Can I submit form using app.launchURL

I want to submit a pdf form without replacing my page. I need it open in new tab.
The script below is work, but it replaces my old page
this.submitForm({
cURL:
"http://localhost:8080/project/TestServlet",
cSubmitAs:
"PDF",
cCharset:
"utf-8"
This script is open a new tab but I have no idea how can I submit a form using this
app.launchURL("http://localhost:8080/project/TestServlet", true);
Can anyone guide me how to submit form with open new tab on the web browser?
Thanks.

No, you can't submit the form like that. You could submit some form data as
a URL parameter, though.

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This worked fine until our company pushed out Adobe Reader X to all of our employees. Now the above function does nothing.
Is anyone experiencing similar?   When I say the function does nothing, you click on button that runs the above function, and no new window opens with specified URL.

I am not quite sure what that means. Can you please explain?
This has worked on same client pc before with version 7 - 9.   Now doesn't work anymore since upgrade to Adobe Reader X.
Note: ALL other AcroScript functions work properly
Really appreciate any assistance you have.
Jeremy
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Putting TRUE in there produces no result.
Message was edited by: jred33

Using app.launchURL to make an mp3 play in hosts default program?

Im trying to find an easy way to provide audio help from within the forms, so am using app.launchURL to target mp3 files (have soundbooth so can change file type if that helps make it easy).
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Hi,
Some time ago I downloaded JavaScript for Acrobat API reference doc. In this doc i found some function which can be helpfull for you - getPlayers.
I didn't check is it working in Designer ES or not, but you can try )
Example 1
List MP3 players to the debug console.var mp = app.media.getPlayers("audio/mp3")
for ( var i = 0; i < mp.length; i++) {
console.println("\nmp[" + i + "] Properties");
for ( var p in mp[i] ) console.println(p + ": " + mp[i][p]);
Example 2Choose any player that can play Flash media by matching the MIME type. The code assumes the code below is executed as a Rendition action with associated rendition (so no arguments for createPlayer are required).
var player = app.media.createPlayer();
player.settings.players = app.media.getPlayers( "application/x-shockwave-flash" );
player.open();
BR,
Paul Butenko

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Submit form data using handheld devices over a wireless connection. If you are working offline, the data is temporarily stored, then submitted once a connection is established. Send forms by e-mail or directly to the destination server using a cradle or cable

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Aside from the free app you were trying to download, make sure your Mac meets Lion's requirements...
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jonbradley wrote:
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The SendMail doesn't know how to talk to your default mail client. Please select a different mail application to use.
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Go to Solution.

Hi senthukannan
Thank you for posting and welcome to Nokia Support Discussions!
May we know the model of your phone? Where are you trying to download all the applications? Any error message? Please provide us all the important information so we can get better answers from the community.
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Not sure if this is the correct forum to raise this question
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Sorry, this is in the wrong place (and I can't find a way to delete it). Please ignore.

I can't compile forms using telnet ....

i have an application server with linux redhat 4 software.
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do
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but every time i have to go to the server which is located in another room. with every modification i have to recompile and have to go to the other room .
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[oracle@apps forms_to_compile]$ sh cpfdry.sh
compiling form PA_SPECIAL_PAY_COST.fmb
FRM-91500: █و╤ ▐╟╧╤ ┌طه ╚╧┴/┼▀ع╟ط ╟ط╚غ╟┴
compiling form sal_arseda_balance.fmb
FRM-91500: █و╤ ▐╟╧╤ ┌طه ╚╧┴/┼▀ع╟ط ╟ط╚غ╟┴
compiling form sal_order_reserve.fmb
FRM-91500: █و╤ ▐╟╧╤ ┌طه ╚╧┴/┼▀ع╟ط ╟ط╚غ╟┴
as you can see i got an error and the forms aren't compiled.
and still now i have the same problem, and unfortunatly i still have to go to the room that have the server many times at the day ..
what is the problem, i need some help plz ..
thanks....
sabry...
Edited by: user635392 on Jan 8, 2011 5:24 AM

thanks for interest..
yes , it is the same user
my server ip is 192.9.200.2, so i write in the command line ' telnet 192.9.200.2.
Red Hat Enterprise Linux ES release 4 (Nahant Update 4)
Kernel 2.6.9-42.ELsmp on an i686
login: oracle
Password:
in the login and password i use the same user ' oracle ' and the same password
thanks ..
sabry ..

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Can I submit form using app.launchURL

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