Dynamic filename for stdout from cron

Question

OL 5.6 x86-64
I'm looking for a way to dynamicly specify a filename for stdout from a cron job.
From a command line, this works fine:
/home/estevens/bin/x1 > /tmp/estevens_x1_log.`date +%F_%H%M%S`Producing the desired output:
estevens:dwdev$ ls -ltr /tmp/est*
-rw-rw-r-- 1 estevens estevens 96 Aug 13 10:23 /tmp/estevens_x1_log.2012-08-13_102356But when I put that in my crontab:
12 * * * 1 /home/estevens/bin/x1 > /tmp/estevens_x1_log.`date +%F_%H%M%S`I get this result
/bin/sh: -c: line 0: unexpected EOF while looking for matching ``'
/bin/sh: -c: line 1: syntax error: unexpected end of file(Result comes to me in an auto-generated email)

Answer 1

The % sign has a special meaning in cron. A % is used to denote a new line in a crontab entry. You will simply have to escape the % signs and it should work, for instance:
<pre>
12 * * * 1 /home/estevens/bin/x1 > /tmp/estevens_x1_log.`date +\%F_\%H\%M\%S`
</pre>