Converting a single edition into Multiple edition

Question

I have created a single edition ipad app (Game Drive - A Safari Guide), which is selling well. But now I want to create an iphone app multiple edition app. I submitted the iphone app, but Apple rejected it as they say that it is not compatible with ipad. So to be able to have an iphone app, I have to have an ipad version of the same app. My problem is that it is the same app, i.e. if I have a multiple edition app called Game Drive, it will be the same as the single edition app that I already have on the app store.
My questions are: 1. What is the tendancy - do people buy multiple edition apps more, or single editions? i.e. will I loose out if I convert to a multiple edition app on my ipad?
2. If I keep the single edition of the app on the app store for the ipad, will people get confused because there are two apps with the same name? Has anybody done that before?
3. Is it worthwhile putting it on newsstand?
My existing app is selling quite well, and don't want to mess with something that works. But to be able to create an iphone app, I have to have a multiple ipad app of the same thing.
Can someone give some advice please?

Answer 1

SQL> create table hierarchy_table
  2  as
  3  select 1 parent, 2 child from dual union all
  4  select null, 1 from dual union all
  5  select 1, 3 from dual union all
  6  select 2, 4 from dual union all
  7  select 3, 5 from dual union all
  8  select 2, 6 from dual
  9  /
Tabel is aangemaakt.
SQL> column s format a30
SQL> column c1 format a5
SQL> column c2 format a5
SQL> column c3 format a5
SQL> select s
  2       , substr
  3         ( s
  4         , nullif(instr(s,'|',1,1),0) + 1
  5         , nvl(nullif(instr(s,'|',1,2),0),4000) - instr(s,'|',1,1) - 1
  6         ) c1
  7       , substr
  8         ( s
  9         , nullif(instr(s,'|',1,2),0) + 1
10         , nvl(nullif(instr(s,'|',1,3),0),4000) - instr(s,'|',1,2) - 1
11         ) c2
12       , substr
13         ( s
14         , nullif(instr(s,'|',1,3),0) + 1
15         , nvl(nullif(instr(s,'|',1,4),0),4000) - instr(s,'|',1,3) - 1
16         ) c3
17    from ( select sys_connect_by_path(child,'|') s
18             from hierarchy_table
19          connect by parent = prior child
20            start with parent is null
21         )
22  /
S                              C1    C2    C3
|1                             1
|1|2                           1     2
|1|2|4                         1     2     4
|1|2|6                         1     2     6
|1|3                           1     3
|1|3|5                         1     3     5
6 rijen zijn geselecteerd.Regards,
Rob.