Zip file upload to content area

Has anyone tried zipping up a huge folder on the filesystem, say around a 100 files and uploaded the zip to a content ara folder? I could successfully upload the zip file but and then used the unzip link next to the uploaded content. It unzips as well, but when I click on the folder to view the unzipped files, before it could show me the 100 odd files, the server times out. I believe it is due to the number of files in a single folder. If I do the same thing with a hierarchy of folders and sub-folders containing only 10s' of files it works and displays the page to me with all links working.
I hope you must have tried this, and pls. help me and provide me an alternative.

check out this OSS Note No. 925327
<a href="http://service.sap.com/~form/handler?_APP=01100107900000000342&_EVENT=REDIR&_NNUM=925327">HTTP error: 411 Length Required in upload to content server</a>
Regards
Raja

Similar Messages

How to zip files in a content area

Hi!!
We have a lot of documents in a content area, and every day the number of documents is going up. The question is, if we can zip these documents or something similar.

If you're asking about compressing the files in the repository, or adding a bunch of items to a zip file, neither of these features are currently available.
You would have to download the files, add them to a zip on the desktop, and then upload the new zip file.
Regards,
Jerry
PortalPM

Automatic upload of content area items from the O/S

I wish to automate the upload of content area items into the portal. Can this be done via the PDK or otherwise?
I have a number of PDF and HTML reports that get generated and placed into a physical directory on the server. I want all these files from a specific directory to be uploaded as items into the portal automatically so that users can view the reports with appropriate security. The reports can be modified so that when run they insert a record into a custom table to store their path and file names. This can be used by a custom procedure to point to the files at the point of upload.
However, can this upload actually be done?
Any ideas on how to do this would be useful.
Regards,
John

Physical path on the database server.
Using the api to upload is easy as long as you provide the content-area id, folder-id, display-name, item-type (PORTAL30.WWSBR_API.ITEM_TYPE_FILE), content-area type id (PORTAL30.WWSBR_API.SHARED_OBJECTS), folder-region-id (whatever it is for Regular Items, you'll find it in wwsbr_all_folder_regions) and the physical file-name.

File handling in Content areas

Where is it determined what happens when you select a file in a content area folder? If I want to only be able to download the file and not try to read it, is there a setting that may be changed to allow this?
Thanks,
Chris

Chris,
We just do whatever the browser is configured to do with the file type. There are no special settings available in Portal.
Regards,
Jerry
null

Problem upload too large file in a Content Area ORA-1401

Hi All
I have a customer who is trying to upload a file with a too large name in a content area.
If the filename is 80 characters, it works fine.
But if the filename is upper or 80 characters the following error ocurred:
ORA-01401: inserted value too large for column
DAD name: portal30
PROCEDURE : PORTAL30.wwv_add_wizard.edititem
URL : http://sbastida-us:80/pls/portal30/PORTAL30.wwv_add_wizard.edititem
I checked the table: WWV_DOCUMENT and it have a column name: FILENAME is defined like VARCHAR2(350).
If i run a query on this table, the filename column stores the filename of the file uploaded.
Is this a new bug? may i fill this bug?
Do you have any idea about this issue?
Thanks in advance,
Catalina

Catalina,
The following restrictions apply to the names of documents that you are uploading into the repository:
Filenames must be 80 characters or less.
Filenames must not include any of these characters: \ / : * ? < > | " % # +
Filenames can include spaces and any of these characters: ! @ ~ & . $ ^ ( ) - _ ` ' [ ] { } ; =
Regards,
Jerry
null

Limited File size uploaded to Content Area

Is it possible to limit the file uploaded as an item in the content area/folder ?

Its a benign error. It has to do with flexible parameter passing. You can ignore it.
Recently I have been receiving the following error in my apache error log file...It tells me to refer to the doc for ways around this issue...I am unable to locate any doc on this issue. I have looked in the iAS plsql doc as well. Now this comes and goes as well. For the most part clients can upload files successfully, but once and a while this error occurs. The error causes the 404 error in the browser
[Tue Oct 29 16:41:25 2002] [warn] mod_plsql: /pls/portal30/PORTAL30.wwv_add_wizard.edititem had to be described for execution. Refer to the PL/SQL GateWay documentation on how to avoid this
mod_plsql: /pls/portal30/PORTAL30.wwv_edit_tab.edititem had to be described for execution. Refer to the
PL/SQL GateWay documentation on how to avoid this
Any help would be greatly appreciated...
I am on 30980 portal at the moment...we are upgrading in the next couple weeks. Is this a known bug in a specific version??

ZIP File has damaged contents - Multiple file download

Hi,
I am using ZIP API in Web Dynpro JAVA for multiple file download scenario.
Issue:--->
Some files are not opening correctly after unzipping the ZIP file.
Example-1: some PDF files gives out message that " "
Example-2: Also, a JPG file shows only upper half of the image.
So in all, the content of generated ZIP file are damaged.
Any idea why this is happening?
Thanks & regards,
Amey

And this is the code I'm using:-
Unzipped PDF files give this error --> There was an error opening this document. The file is damaged and could not be repaired
for(int i = 0; i < l_int_NodeSize; i++){
     g_SearchOutputEle = g_SearchOutputNode.getCtx_vn_SearchOutputElementAt(i);
     java.net.URL url = new URL(g_SearchOutputEle.getFileUrl());
     java.net.URLConnection urlConnection = url.openConnection();
     java.io.InputStream inputStream = url.openStream();
     int arraySize = urlConnection.getContentLength();
     byte[] byteArray = new byte[arraySize];
     DataInputStream dis = new DataInputStream(inputStream);
     dis.read(byteArray);
     ZipEntry zipEntry = new ZipEntry("Name-"+i);
     zipEntry.setSize(byteArray.length);
     zos.putNextEntry(zipEntry);
     zos.write(byteArray);
     zos.closeEntry();
zos.close();
byte[] byteOutArray = baos.toByteArray();
IWDResource resource = WDResourceFactory.createResource(byteOutArray, "Downloads.zip",WDWebResourceType.UNKNOWN);
String urlString = resource.getUrl(WDFileDownloadBehaviour.ALLOW_SAVE.ordinal());
IWDWindow win_MultiFileWindow = wdComponentAPI.getWindowManager().createNonModalExternalWindow(urlString);
win_MultiFileWindow.setWindowSize(0,0);
win_MultiFileWindow.show();
Edited by: Amey Mogare on Mar 30, 2010 7:49 AM

Docx file upload to content repository on MS Sharepoint

I have installed Primavera P6 EPPM version 8.2 in use with content repository on MS Sharepoint 2010 SP1.
When I an trying to upload files with extensions "docx", "xlsx" ... system message "uknown error, please contact
your System Administrator" pop ups.
Plus to it, all uploaded documents dissapears from list in "Projects" menu "Documents" . In "Dashbords" portlet
I can see all earlier uploaded documents.
May be somebody had similar problems and found solution for it? Advice would be very valuable.
Juozas

I'm not sure about that code for the file upload part. You should really go find the File upload stuff from Jakarta Commons or UploadBean from whoever wrote it. That will handle the file upload. The database part, there are tutorials in Java's site ... try searching for "store image database"

Images present in datagridview not exporting to file only text contents are generating into PDF file..

Hi Everyone,
I have created simple Desktop app in that I trying to generate PDF file from Datagridview...when I click on ExportPDf button Pdf file is generation successfully but the issue is in that pdf whatever the images has present in datagridview that images
are not generation into PDF only the text contents are Present in PDF file.
Does any one can tell me how to generate the PDF file along with images.
Here is my code:
private void btnexportPDF_Click(object sender, EventArgs e)
int ApplicationNameSize = 15;
int datesize = 12;
Document document = null;
try
SaveFileDialog savefiledg = new SaveFileDialog();
savefiledg.Filter = "All Files | *.* ";
if (savefiledg.ShowDialog() == DialogResult.OK)
string path = savefiledg.FileName;
document = new Document(PageSize.A4, 3, 3, 10, 5);
PdfWriter writer = PdfWriter.GetInstance(document, new FileStream(path + ".pdf", FileMode.Create));
document.Open();
// Creates a phrase to hold the application name at the left hand side of the header.
Phrase phApplicationName = new Phrase("Sri Lakshmi Finance,Hosur-560068", FontFactory.GetFont("Arial", ApplicationNameSize, iTextSharp.text.Font.NORMAL));
// Creates a phrase to show the current date at the right hand side of the header.
Phrase phDate = new Phrase(DateTime.Now.ToLongDateString(), FontFactory.GetFont("Arial", datesize, iTextSharp.text.Font.NORMAL));
document.Add(phApplicationName);
document.Add(phDate);
iTextSharp.text.Image img = iTextSharp.text.Image.GetInstance("D:\\logo.JPG");
document.Add(img);
iTextSharp.text.Font font5= iTextSharp.text.FontFactory.GetFont(FontFactory.TIMES_ROMAN, 5);
iTextSharp.text.Font font6 = iTextSharp.text.FontFactory.GetFont(FontFactory.HELVETICA_BOLD, 6);
//float[] columnDefinitionSize = { 2.5f, 7.0f,6.6f, 8.6f, 6.6f, 5.0f, 4.5f, 7.0f, 6.3f, 7.0f, 3.5f, 6.0f, };
PdfPTable table = null;
table = new PdfPTable(dataGridView1.Columns.Count);
table.WidthPercentage = 100;
PdfPCell cell = null;
foreach (DataGridViewColumn c in dataGridView1.Columns)
cell = new PdfPCell(new Phrase(new Chunk(c.HeaderText,font6)));
cell.HorizontalAlignment = PdfPCell.ALIGN_CENTER;
cell.VerticalAlignment = PdfPCell.ALIGN_CENTER;
cell.BackgroundColor = new iTextSharp.text.BaseColor(240, 240, 240);
table.AddCell(cell);
if (dataGridView1.Rows.Count > 0)
for (int i = 0; i < dataGridView1.Rows.Count; i++)
PdfPCell[] objcell = new PdfPCell[dataGridView1.Columns.Count];
for (int j = 0; j < dataGridView1.Columns.Count - 0; j++)
cell = new PdfPCell(new Phrase(dataGridView1.Rows[i].Cells[j].Value.ToString(), font5));
cell.HorizontalAlignment = PdfPCell.ALIGN_LEFT;
cell.VerticalAlignment = PdfPCell.ALIGN_LEFT;
cell.Padding = PdfPCell.ALIGN_LEFT;
objcell[j] = cell;
PdfPRow newrow = new PdfPRow(objcell);
table.Rows.Add(newrow);
document.Add(table);
MessageBox.Show("PDF Generated Successfully");
document.Close();
else
//Error
catch (FileLoadException fle)
MessageBox.Show(fle.Message);
MessageBox.Show("Error in PDF Generation", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
Runtime Gridview content:
Generated PDF File:
Thanks & Regards RAJENDRAN M

Hi Everyone,
I have created simple Desktop app in that I trying to generate PDF file from Datagridview...when I click on ExportPDf button Pdf file is generation successfully but the issue is in that pdf whatever the images has present in datagridview that images
are not generation into PDF only the text contents are Present in PDF file.
Does any one can tell me how to generate the PDF file along with images.
Here is my code:
private void btnexportPDF_Click(object sender, EventArgs e)
int ApplicationNameSize = 15;
int datesize = 12;
Document document = null;
try
SaveFileDialog savefiledg = new SaveFileDialog();
savefiledg.Filter = "All Files | *.* ";
if (savefiledg.ShowDialog() == DialogResult.OK)
string path = savefiledg.FileName;
document = new Document(PageSize.A4, 3, 3, 10, 5);
PdfWriter writer = PdfWriter.GetInstance(document, new FileStream(path + ".pdf", FileMode.Create));
document.Open();
// Creates a phrase to hold the application name at the left hand side of the header.
Phrase phApplicationName = new Phrase("Sri Lakshmi Finance,Hosur-560068", FontFactory.GetFont("Arial", ApplicationNameSize, iTextSharp.text.Font.NORMAL));
// Creates a phrase to show the current date at the right hand side of the header.
Phrase phDate = new Phrase(DateTime.Now.ToLongDateString(), FontFactory.GetFont("Arial", datesize, iTextSharp.text.Font.NORMAL));
document.Add(phApplicationName);
document.Add(phDate);
iTextSharp.text.Image img = iTextSharp.text.Image.GetInstance("D:\\logo.JPG");
document.Add(img);
iTextSharp.text.Font font5= iTextSharp.text.FontFactory.GetFont(FontFactory.TIMES_ROMAN, 5);
iTextSharp.text.Font font6 = iTextSharp.text.FontFactory.GetFont(FontFactory.HELVETICA_BOLD, 6);
//float[] columnDefinitionSize = { 2.5f, 7.0f,6.6f, 8.6f, 6.6f, 5.0f, 4.5f, 7.0f, 6.3f, 7.0f, 3.5f, 6.0f, };
PdfPTable table = null;
table = new PdfPTable(dataGridView1.Columns.Count);
table.WidthPercentage = 100;
PdfPCell cell = null;
foreach (DataGridViewColumn c in dataGridView1.Columns)
cell = new PdfPCell(new Phrase(new Chunk(c.HeaderText,font6)));
cell.HorizontalAlignment = PdfPCell.ALIGN_CENTER;
cell.VerticalAlignment = PdfPCell.ALIGN_CENTER;
cell.BackgroundColor = new iTextSharp.text.BaseColor(240, 240, 240);
table.AddCell(cell);
if (dataGridView1.Rows.Count > 0)
for (int i = 0; i < dataGridView1.Rows.Count; i++)
PdfPCell[] objcell = new PdfPCell[dataGridView1.Columns.Count];
for (int j = 0; j < dataGridView1.Columns.Count - 0; j++)
cell = new PdfPCell(new Phrase(dataGridView1.Rows[i].Cells[j].Value.ToString(), font5));
cell.HorizontalAlignment = PdfPCell.ALIGN_LEFT;
cell.VerticalAlignment = PdfPCell.ALIGN_LEFT;
cell.Padding = PdfPCell.ALIGN_LEFT;
objcell[j] = cell;
PdfPRow newrow = new PdfPRow(objcell);
table.Rows.Add(newrow);
document.Add(table);
MessageBox.Show("PDF Generated Successfully");
document.Close();
else
//Error
catch (FileLoadException fle)
MessageBox.Show(fle.Message);
MessageBox.Show("Error in PDF Generation", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
Runtime Gridview content:
Generated PDF File:
Thanks & Regards RAJENDRAN M
Hello,
Since this issue is mainly related to iTextSharp which belongs to third-party, I would recommend you consider posting this issue on its support website to get help.
Maybe the following forum will help.
http://support.itextpdf.com/forum/26
Regards,
Carl
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Creating a zip file from the contents of a directory

hi, I am having a problem as the title suggests with a zip fil creation...
using the basic example zip.java i wished to edit it so it doesnt zip a file fro the current directory but rather a directory i inputted.
It is able to read the first file then throws out the following error with the code below it:
java.io.FileNotFoundException: test.jpg (The system cannot find the file specified)
import java.io.*;
import java.util.zip.*;
public class Zip {
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FileInputStream fi = new FileInputStream(files[i]);
origin = new BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(files[i]);
out.putNextEntry(entry);
int count;
while((count = origin.read(data, 0,
BUFFER)) != -1)
out.write(data, 0, count);
origin.close();
out.close();
catch(Exception e)
e.printStackTrace();
After investigation i am lead to believe this is because the method returns an array of file and directory names only but not their path and the unqualified names would have therefore be defaulted to the current working directory. Something i understand if this is the case.
So instead i used the File.listFiles() method to return an array
of File objects, instead of an array of Strings as shown in the snippet of the changed code below (the changed code highlighted)...but arrived at another error on the second section of highlighted code meaning i cant compile. I cant understand why this is so!
The error is: "cannot find symbol, Symbol: Contructor ZipEntry (Java.IO.file), location: class.java.util.zip.ZipEntry"
File f = new File("C:/Documents and Settings/Phil/My Documents/My Pictures/Work/");
         **************File g[] = f.listFiles();***************
         **************String files[] = f.list();**************
         for (int i=0; i<g.length; i++)
            System.out.println("Adding: "+g);
FileInputStream fi = new FileInputStream(g[i]);
origin = new BufferedInputStream(fi, BUFFER);
**************ZipEntry entry = new ZipEntry(g[i]);************
out.putNextEntry(entry);
int count;
while((count = origin.read(data, 0,
BUFFER)) != -1)
out.write(data, 0, count);
origin.close();
out.close();
Any help and thoughts most appreciated. Thank u in advance

I'll admit i took 1 look at that reply an thought "thats stupid that wont work"...
then a second look an though "actually, i should work i cant believe i didnt think of that"
Anyways i tried it and it did work
How are the duke dollars awarded, cos u should have them ordinary_guy
cheers!

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Any thoughts on what might be causing this?

Another follow-up: Now, for whatever reason, even attachments of a single document aren't going through.
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Zip file uploaded by CF can't be unzipped by CF or Java

I'm having a WTF moment right now trying to track down this
problem. I am creating a monitoring tool for our merge email
system. What I would like to do is submit a job zip file through
our upload form, in which case I just need to upload a zip file
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================

danielmroberts,
I tested it and received the same error. Using
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usually 2b bigger than original. Though I do not know if that
matters at all.
The strange thing is if you add another parameter after the
zip file (an empty text file or a form field), it suddenly works.
<cfhttp url="
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<cfhttpparam name="zipfile" type="file"
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<cfhttpparam name="placeholder" type="FormField"
value="Empty Field">
</cfhttp>

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I have a problem where I have loaded up a series of inter-linked HTML files created in an HTML editor (e.g. Dreamweaver). They all exist within a folder and all the links work. As soon as I amend a file and reload it, it gets a new name on the database (for example index_0.htm and then index_1.htm). Therefore because the name has changed the links no longer work. I have item versioning switched off in the content area and the folders where the items reside.
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Download zip files for Oracle 12c are corrupt

Hi,
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1. winx64_12c_database_1of2
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below are corrupted files when downloaded 2nd time
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!   C:\Downloads\winx64_12c_database_2of2(1).zip: CRC failed in database\stage\Components\oracle.rdbms.install.seeddb.sample_schema\12.1.0.1.0\1\DataFiles\Expanded\filegroup1\sampleschema.dfb. The file is corrupt
Request you to Advice.
Thanks
Saurabh

I assume you are downloading from this page - http://www.oracle.com/technetwork/database/enterprise-edition/downloads/database12c-win64-download-1968077.html
Have you verified the checksums of the two zip files after you downloaded them ?
HTH
Srini

Zip file upload to content area

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