Exists function- For common products in two sets

Question

Hi All ,
I have this below mdx query , where i want the common products that were submitted in december 2014 and present in the following two sets 
i) First Set :  List of apps  which are set by required attribute in ManualReview dimension as "true" ,result attribute is "fail" for them  and  Submitted date is
December 2014 
ii) Second set : List of products where IsAutopassed is "True"  and Submitted date is
December 2014  . 
Below is the mdx query for this. But i am not able to get common products out of these two sets . i.e. i want to implement the sql functionality of 
SELECT * FROM SET1 WHERE PRODUCTID IN ( SELECT PRODUCTID FROM SET2)
SELECT
non empty
EXISTS(
[DimProduct].[ProductId].[ProductId].members,[DimManualReview].[Required].&[True],
[DimResult].[Result].&[Fail],
[DimSubmittedDate].[Calendar Date Hierarchy].[Year].&[Calendar 2014].&[Quarter 4, 2014].&[December 2014]
[DimProduct].[ProductId].[ProductId].members, [DimProductSubmission].[IsAutoPassed].&[True],
[DimSubmittedDate].[Calendar Date Hierarchy].[Year].&[Calendar 2014].&[Quarter 4, 2014].&[December 2014]
) ) ON ROWS,
non empty [Measures].[ProductCount] ON columns
FROM RAD
Please help me in getting in to a right direction.

Answer 1

Hi NedunuriRajesh,
According to your description, you want to get the common member from two sets. Right?
In this scenario, I suggest you use INTERSECT() the intersection of two input sets. Please try the MDX below:
SELECT
non empty
INTERSECT(
[DimProduct].[ProductId].[ProductId].members,[DimManualReview].[Required].&[True],
[DimResult].[Result].&[Fail],
[DimSubmittedDate].[Calendar Date Hierarchy].[Year].&[Calendar
2014].&[Quarter 4,
2014].&[December 2014]
[DimProduct].[ProductId].[ProductId].members,
[DimProductSubmission].[IsAutoPassed].&[True],
[DimSubmittedDate].[Calendar Date Hierarchy].[Year].&[Calendar
2014].&[Quarter 4,
2014].&[December 2014]
ON ROWS,
non empty [Measures].[ProductCount]
ON columns
FROM RAD
If you have any question, please feel free to ask.
Simon Hou
TechNet Community Support