Displaying header with data binded to the R/3 system

hi
I have developed an application which uses Interactive form to generate the Invoice PDF by getting data from back end system R/3.
Now my problem is that the Header which I need to display contains some data binded with the back end system and that the Header needs to be displayed on each and every page of the Invoice.
I need to know how can we set the header so that the header is displayed on each page with the data binded to the back end system.
Immediate help would be appreciated.
Thanks and regards,
kris

Hi Gopi,
There is a limitation for your requirement.The runtime data will not change in each page or it will be blank in case of header.
I have used an alternative for the forms designed from SFP .I have called the PDF in a loop in the driver program. Then a new pdf will generated for each case.
May be the alternative is assign the values through scripting.
pavan meda

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                  <font family="Tahoma" size="10" color="0x" />
                  <format><![CDATA[{%Value}{numDecimals:0,decimalSeparator:.,thousandsSeparator:\,}]]></format>
                </labels>
                <major_grid enabled="False"/>
    <minor_grid enabled="False"/>
              </y_axis>
              <x_axis>
                <scale  mode="Normal" type="DateTime"    />
                <title enabled="false"/>
                <labels enabled="true" position="Outside">
                  <font family="Tahoma" size="10" color="0x" />
                  <format><![CDATA[{%Value}]]></format>
                </labels>
                <major_grid enabled="True" interlaced="false">
                    <line color="Black" />
                  </major_grid>
    <minor_grid enabled="True">
                  </minor_grid>
              </x_axis>
            </axes>
          </chart_settings>
          <data_plot_settings enable_3d_mode="false" >
            <line_series>
              <tooltip_settings enabled="true">
                <format><![CDATA[{%Name}{enabled:False} - {%Value}{numDecimals:0,decimalSeparator:.,thousandsSeparator:\,}]]></format>
                <font family="Tahoma" size="10" color="0x" />
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              </tooltip_settings>
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                <background enabled="false"/>
                <font family="Tahoma" size="10" color="0x" />
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              <marker_settings enabled="True" >
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              </marker_settings>
            </line_series>
          </data_plot_settings>
    #DATA#
        </chart>
      </charts>
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    This will be a little bit lengthy answer, but I guess it will be easier to understand what I meant to say.
    I created a table that contains values you used as a data source (just to make my life easier):
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    VALUE                    LABEL
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    12.10.2010 10:03:45          1
    12.10.2010 11:03:45          2
    12.10.2010 11:33:45          1
    12.10.2010 12:03:45          0
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    Step 1: current and previous values - difference in number of MINUTES
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    11:03 10:03           60
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    12:03 11:33           30Step 2: a little bit of calculation:
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    - MIN_DIFF: what is the minimum time difference (minutes)?
    - SLICES: how many time slices do we want on the x-axis?
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      4    min(x.minutes_diff) min_diff,
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      6    (max(x.value) - min(x.value)) * 24 * 60 / min(x.minutes_diff) slices
      7  from (select t.value,
      8               lag(t.value) over (order by t.value) previous_value,
      9               (t.value - lag(t.value) over (order by t.value)) * 24 * 60 minutes_diff
    10        from test t
    11       ) x;
    MIN_V MAX_V   MIN_DIFF  TIME_SPAN     SLICES
    09:03 12:03         30        180          6There's 180 minutes between 09:03 and 12:03; minimum time difference in our TEST table is 30 minutes, so - we want to have 6 time slices on the x-axis (180 / 30).
    Step 3: row generator technique: let's create time values that are missing:
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      2  from (select
      3          min(x.value) min_val,
      4          max(x.value) max_val,
      5          min(x.minutes_diff) min_diff,
      6          (max(x.value) - min(x.value)) * 24 * 60 time_span,
      7          (max(x.value) - min(x.value)) * 24 * 60 / min(x.minutes_diff) slices
      8        from (select t.value,
      9                     lag(t.value) over (order by t.value) previous_value,
    10                     (t.value - lag(t.value) over (order by t.value)) * 24 * 60 minutes_diff
    11              from test t
    12             ) x
    13       ) y
    14  connect by level <= y.slices + 1;
    VAL
    09:03
    09:33
    10:03
    10:33
    11:03
    11:33
    12:03
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    Step 4: join newly generated time values with the original table. Use OUTER JOIN; missing labels will be 0 (zero):
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      8                max(x.value) max_val,
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    19       ) z,
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      09:33          0
      10:03          1
      10:33          0
      11:03          2
      11:33          1
      12:03          0
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