0|FUNC |GLOB |0    |UNDEF |int bar(int)
                                                       [__1cDbar6Fi_i_]The -C option fo nm shows both the mangled and demangled names of symbols. This example has 2 functions called foo. You can tell which one you want by matching the demangled name to the mangled name.
There is no "name mangler" that takes a symbol and mangles it, because the mangling in general depends on the context where the symbol is declared. You need almost all of a C++ compiler front end to create the mangled name.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "";
Also I have used,
             String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
          String ldapURL = "ldap://mydc.antipodes.com:389";
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
code I have used:
//specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "";
Also I have used,
             String searchFilter = "(&(objectClass=user)(CN=Username))";
               //Specify the Base for the search
               String searchBase = "ou=ibmgroups,o=ibm.com";
But in both cases I am getting value for Total groups as 0.
Code Reference:
* memberof.java
* December 2004
* Sample JNDI application to determine what groups a user belongs to
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class memberof     {
     public static void main (String[] args)     {
          Hashtable env = new Hashtable();
          String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
          String adminPassword = "XXXXXXX";
          String ldapURL = "ldap://mydc.antipodes.com:389";
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          //set security credentials, note using simple cleartext authentication
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          //connect to my domain controller
          env.put(Context.PROVIDER_URL,ldapURL);
          try {
               //Create the initial directory context
               LdapContext ctx = new InitialLdapContext(env,null);
               //Create the search controls
               SearchControls searchCtls = new SearchControls();
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
               //Specify the Base for the search
               String searchBase = "DC=antipodes,DC=com";
               //initialize counter to total the group members
               int totalResults = 0;
               //Specify the attributes to return
               String returnedAtts[]={"memberOf"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
               //Loop through the search results
               while (answer.hasMoreElements()) {
                    SearchResult sr = (SearchResult)answer.next();
                    System.out.println(">>>" + sr.getName());
                    //Print out the groups
                    Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                              for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                   Attribute attr = (Attribute)ae.next();
                                   System.out.println("Attribute: " + attr.getID());
                                   for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                        System.out.println(" " + totalResults + ". " + e.next());
                         catch (NamingException e)     {
                              System.err.println("Problem listing membership: " + e);
               System.out.println("Total groups: " + totalResults);
               ctx.close();
          catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
Any help will be highly appreciated.

How to get column names for a specific view in the scheme?

how to get column names for a specific view in the scheme?
TIA
Don't have DD on the wall anymore....

or this?
SQL> select text from ALL_VIEWS
2 where VIEW_NAME
3 ='EMP_VIEW';
TEXT
SELECT empno,ename FROM EMP
WHERE empno=10

Error -1074395975 occurred at IMAQ AVI Read Frame DirectX has timed out readin

When i run the "Read AVI Example" on every kind of AVI file, I get the error:
Error -1074395975 occurred at IMAQ AVI Read Frame DirectX has timed out reading or writing the AVI file. When closing an AVI file, try adding an additional delay. When reading an AVI file, try reducing CPU and disk load.

The forums search gives two threads talking about this error:
http://forums.ni.com/ni/board/message?board.id=170&message.id=392042&requireLogin=False
http://forums.ni.com/ni/board/message?board.id=170&requireLogin=False&thread.id=195832
Did you allready had a look at them?

B2B 11g: Getting File Name in inbound integration and passing it to SOA

Hi,
I am Reading a EDI x12 file in inbound B2B .I am checking the 'preserve File Name' check Box at Listening channel properties.....Then Integrating B2B to soa using AQ Adapter.But I couldn't find any property where I can pass the file name which I read through B2b to Composite. I need the file name because I am inserting all the records in Database and client wants to see which record in DB has been inserted from which file.
Any pointers would be helpful.

Hello,
Try to use the b2b.fileName property. Although it probably is not shown on the list you should be able to access it.
Also, please check the patch 18021286 which has many improvements and allows for two cases that can be useful for you:
- Get information on back-end about which channel and agreement was used to deliver
- Using callout Ret values which allow for specific properties to be set on callouts and passed all the way until the back-end application.
Hope this helps.
Best Regards
Tiago Teixeira

How to get the name of the attachment in Sender Mail Adaper?

hi mates,
I've scenario a where in I need to pick up a mail with an attachment and change its extension and send it to target system using file adapter.
I'm able to pick up the mail with attachment using sender mail adapter but not able to get the name of the attachment so that I can use it in mapping or on the adapter configuration. How do I read the name of the attachment and manupulate it?
I looked at the thread sender mail adapter - attachment name But the solution is not described. I think Stefan is talking about the SP!2 for PI 7.0. I'm on XI 3.0 what is the equivalent SP for that, SP20? Stefan, can you please throw me more light on it?
I appreciate your valuable inputs
thx in adv
praveen

Thanks Aamir.
Earlier I replied to that thread asking for more details...but did not see the response...
anyways, thanks for your quick help..
but I wonder abt the PI SP12/ XI SP20 pre-requisite. We can have adapter modules on SPs lower than PI SP12/XI SP20 as well, can we not?
thanks
praveen

Where is IMAQ AVI Get Filter Names VI?

Similar Messages

Maybe you are looking for