Double.parseDouble() is not Locale specific, how do I get round this?

Question

I am parsing Strings into doubles using
String myNumber = "12,34";
double d = Double.parseDouble( myNumber );The problem is that my number is of French style (it has commas instead of fullstops for the decimal points)
The default Locale is English, so I get NumberFormat problems when parsing. (I can understand this)
I even get NumberFormat problems when I do this:
Locale.setDefault(Locale.FRENCH);
double d = Double.parseDouble( myNumber );Which I think is really strange. I guess the Locale of Double is set at a certain time and not reset.
OR maybe Double.parseDouble( <STRING> ); is not Locale specific?
Where is my understanding wrong?

Answer 1

Do you know if DecimalFormat reflects the default Locale if the default Locale changes?
Or will I have to make a new DecimalFormat whenever it changes?As Locale is invariant, a DecimalFormat instance (as well a any object with a reference to the default Locale) cannot reflect the default Locale changes.
But each time you create a new instance of DecimalFormat without specifying the Locale, it will get up-to-date Locale.
However, you might prefer setting the locale explicitely (instead of changing the default one.)
Note that Double valueOf() or parseDouble() methods are not related to default Locale, they use a fixed format.