Feedback-desperate!

Question

Okay, my program generates a 3 letter string. The user guess'. Now depending on how close they are they should receive feedback.
A “W” indicates that they don’t have any characters right. One or more “O”s indicates that they have a correct character/s, but in the incorrect position/s.
Finally, one or more “C”s indicates that they have the correct character/s in the correct position/s.
I have started but need some help;
String cString = ""; //for storing Cs
String oString = ""; //for storing Os
loop over the first string guess.
for(int i=0; i<3; i++)
//get the i th char from the String to compare to the other String.
char guessCharI = guess.charAt(i);
//loop over random String to compare
for(int j=0; j<3; j++)
//now do a similar thing in getting the j th char from the random String
char randCharJ = random.charAt(j);
//if i==j and the chars are the same, you can add a C to the
cString
//if i!=j and the chars are the same, you can add a O to the
oString.Help..... Can someone please help me start?
I hope I haven't lost anyone.
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Answer 1

A &#8220;W&#8221; indicates that they don&#8217;t have any characters right. One or more &#8220;O&#8221;s indicates that they have a correct character/s, but in the incorrect position/s.Finally, one or more &#8220;C&#8221;s indicates that they have the correct character/s in the correct position/s.
That's kind of looking at it backwards. Provided that care is taken to ensure that the two Stirngs are in fact the same length --
-- Loop though once comparing characters at the same position
-- Whan a match is found, increment a counter and replace the character in both Strings at that position with some character that is illegal to your words .. like @ or _.
-- Loop through in nested loops comparing legal characters in cString with all legal characters in oString.
-- Same as second step above
-- Loop through either String and count the remaining legal characters.
Using [String#toCharArray|http://java.sun.com/javase/6/docs/api/java/lang/String.html#toCharArray()] may be useful for this exercise.
I leave it as an exercise to you to combine the loops into more efficient code, but do that only after you have it working with 3 separate passes.
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