Count when ID number sum total 300

Afternoon Folks,
Just wondering if somebody could help me with a code query?
I'm trying to count the number of Service Packs where the sum payment total for each distinct sp_id is less than £300 and also greater than £300.
This is the code I have so far:
select specialty,
count(distinct sp_id) "Service Packs",
sum(payment_total) "Total Paid £",
round(sum(payment_total)/count(distinct sp_id),0) "Average Spend per SP"
from a3_fact_sms_service_inv
where specialty in ('Chiropody','Podiatry')
and service_date between '01Jan11' and '31Dec11'
group by specialty
This is the table of what I want it to look like
SPECIALTY     Service Packs     Total Paid £     Average Spend per SP     *<300*     *>300*
Chiropody     129     25682.26     199     *107*     *22*     
Podiatry     622     206651.08     332     *403*     *219*
I'm currently running 10g application
Regards
Wardie:)

Hi,
when you post some code please include them between {noformat}{noformat}.
i.e.:
{noformat}{noformat}
DECLARE
a
{noformat}{noformat}
Additionally provide some table creation, sample data and expected output.
Please read [url:SQL and PL/SQL FAQ do I ask a question on the forums?[/url].
*Removed my suggestions as I misunderstood the problem*
Regards.
Al
Edited by: Alberto Faenza on Oct 24, 2012 5:05 PM
Updated                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

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