Count days
Hi experts,
i m looking for a fm or code for counting occurence of a day in period.
Example : I want to count the number of times that monday occurs in the period between begin date 01-01-2010 and end date
31-12-2010.
So i have the input parameters : name of the day ( number of the day ). and begin and end period
Hi,
Please check this link will help you find your solution.
http://wiki.sdn.sap.com/wiki/display/ABAP/FunctionModulerelatedonDate+calculations
Cheers.
Similar Messages
-
Count days in a month for a date range
i am trying to find no. of days between 2 Date Ranges for a list of Ids. i used the logic in the below link:
count days of the month
My query is giving duplicates since, I have list of Ids.
Doctor_ID Patient_ID ARRIVE_DT_TM DISCH_DT_TM
755722 42972229 10/18/2012 7:50 3/14/2013 20:45
763305 42972232 1/7/2013 20:27 3/15/2013 19:15
25391509 42972298 2/4/2013 22:45 3/8/2013 22:03
746779 42972331 1/4/2013 23:00 3/26/2013 21:50
763305 42972338 3/4/2013 22:19 3/6/2013 19:35
763305 42972411 11/4/2013 22:32 3/29/2013 17:30
I am looking for query to give me for Patient_ID = 42972229
MONTH COUNT_DAYS
201210 14
201211 30
201212 31
201301 31
201302 28
201303 14
I am running the following code and it loops through the months and gives duplicates when I remove where Patient_id IN (42972229)
select
Doctor_ID
, Patient_ID
, AR_DTTM
, DSC_DTTM
, TO_CHAR(ADD_MONTHS(TRUNC(date1, 'MONTH'), LEVEL - 1), 'YYYY MM') MONTHS_BET
, (LEAST(date2, ADD_MONTHS(TRUNC(date1, 'MONTH') - 1, LEVEL)) - GREATEST(date1, ADD_MONTHS(TRUNC(date1, 'MONTH'), LEVEL - 1)))+ 1 AS DAYSCOUNT
from (select
Doctor_ID
, Patient_ID
, ARRIVE_DT_TM AR_DTTM
, DISCH_DT_TM DSC_DTTM
,TRUNC(ARRIVE_DT_TM,'DDD') AS date1
,TRUNC(DISCH_DT_TM,'DDD') AS date2
from temp where Patient_id IN (42972229)
CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(date2, 'MONTH'), TRUNC(date1, 'MONTH')) + 1
Please help!Hi,
ASTRA_007 wrote:
Results I would like to see are:
Doctor_ID Patient_ID ARRIVE_DT_TM DISCH_DT_TM Month CountofDays
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 10 14
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 11 30
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 12 31
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 01 31
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 02 28
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 03 14
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 01 25
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 02 28
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 03 15
and so on...So each row represents a patient-month, and you want to display several columns from the temp table on each output row. In that case, include all those columns in both the SELECT and GROUP BY clauses, like this:
WITH universe AS
SELECT *
FROM temp
-- WHERE patient_id IN (42972229)
, date_range AS
SELECT TRUNC (MIN (arrive_dt_tm)) AS first_date
, TRUNC (MAX (disch_dt_tm)) AS last_date
FROM universe
, all_dates AS
SELECT first_date + LEVEL - 1 AS a_date
FROM date_range
CONNECT BY LEVEL <= (last_date + 1) - first_date
SELECT u.doctor_id
, u.patient_id
, u.arrive_dt_tm
, u.disch_dt_tm
, TO_CHAR ( TRUNC (a.a_date, 'MONTH')
, 'YYYY MM'
) AS month
, COUNT (*) AS count_days
FROM all_dates a
JOIN universe u ON a.a_date BETWEEN TRUNC (u.arrive_dt_tm)
AND u.disch_dt_tm
GROUP BY u.doctor_id
, u.patient_id
, u.arrive_dt_tm
, u.disch_dt_tm
, TRUNC (a.a_date, 'MONTH')
ORDER BY u.patient_id
, TRUNC (a.a_date, 'MONTH')
;Output from your sample data (with no filtering):
`DOCTOR_ID PATIENT_ID ARRIVE_DT_TM DISCH_DT_TM MONTH COUNT_DAYS
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 10 14
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 11 30
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2012 12 31
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 01 31
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 02 28
755722 42972229 10/18/2012 7:50 3/14/2013 20:45 2013 03 14
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 01 25
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 02 28
763305 42972232 1/7/2013 20:27 3/15/2013 19:15 2013 03 15
25391509 42972298 2/4/2013 22:45 3/8/2013 22:3 2013 02 25
25391509 42972298 2/4/2013 22:45 3/8/2013 22:3 2013 03 8
746779 42972331 1/4/2013 23:0 3/26/2013 21:50 2013 01 28
746779 42972331 1/4/2013 23:0 3/26/2013 21:50 2013 02 28
746779 42972331 1/4/2013 23:0 3/26/2013 21:50 2013 03 26
763305 42972338 3/4/2013 22:19 3/6/2013 19:35 2013 03 3
In the end the objective is to count the no. of days in each month between the arrival and discharge dates by Physician and for his/her patients.Then is the output above really what you want? Say you're interested in physician 763305. That physician had 18-patient days in March, 2013, but the output doesn't make it clear.
I ran your query, it works great but I have a long list of patients for whom I have to run these counts.the query above includes all patient_ids.
That's a separate problem, to be solved in the first sub-query, universe. The rest of the query will be unchanged.
How will you know which patients to include? If you can derive the list from temp itself, just use a WHERE clause in universe. If you need to look at other tables, join them in universe, or use them in sub-queries in universe, or both.
For exmple, if you decide that the list of patient_ids has no pattern, and that you'll need to store their ids in a separate table (perhaps a global temporary table), then universe might be:
WITH universe AS
SELECT t.* -- or list columns needed
FROM temp t
JOIN patient_ids_to_include p
ON p.patient_id = t.patient_id
) ...The rest of the query can be the same as above.
If a same patient is admitted again then Patient_ID will be different no matter when readmitted.Are you saying that patient_id identifies a visit, not a patient, and that the same person is assigned a different patient_id every time that person is admitted?
For
INSERT INTO temp (doctor_id, patient_id, arrive_dt_tm, disch_dt_tm)
VALUES ( 755722
, 42972229
, TO_DATE ('03/14/2013 23:00', 'MM/DD/YYYY HH24:MI')
, TO_DATE ('04/01/2013 12:00', 'MM/DD/YYYY HH24:MI')
First the Patient ID will be different from the earlier admission. Second the results will show like:
Doctor_ID Patient_ID ARRIVE_DT_TM DISCH_DT_TM Month CountofDays
755722 42972229 3/14/2013 23:00 4/1/2013 12:00 2012 03 14
755722 42972229 3/14/2013 23:00 4/1/2013 12:00 2012 04 1Are you saying that temp.patient_id is unique, and so the situation is impossible?
Edited by: Frank Kulash on May 7, 2013 10:23 AM -
Hi Team members,
we are working on a budgeting application and stuck on below Research, please assist/advise is there any built-in Function to count Days in a Month which we can use or a work around .
Requirement:
To calculate budgeted Expenses per month, user will enter the daily budgeted expenses for a month and it will multiple with total number of days in a month via formula. same thing happens to some revenue items.
Note:
every months contains different number of Days which will result in change in Expense/Revenue figures.
e.g
Daily Expense for Jan will be $100/day
total days in Jan = 31
Result will be 31*100 = $3100 expense in Jan
but in Feb it will be
Daily Expense for Feb will be $100/day
total days in Jan = 28
Result will be 28*100 = $2800 expense in Feb
Regards,
AleeDear Alp,
Thanks for the Code!!!
Note:
In general terms the algorithm for calculating a leap year is as follows...
A year will be a leap year if it is divisible by 4 but not by 100. If a year is divisible by 4 and by 100, it is not a leap year unless it is also divisible by 400.
Thus years such as 1996, 1992, 1988 and so on are leap years because they are divisible by 4 but not by 100. For century years, the 400 rule is important. Thus, century years 1900, 1800 and 1700 while all still divisible by 4 are also exactly divisible by 100. As they are not further divisible by 400, they are not leap years.
Regards,
Alee -
So, I got Adobe CC a year ago and I recently downloaded ABOBE CC 2014 at adobes SUGGESTION. When I open After effects it says I only have 4 (and counting ) days left to purchase…………I’m supposed to get it for FREE, right?. It doesn’t happen when I open illustrator and Photoshop CC 2014. Am I doing something wrong? If you’re not the one to contact please refer to the correct person……….the school uses AE CC 2014 so I NEED to have the correct version.
you MAY need to log out of the Cloud and restart your computer and log back in to the Cloud for things to work
or
A chat session where an agent may remotely look inside your computer may help
Creative Cloud chat support (all Creative Cloud customer service issues)
http://helpx.adobe.com/x-productkb/global/service-ccm.html -
dear members,
I have been provided with the date range.
i want to calculate the no. of days for each month, within the above date range.
e.g. date1='10-01-2011' and date2='18-03-2011'
for month=01 count days=22
for month=02 count days=28
for month=03 count days=18
thanks
teefu
developerWITH parameters AS
SELECT TO_DATE ( '10-01-2011'
, 'DD-MM-YYYY'
) AS start_dt
, TO_DATE ( '18-03-2011'
, 'DD-MM-YYYY'
) AS end_dt
FROM dual
SELECT TO_CHAR ( start_dt + LEVEL - 1
, 'FMMonth YYYY'
) AS month
, COUNT (*) AS days
FROM parameters
CONNECT BY LEVEL <= 1 + end_dt - start_dt
GROUP BY TO_CHAR ( start_dt + LEVEL - 1
, 'FMMonth YYYY'
ORDER BY MIN (LEVEL)
duplicate thread already one has given the above answer
count days of the month
Edited by: LPS on Jul 21, 2011 2:16 AM -
FM to exclude holidays and weekends and count days in Leave period
Hi Friends,
My requirement is to count no of days leave applied !!
Which should exclude Holidays and weekends and count only business days..
I.E. per week onlyt 5 working days!!
Is there any FM to do so Becasue this exlcuding holidays not happens manually...
Thanks in advance...
Regards
sasHi Dilek Please can you send the screen shots of those
Just put HRworkdays F4 and can you send the screen shots of those please!!!Which will help to show to my client !!
MY id is in businees card please take it as per rules i cant type ....Thanks in advance!!
Regards
sas
Edited by: saslove sap on Sep 8, 2009 8:32 AM
I have check with other client systems of ECC 6.0 there is no FM of you provided !! Intresting !!
Any one any other idea to achieve the same please provide!!
Regards
sas
Edited by: saslove sap on Sep 8, 2009 9:45 AM
Edited by: saslove sap on Sep 8, 2009 10:04 AM -
Count days between two dates without weekend
Hi,
I need a solution in query or another thread, that returns the count of days between two dates without consider weekend (saturday and sunday) , I have the columns of type Date, and the return need in format of hours in one column hh:mm:ss and days in another column.
Regards
JonasHi and welcome to the forum.
Keep in mind that you can do a search on this forum.
Your question has been asked before.
Some other pointers:
http://asktom.oracle.com/pls/asktom/ASKTOM.download_file?p_file=6551242712657900129
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:185012348071 -
MDX count days - since registered (customer) - dynamically
Hi, I have a problem with a MDX statement and I did not find an approach.
We have a customer dimension that includes a date for the registration. We want to know following:
How many days since the registration, but not only for the actual date (today), it must be dynamic.
Example:
Customer A registered on 2011-08-15 (yyyy-mm-dd).
Whenwe choose the time dimension an we take the date 2011-08-20 we want the number 5 because he is registered since 5 days. When we choose 2011-08-25 the result would be 10 etc.
It could be so easily: calculate the difference in days between Registration day and selected day ([Date].[Date].currentmeber????)
Something like: datediff(days, [dim Customer].[Registration Date], [Date].[Date])
But I´m to stupid to translate this easy problem to MDX. Any hints?EDIT: Fixed it (Forgot the date-dimension on axis 1) THANKS!
Hi dstewartbi,
your code looks not bad. Problem is: Only the actual date is not enough. I need something like currentMember. If I try this:
WITH
MEMBER [Measures].[Days Since Registration] AS
( StrToMember ( '[Dim Date].[Full Date Alternate Key].&[' + [Dim Customer].[Date Of Birth].CurrentMember.MEMBER_NAME + 'T00:00:00]' )
: StrToMember ( '[Dim Date].[Full Date Alternate Key].&[' + [Dim Date].[Full Date Alternate Key].CurrentMember.Member_Name+ 'T00:00:00]' ) ).Count
- 1
I get following error:Cannot convert 'AllT00:00:00' into date-type
If I just use:
WITH
MEMBER [Measures].[Days Since Registration] AS
( StrToMember ( '[Dim Date].[Full Date Alternate Key].&[' + [Dim Customer].[Date Of Birth].CurrentMember.MEMBER_NAME + 'T00:00:00]' )
: [Dim Date].[Full Date Alternate Key].CurrentMember ).Count
- 1
I get the error (in german): "Operanden des Bereich (:) haben unterschiedliche Ebenen, müssen jedoch identisch sein"
Something like Operands have different levels. -
PCL 1: What is ANZHL & ANZHL1 & how to count days taken
hi experts,
I have question to understand PCL1. I want to check check all the annual leave types using in
infotype 2001 for this year. However when I check table purl, fields anzhl show all the leave
has been taken, include off day. For example I have taken leave 01/04/2010-6/04/2010.Actual date 05/04 is
off day. However in fields anzhl, it will count 6 days(include off day). When I check fields anzh1
it show 9 for every single day except 05/04. On 05/04, it show 0. What does it means actually,
can I assume 0 in anzh1 as off day. How about 9?HI,
0 and 9 must be the planned working hours from DWS on those respective days. Please cross check.
cheers
AJ -
How to count days between two dates excluding saterady and sunday
Hi all
iam working on oracle sql/plsql.
In my application , i need to caliculate leave days between two dates excluding saterady and sunday
Please tell me the solution if any one knows
thanks in advance ,
baluMore modern version:
WITH date_tab AS
(SELECT TO_DATE ('&from_date', 'dd-MON-yyyy')
+ LEVEL
- 1 business_date
FROM DUAL
CONNECT BY LEVEL <=
TO_DATE ('&to_date', 'dd-MON-yyyy')
- TO_DATE ('&from_date', 'dd-MON-yyyy')
+ 1)
SELECT business_date
FROM date_tab
WHERE TO_CHAR (business_date, 'DY') NOT IN ('SAT', 'SUN');Thank you,
Tony Miller
Webster, TX
Never Surrender Dreams!
JMS
If this question is answered, please mark the thread as closed and assign points where earned.. -
Dear all,
We want to have DP91 (automatic billing) for one of our dept. The timesheets are interfaced with the WBS element of sales oder (time sheets are entered to the WBS activities by the associates). My problem is that when we are trying to run DP91 its taking the hours but we wanted to count days such that if an associate enters the timesheet for even one minute in a day it should be counted as a day for him.. Even we have put the UOM as u2018dayu2019 for the materials but in DP91 its appearing as hours.
How to solve this problem.
Regards,
PadmajaHi,
I could understand from your question that You need to convert resources' hours in days.
Please go to MM02-enter material no,organizational data and select views.You get material in change mode.Press on additional data button on application tool bar and select unit of measurement views.
enter conversion unit on this screen.
For example -If you consider 1 working day is 8 hours,maintain 1 day equal to 8 hours.
If consultant enter 2 hours then it will be converted as 0.25 day.
(Moreover you need to create WBS element for each consultant.I suggest you discuss your requirement with your MM consultant to help you.)
Thanks,
Vrajesh -
Count consecutive Workdays where employee has taken SICK leave
I am trying to identify a way within sql to count the number of consecutive workdays (Monday - Friday) an employee has taken SICK leave. My problem in the past has been trying to count days whereas we cross the weekend. Currently I have 4 queries identifying patterns around the weekend that I run and export into an Excel Spreadsheet and manipulate from there. My goal is to be able to list an EMPLID (employee id), EMPL_RCD ( employee record), Min(DUR) (Date of absence), Max(DUR), and count of consecutive workdays.
Any help or guidance would will be appreciated. I have attached my current query.
I run my current query 4 times using the patterns below one at a time.
SELECT DISTINCT A.EMPLID,A.EMPL_RCD, A.DUR,b.dur,c.dur,d.dur, A.TL_QUANTITY, A.TRC
FROM PS_TL_RPTD_TIME A, PS_TL_RPTD_TIME B, PS_TL_RPTD_TIME C,PS_TL_RPTD_TIME D
WHERE A.EMPLID = B.EMPLID
AND A.EMPL_RCD = B.EMPL_RCD
AND A.EMPLID = C.EMPLID
AND A.EMPL_RCD = C.EMPL_RCD
AND A.EMPLID = D.EMPLID
AND A.EMPL_RCD = D.EMPL_RCD
AND B.EMPLID = C.EMPLID
AND B.EMPL_RCD = C.EMPL_RCD
AND B.TRC = C.TRC
AND A.TRC = B.TRC
AND A.TRC = C.TRC
AND A.TRC = D.TRC
AND (B.DUR = A.DUR+3 AND C.DUR = A.DUR+4 AND D.DUR = A.DUR+5) Friday, Monday, Tuesday, Wednesday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+4 AND D.DUR = A.DUR+5) Thursday, Friday, Monday, Tuesday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+2 AND D.DUR = A.DUR+5) Wednesday, Thursday, Friday, Monday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+2 AND D.DUR = A.DUR+3) -- Same workweek
AND A.TRC LIKE 'SICK%'
AND NOT EXISTS ( SELECT 'x' FROM PS_JOB J
WHERE J.EMPLID = A.EMPLID
AND J.EMPL_RCD = A.EMPL_RCD
AND J.EMPL_STATUS IN ('P','L')
AND J.EFFDT = ( SELECT MAX(J1.EFFDT) FROM PS_JOB J1
WHERE J1.EMPLID = J.EMPLID
AND J1.EMPL_RCD = J.EMPL_RCD
AND J1.EFFDT <= D.DUR))You should consider a technique from data warehousing where you use a table to describe dates. To keep things simple, let's create a table that holds all your valid business days for the past 2 weeks...
create table business_dates (business_day date);
begin
insert into business_dates values (to_date('16-oct-2006'));
insert into business_dates values (to_date('17-oct-2006'));
insert into business_dates values (to_date('18-oct-2006'));
insert into business_dates values (to_date('19-oct-2006'));
insert into business_dates values (to_date('20-oct-2006'));
insert into business_dates values (to_date('23-oct-2006'));
insert into business_dates values (to_date('24-oct-2006'));
insert into business_dates values (to_date('25-oct-2006'));
insert into business_dates values (to_date('26-oct-2006'));
insert into business_dates values (to_date('27-oct-2006'));
insert into business_dates values (to_date('30-oct-2006'));
insert into business_dates values (to_date('31-oct-2006'));
insert into business_dates values (to_date('01-nov-2006'));
insert into business_dates values (to_date('02-nov-2006'));
insert into business_dates values (to_date('03-nov-2006'));
end;
now we create a table that shows whether each employee was sick or not for a given work day...
create table attendance (empid number, business_day date, sick char(1));
insert into attendance values (100, to_date('16-oct-2006'), 'N');
insert into attendance values (100, to_date('17-oct-2006'), 'Y');
insert into attendance values (100, to_date('18-oct-2006'), 'Y');
insert into attendance values (100, to_date('19-oct-2006'), 'N');
insert into attendance values (100, to_date('20-oct-2006'), 'N');
insert into attendance values (100, to_date('23-oct-2006'), 'Y');
insert into attendance values (100, to_date('24-oct-2006'), 'Y');
insert into attendance values (100, to_date('25-oct-2006'), 'Y');
insert into attendance values (100, to_date('26-oct-2006'), 'N');
insert into attendance values (100, to_date('27-oct-2006'), 'N');
insert into attendance values (100, to_date('30-oct-2006'), 'N');
insert into attendance values (100, to_date('31-oct-2006'), 'Y');
insert into attendance values (100, to_date('01-nov-2006'), 'N');
insert into attendance values (100, to_date('02-nov-2006'), 'N');
insert into attendance values (100, to_date('03-nov-2006'), 'N');
insert into attendance values (105, to_date('16-oct-2006'), 'Y');
insert into attendance values (105, to_date('17-oct-2006'), 'Y');
insert into attendance values (105, to_date('18-oct-2006'), 'N');
insert into attendance values (105, to_date('19-oct-2006'), 'N');
insert into attendance values (105, to_date('20-oct-2006'), 'Y');
insert into attendance values (105, to_date('23-oct-2006'), 'N');
insert into attendance values (105, to_date('24-oct-2006'), 'N');
insert into attendance values (105, to_date('25-oct-2006'), 'Y');
insert into attendance values (105, to_date('26-oct-2006'), 'Y');
insert into attendance values (105, to_date('27-oct-2006'), 'Y');
insert into attendance values (105, to_date('30-oct-2006'), 'Y');
insert into attendance values (105, to_date('31-oct-2006'), 'Y');
insert into attendance values (105, to_date('01-nov-2006'), 'N');
insert into attendance values (105, to_date('02-nov-2006'), 'N');
insert into attendance values (105, to_date('03-nov-2006'), 'Y');
Now the query to get each sick occurrence and the number of consecutive days for each employee is...
select empid, first_sick_day, sick_count from
(select empid,
first_value(business_day) over (partition by empid, groupno order by business_day) as first_sick_day,
row_number() over (partition by empid, groupno order by business_day) as rn,
count(*) over (partition by empid, groupno) as sick_count
from
(select empid, business_day, daynum-rownum groupno
from
(SELECT a.empid, a.business_day, d.day_num as daynum
FROM attendance a,
(select rownum as day_num, business_day
from (select business_day from business_dates order by business_day)) d
WHERE sick = 'Y' AND a.business_day = d.business_day
ORDER BY 1,2 )
where rn = 1;
The above query can be modified slightly to only give you the sick occurrence with the maximum number of consecutive days for each employee.
Having a separate date table is nice because you can take in account weekends, holidays or any other nonwork day by just removing that date from the table. Generating this table is easy as date dimension examples can be found on on the web, and the amount of rows is small (250 rows per year approx).
JR -
Need to display date result but has to exclude sat & sun day
Hi all,
I need to display date (A), from the plan date (B) for qty more than 10, but the result of A, should be B -10 and should not include sat & sunday.
I managed to do in excel but I have problem in oracle sql here.
My quote in excel, =IF(qty<=10, WORKDAY(plan_date,-5), WORKDAY(plan_date,-10))
If qty=12, plan_date is 30/05/11, the result is 16/05/11
qty=2, plan_date is 30/05/11, the result is 23/05/11
Anyone can help me to quote in SQL ?
Thanks.
LimCREATE OR REPLACE FUNCTION GOKHAN.business_date (start_date DATE, days NUMBER)
RETURN DATE
IS
counter number := 0;
curdate DATE:= start_date;
BEGIN
WHILE counter < days
LOOP
curdate := curdate - 1;
IF TO_CHAR (curdate, 'D') BETWEEN 1 AND 5
THEN
dbms_output.put_line( curdate || ' ' || TO_CHAR (curdate, 'D'));
counter := counter + 1;
END IF;
END LOOP;
RETURN curdate;
END;
with t as (
select to_date('30/05/11','DD/MM/YY' ) plan_date, 12 qty from dual
union all
select to_date('30/05/11','DD/MM/YY' ) , 2 from dual
select qty, case when qty <= 10 then business_date( plan_date, 5 ) else business_date( plan_date, 10 ) end plan_date from t;
QTY PLAN_DATE
12 16/05/2011
2 23/05/2011Best Regards,
Gokhan Atil
If this question is answered, please mark appropriate posts as correct/helpful and the thread as closed. Thanks -
Get working days of actual month in time management
Hello,
a customer wants his employees to work some additional time every workday. The time is different for each employee and has to be specified on a monthly basis, but has to be shown daily in time sheet.
Days with holidays or illness do not require additional work, but count when calculation daily quota.
I would like to use P0050-ZTZUA to store the value of the hours which the employee has to work extra per month.
Now I need to divide this value through the number of workdays of the actual month, to get a value per day. Unfortunately I did not find any operation to get number of workdays.
Thanks in advanceHello again.
I did not get it!
I made a simple PCR "Z123" just to test, how to count days. It looks like this:
D VARSTCURMO
** HRS=1 ADDDB9082
I call this with ACTIO Z123 and see, that the result for timetype 9082 is 1 at every day that is evaluated in my calculation period.
In the example I do not care for workingdays, I just wanted to test, if the counting of days is functioning.
Since the timetype 9082 is cumulated, I get number of days of period at the end of the time calculation in SALDO-Table.
For example:
Day Saldo in 9082
January 1 1
January 2 2
January 3 3
January 31 31
My problem is, that I need the number of days at each day of the calculation. Already at January 1 I need to divide a given amount of time through the number of days (31 in the example).
I'm afraid, that this issue cannot be solved? -
ICal custom repeat every x days EXCLUDING weekends?
I have an event I would like to repeat every x number of days excluding weekends (so only counting M-F as "counted" days). Is there a way to do this?
You can exclude Sat/Sun, but they will still be counted - so an occurrence on those days is dropped, and you will get fewer occurrences than you should.
AK
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