XSLT Problem in Sum value

Hello,
How can I get the sum() of the XML in some two fields?
<orders>
<order>
<item>Book</item>
<qty>10</qty>
<price>12.5</price>
</order>
<order>
<item>CD</item>
<qty>3</qty>
<price>6.99</price>
</order>
</orders>
How can I get the subtotal ????
-- subtotal = sum(qty*price)
Eric

here what you're looking for!
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:variable name="total" />
<xsl:template match="orders">
<html>
<Head>
<title>main file</title>
</Head>
<body>
<xsl:apply-templates select="order"/>
totale:<xsl:value-of select="round(sum(child::*/child::qty)*sum(child::*/child::price))"/>
</body>
</html>
</xsl:template>
<xsl:template match="order">
<xsl:variable name="quantite" select="./qty"/>
<xsl:variable name="price" select="./price"/>
subtotal<xsl:value-of select="position()"/>=<xsl:value-of select="$quantite*$price"/>
</xsl:template>
</xsl:stylesheet>

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Hello,
I have some problem using "disable-output-escaping" attribute of xsl:value-of() function.
I have a table SONGS with two columns XML and XSL filled with :
<song>
<title>Isn't she lovely?</title>
</song>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" encoding="UTF-8"></xsl:output>
<xsl:template match="//song">
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      <xsl:value-of select="title" disable-output-escaping="yes"></xsl:value-of>
    </out>
</xsl:template>
</xsl:stylesheet>The query to transform XML with XSL :
SELECT XMLTRANSFORM (xml, xsl) FROM songs;I get this XML :
<out>Isn't she lovely?</out>but I want that (without the '&' special character) :
<out>Isn't she lovely?</out>How can I procees to succeed ?
Thanks,
Dominique

What DB version?
The following SQL
select xmltransform(XMLTYPE('<song>
<title>Isn''t she lovely?</title>
</song>'), XMLTYPE('<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" encoding="UTF-8"></xsl:output>
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</xsl:template>
</xsl:stylesheet>'))
from dual;produces this on 11.1.0.6
<?xml version="1.0" encoding="UTF-8"?>
<out>Isn't she lovely?</out>and this on 10.2.0.4
<out>Isn't she lovely?</out>I found a couple of previous discussions regarding this at
{thread:id=679397}
{thread:id=879301}
The last discussion provides a workaround if you need it.

Error in printing sum value of DME file in Automatic Payment Run

Hi All,
We are in the process of upgrading from R/3-4.0B to ECC6.0.
In Automatic Payment run in transaction F110, when the spool is generated, the sum values is displaying in correctly. It is displaying and printing as actual value/100 for example if total of all the line items is 1000000, the sum value displaying as 10000 and in words also prints as ten thousands.
Kindly let us know how to fix the issue, if any one has come across with similar issue.
Thanx & Regards
Ashok

Hi VVR,
I got the following errors:
Err     Message text
003    Item is blocked for payemnt
007    Error in creating the payment doc, read job log.....
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Sum values in last row for date format "hh24:mi"

Hi,
I have a big problem creating a sum row with date data.
I created a sql view where the result looks like that:
SELECT category_name,
user_name,
b_mmyyyy,
b_1, ..., b_31
FROM view_category_user_booking
category_name, user_name, b_1, ..., b_31
category1, user1, 122008, 01:00, ..., 03:30
category2, user1, 122008, 02:00, ..., 01:00
category3, user1, 122008, 00:00, ..., 00:15My goal is to integrate a sum row at the end for the columns b_1 ... b_31
category_name, user_name, b_1, ..., b_31
category1, user1, 122008, 01:00, ..., 03:30
category2, user1, 122008, 02:00, ..., 01:00
category3, user1, 122008, 00:00, ..., 00:15
Sum, user1, 122008, 03:00, ..., 04:45I tried it like that:
select decode(grouping(category_name),1,'Summe',category_name),
sum(to_number(replace(b_1,':',','))) as b_1,
sum(to_number(replace(b_31,':',','))) as b_31
from category_user_booking
where user_name = 'user1'
and b_mmyyyy = '122008'
group by rollup(category_name)But the result isn't really successful
category_name, b_1, b_31
category1, 1, 3,3
category2, 2, 1
category3, 0, 0,15
Sum, 3, 4,45Is there somebody with an idea?
Thanks ahead,
Tobias

Hi Avinash,
the problem is not the grouping it is the date format.
Instead of a value like 5,4 > I want 05:40 or 1,75 > I want 02:15 in the sum value.
In my table all time values are saved in the format hh24:mi.
I don't know how to get that via a sql statement.
Output I want:
category_name, user_name, b_1, ..., b_31
category1, user1, 122008, 01:00, ..., 03:30
category2, user1, 122008, 02:00, ..., 01:00
category3, user1, 122008, 00:00, ..., 00:15
Sum, user1, 122008, 03:00, ..., 04:45Regards,
Tobias

How to sum value from a day to next day

First, I provided the CREATE and INSERT sql statements for testing:
CREATE TABLE TBL_CALC
    "YEAR" VARCHAR2(4),
    "MONTH" VARCHAR2(2),
    "DAY"   VARCHAR2(2),
    "HOUR" VARCHAR2(2),
    "VALUE" VARCHAR2(20)
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','20','32')
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','21','33');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','22','53');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','23','28');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','0','37');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','1','35');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','2','39');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','3','57');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','13','42');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','14','12');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','21','32');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','22','52');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','23','29');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','0','27');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','1','45');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','2','69');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','3','68');I have this sql to get the period of time of a day:
         select year,month,day,hr,val,
                 sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by year,month,day) as new_value
                      from(
                             select year,month,day,to_number(hour) hr,to_number(value) val from tbl_calc
         order by year,month,day,hrHere's the output:
YEAR MONTH DAY HR VAL NEW_VALUE
2000 1     1   20 32       146
2000 1     1   21 33       146
2000 1     1   22 53       146
2000 1     1   23 28       146
2000 1     2    0 37       168
2000 1     2    1 35       168
2000 1     2    2 39       168
2000 1     2    3 57       168
2000 1     2   13 42       168
2000 1     2   14 12       168
2000 1     31 21 32       113
2000 1     31 22 52       113
2000 1     31 23 29       113
2000 2     1    0 27       209
2000 2     1    1 45       209
2000 2     1    2 69       209
2000 2     1    3 68       209
17 rows selected The above sql get the sum of time period which in 20-23 and 0-3 in every day.
The values are recorded by each hour. (sometimes there are missed hours)
My problem is how to get the sum of time period over each day?
For example, I need to get the sum of value of a day night time from 20-23 and the next day morning 0-3, to become a sum value in this period.
Let say, the sum from 1st Jan night time to 2nd Jan morning should be combined into 1 value (146+168)=314.
In addition, there is a tricky point is that from every month last day (31th Jan night time to 1st Feb morning time) are also need to be combined into 1 value.
And it appears the new problem is that how about if the last day is in a non-regular day (not 30,31,28,29), just say maybe March consist only 15 period records only and the last day is 19th March.
The expected output:
YEAR MONTH DAY HR VAL NEW_VALUE
2000 1     1   20 32       314
2000 1     1   21 33       314
2000 1     1   22 53       314
2000 1     1   23 28       314
2000 1     2    0 37       314
2000 1     2    1 35       314
2000 1     2    2 39       314
2000 1     2    3 57       314
2000 1     2   13 42       314
2000 1     2   14 12       314
2000 1     31 21 32       322
2000 1     31 22 52       322
2000 1     31 23 29       322
2000 2     1    0 27       322
2000 2     1    1 45       322
2000 2     1    2 69       322
2000 2     1    3 68       322
17 rows selected I think its quite complicated case, please ask me for more if you need to clarify for something.
Thanks so much!! :)
Edited by: 920575 on 2012/7/31 上午 1:09

Are you looking for something like this (partially tested)...
SQL> ed
Wrote file afiedt.buf
1 select year
2        ,month
3        ,day
4        ,hr
5        ,val
6        ,sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by year,month,day) as new_value
7        ,sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by trunc(dt-(4/24),'DD')) as day_value
8 from(
9       select year,month,day,to_number(hour) hr,to_number(value) val
10             ,to_date(year||lpad(month,2,'0')||lpad(day,2,'0')||lpad(hour,2,'0')||'0000','YYYYMMDDHH24MISS') as dt
11       from tbl_calc
12      )
13* order by year,month,day,hr
SQL> /
YEAR MO DA         HR        VAL NEW_VALUE DAY_VALUE
2000 1 1          20         32        146        314
2000 1 1          21         33        146        314
2000 1 1          22         53        146        314
2000 1 1          23         28        146        314
2000 1 2           0         37        168        314
2000 1 2           1         35        168        314
2000 1 2           2         39        168        314
2000 1 2           3         57        168        314
2000 1 2          13         42        168          0
2000 1 2          14         12        168          0
2000 1 31         21         32        113        322
2000 1 31         22         52        113        322
2000 1 31         23         29        113        322
2000 2 1           0         27        209        322
2000 2 1           1         45        209        322
2000 2 1           2         69        209        322
2000 2 1           3         68        209        322
17 rows selected.This turns the values into a proper DATE datatype and then offsets that back by 4 hours to bring the 0-3 hours into the previous day, and then partitions the sum based on that day.

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sorry for the late updation.
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below is the original request.
Hi,
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hi TimoHahn,
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<part name="String_2" type="xsd:string"/>
<part name="String_3" type="xsd:string"/>
<part name="String_4" type="xsd:string"/>
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<area title1="special" link1="link2.php"/>
</slideshow>
here is the code on my scene:
var link1:Array = new Array();
var LINK:String;
var url:String;
var whoOn:Number;
whoOn=0;
var x:XML = new XML();
x.ignoreWhite = true;
x.onLoad = function(success) {
var photos:Array = this.firstChild.childNodes;
for (i=0; i<photos.length; i++) {
_root.link1.push(photos[i].attributes.link1);
url=link1[whoOn];
filmstrip.theUrl=url;//<<--HERE
x.load("category.xml");
var cbListener:Object = new Object();
cbListener.change = function(event_obj:Object) {
trace(select.selectedItem.label);
if (select.selectedItem.label == "Last updated") {
whoOn=0;
} else if (select.selectedItem.label == "Special") {
whoOn=1;
url=link1[whoOn];
filmstrip.theUrl=url; //<<-----HERE
select.addEventListener("change",cbListener);
here is the code inside the movie clip "filmstrip"
var T:XML = new XML();
T.ignoreWhite = true;
T.onLoad = function(xml) {
etc etc etc }
T.load(theUrl);    //<<---HERE it still undefined

YESSSS . Thanks you very much Kglad it wotk i put all in a function inside the filmstrip function Tload(theUrl){etc ect}and in the root i call it like this filmstrip.Tload(theUrl);   and it works
code in the root var link1:Array = new Array();
var LINK:String;
var url:String;
var whoOn:Number;
whoOn=0;
var x:XML = new XML();
x.ignoreWhite = true;
x.onLoad = function(success) {
var photos:Array = this.firstChild.childNodes;
for (i=0; i<photos.length; i++) {
_root.link1.push(photos[i].attributes.link1);
url=link1[whoOn];
theUrl=url;
filmstrip.Tload(theUrl);//<<--HERE
x.load("category.xml");
var cbListener:Object = new Object();
cbListener.change = function(event_obj:Object) {
trace(select.selectedItem.label);
if (select.selectedItem.label == "Last updated") {
whoOn=0;
} else if (select.selectedItem.label == "Special") {
whoOn=1;
url=link1[whoOn];
theUrl=url;
filmstrip.Tload(theUrl);//<<-----HERE
select.addEventListener("change",cbListener);

Problem in the values in invoice

HI All,
i have a problem in invoice printing, If i create a new billing document and generate the output via VF02, the line item values and tax values in the amount column not getting printed properly. if i take the printout for the same document again everything is comng perfectly. I have debugged the subroutine program which i created is working fine in the debug mode. when i generate any invoice for the first time, i have a problem in the values.
Please help me to find this..
Thanks and Regards,
Ahamed Anish S.

this was solved by myself..

Real simple xslt problem/question

Hi, i have a real simple xslt problem but i just cant figure out how to do it by looking at various examples on the net. i have a xml document and in it are some elements with a "result" tag name. i want to use xslt to reproduce exactly the same xml document except with an attribute called "id" added to those elements with a "result" tag name. i'm sure that theres a simple solution to it but i just cant figure it out. any helps greatly appreciated, thanks

Start with the XSLT identity transform (I don't have it handy and it's fairly long, but you should be able to google it up). Add this:<xsl:template match="result">
<result id="">
<xsl:apply-templates>
</result>
</xsl:template>

SUM VALUES

Hi
I need to sum values for different CD_INDICATOR, same CD_CUSTOMER , same NM_CYCLE , same CD_STRUT, same PROFILE
CD_STRUT                    NUMBER(6)
NM_CYCLE                    NUMBER(6)
CD_CUSTOMER                 NUMBER(10)
CD_PROFILE                  NUMBER(2)
CD_INDICATOR                NUMBER(6)
VL_INDICATOR                NUMBER(15,2)
LAST_DATE                   DATE
SELECT CD_STRUT ,   NM_CYCLE ,
    CD_CUSTOMER , CD_PROFILE , CD_INDICATOR ,
   VL_INDICADOR VL_INDICATOR , DT_ULTIMA_ATUALIZACAO LAST_DATE
   FROM MYTABLE PPC
   WHERE PPC.CD_TYPE_STRUCT = 5   ---IS CONSTANT = 5
    AND PPC.CD_STRUT = 4
    AND PPC.NM_CYCLE = 200810
    AND PPC.CD_CUSTOMER = 574970
    AND PPC.CD_PROFILE = 1
    AND PPC.CD_INDICATOR IN (4,2);     CD_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR LAST_DATE
       4   200810      574970          1            2              14.00 6/30/2008 8
       4   200810      574970          1            4              1.00 6/30/2008 8     I must to sum VL_INDICATOR , with rule
     When CD_INDICATOR = 4 AND VL_INDICATOR =1.00 I must return sum
     of VL_INDICATOR 2 ( In case above =14) with 1, but if when
     CD_INDICATOR = 4 AND VL_INDICATOR != 1 I must return only value of of VL_INDICATOR 2 ( In case above = 14)
     I must return new CD_INDICATOR (5) as with below
CD_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR LAST_DATE
       4   200810      574970          1          5              15.00 6/30/2008 8     if the values of CD_INDICATOR (2,4)
CD_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR LAST_DATE
       4   200810      574970          1            2              12.00 6/30/2008 8
       4   200810      574970          1            4              4.00 6/30/2008 8RETURN ME
CD_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR LAST_DATE
       4   200810      574970          1          5              12.00 6/30/2008 8

Hi
I must to sum values OF CD_INDICATOR 309 and 4 ,
When value of CD_INDICATOR 4 is equal 1 (One) then I sum 1 else I sum zero
But if record of CD_INDICATOR 4 not exists I must to sum 0
In example below the sum equal 10 because value of CD_INDICATOR 4 is equal 2
CD_STRUT CD_TYPE_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR
       2             5   200810     3320080          1          309             10.00
       2             5   200810     3320080          1            4              2.00 In example below the sum equal 15
CD_STRUT CD_TYPE_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR
       2             5   200810     3320080          1          309             14.00
       2             5   200810     3320080          1            4              1.00 In example below the sum is 10, because no exist cd_indicator 4
CD_STRUT CD_TYPE_STRUT NM_CYCLE CD_CUSTOMER CD_PROFILE CD_INDICATOR      VL_INDICATOR
       2             5   200810     3320080          1          309             10.00
   SELECT c.CD_STRUT,
          cCD_TYPE_STRUT,
          cNM_CYCLE ,
          cCD_CUSTOMER,
          cCD_PROFILE ,
          C.CD_INDICATOR,
          c.VL_INDICATOR
     from T_CUSOTMER a
     INNER JOIN MYTABLE c ON (    a.cd_type_strut = c.cd_type_strut
        AND a.cd_estru = c.cd_estrut
        AND a.CUSTOMER = c.cd_CUSOTMER
        AND c.nm_cyicle = 200810
        AND c.cd_profile = 1
        AND c.cd_indicator = 309
       and c.cd_customer = 3320080)I Want to a OUTER LEFT JOIN with MYTABLE for to get CD_INDICATOR =4 , but I did know how can I do it
Message was edited by:
muttleychess

XSLT Problem in Sum value

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