Which formula(a) do I use to select any value that is than 0 but 7 out of a range of cells and sum them.

Question

I'm working on a sheet that I want to use to select a specific part based on values created by the sum of values in other cells. I am down to the point where I need to select a low range of numbers
If the sum of cell D5 equals any sum between 1-15 will equal = part 1
If the sum of cell D5 equals any sum between 16-23 will equal = part 2 ,
If the sum of cell D5 equal antsy sum between 24-32 will equal part 3.
I'm at a loss how to make one formula or combination of formulas do this.
Thanks in advance.
Big Al Hur

Answer 1

Hi Al,
The confusion arises from your having asked two separate questions, one in the subject line, the other in the body of your initial post.
1.
How do I sum only the values greater than zero and less than 7 in a range of cells?
This formula supplied by SGIII does what you have asked there:
=SUMIFS(A,A,">0",A,"<7")
The syntax is:
SUMIFS(sum-values, test-values, condition, test-values, condition…)
sum-values ( A ) is the range of cells containing the values to be summed (all the body cells in column A)
test-values and condition come in pairs. the first names the range of values to be tested, the second names the condition that must be met.
In this formula, the test-values in each pair are the same as the sum values.
condition ( ">0" ) is the first condition that must be met by these values. (greater than zero)
the second condition ( "<7" ) is the second condition that must be met (less than seven)
To be included in the sum, a value in the list must meet both conditions: It must be greater than 0 AND less than 7. IN SG's example, there are two values that meet both conditions, 2 in A2 and 6 in A5, that meet both conditions. Their sum, 8, is shown in A10, whch is the cell containing the formula.
2
If the sum of cell D5 equals any sum between 1-15 will equal = part 1
If the sum of cell D5 equals any sum between 16-23 will equal = part 2 ,
If the sum of cell D5 equals any sum between 24-32 will equal part 3.
This formula supplied by SGIII, and the Lookup table that goes with it, does what you have asked here.
=VLOOKUP(D5,Lookup::A:B,2,close-match)
Close-match means 'the largest value that is less than or equal to' the search-value.
The search-value is the value in D5
VLOOKUP searches in the leftmost column (A) of the lookup table (columns A and B of the table named Lookup).
With "close-match" specified:
any value that is equal to or greater than 0 and less than 16 will be matched by the 0 in A2. VLOOKUP will return the value in the same row of column 2 (B) of the table: "Part 1"
any value that is equal to or greater than 16 and less than 24 will be matched by the 16 in A3. VLOOKUP will return the value in the same row of column 2 (B) of the table: "Part 2"
any value that is equal to or greater than 24 will be matched by the 24 in A4. VLOOKUP will return the value in the same row of column 2 (B) of the table: "Part 3"
While this is not an exact match with your description above, it will perform exactly as you requested IF the value in D5 is never less than 1 and never greater than 32.
If the possible range is greater than that, I would suggest the changes shown below to the formula and to the lookup table. The column containing numbers is column D, and represents values in D5. Column E shows the result for each value using the given formula and lookup table (LU A). Column F shows results for the same values using the revised formula and lookup tble (LU B):
Original                              =VLOOKUP(D,LU A :: A:B,2,1)
Revised formula: =IFERROR(VLOOKUP(D,LU B :: A:B,2,1),"N//A")
In the revision, IFERROR takes care of the negative values in D2 and D3. The zero value in D4 and in the last row of column D and the overflow values (greater than 32) are handled by the revisions to the lookup table.
Regards,
Barry