Figuring out the correct icloud account

We had to "clear"out our sons iphone 4 (which is not connected to service) because he forgot his password. He's using it like an ipod. When we did this and tried to set it up it is asking us to conncect to an icloud account - but we can't figure out which one. None of our other 3 devices are set up to the one it's prompting us to nor will it recognize the icloud account that it was origanally linked to. Any suggestions?

Thanks Roger this is uncouraging. I went into my iDisk and I found two things. A folder called Istvan's site that opened to a folder called Blog to a file called rss.xml. This file would not open after I downloaded it. The other thing in the same location was a file called sites.rss that I was able to open. I'm hoping that is the one I need to change. Is it?
The very start of the code has the channel and item tags like you mention in your instructions. Here it is:
<?xml version="1.0"?>
<rss xmlns:admhp="http://www.apple.com/DotMac/Homepage" version="2.0">
<channel>
<title>i.am.istvan</title>
<description></description>
<link>http://web.mac.com/i.am.istvan/iWeb</link>
<item>
<title>Blog</title>
If in fact this is the file I need to alter do I replace the three lines between the two tags with my new location? Or do I do something else? Why do I feel like I'm about to cut the wrong wire? Thanks Roger.

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Can't figure out the correct syntax for this select statement

Hello,
The following statement works great and gives the desired results:
prompt
prompt Using WITH t
prompt
with t as
   select a.proj_id,
          a.proj_start,
          a.proj_end,
          case when (
                     select min(a.proj_start)
                       from v b
                      where (a.proj_start = b.proj_end)
                        and (a.proj_id    != b.proj_id)
                    is not null then 0 else 1
          end as flag
     from v a
    order by a.proj_start
select proj_id,
       proj_start,
       proj_end,
       flag,
       -- the following select statement is what I am having a hard time
       -- "duplicating" without using the WITH clause
        select sum(t2.flag)
          from t t2
         where t2.proj_end <= t.proj_end
       ) s
from t;As an academic exercise I wanted to rewrite the above statement without using the WITH clause, I tried this (among dozens of other tries - I've hit a mental block and can't figure it out):
prompt
prompt without with
prompt
select c.proj_id,
       c.proj_start,
       c.proj_end,
       c.flag,
       -- This is what I've tried as the equivalent statement but, it is
       -- syntactically incorrect. What's the correct syntax for what this
       -- statement is intended ?
        select sum(t2.flag)
          from c t2
         where t2.proj_end <= c.proj_end
       ) as proj_grp
from (
        select a.proj_id,
               a.proj_start,
               a.proj_end,
               case when (
                          select min(a.proj_start)
                            from v b
                           where (a.proj_start = b.proj_end)
                             and (a.proj_id    != b.proj_id)
                         is not null then 0 else 1
               end as flag
          from v a
         order by a.proj_start
       ) c;Thank you for helping, much appreciated.
John.
PS: The DDL for the table v used by the above statements is:
drop table v;
create table v (
proj_id         number,
proj_start      date,
proj_end        date
insert into v values
       ( 1, to_date('01-JAN-2005', 'dd-mon-yyyy'),
            to_date('02-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 2, to_date('02-JAN-2005', 'dd-mon-yyyy'),
            to_date('03-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 3, to_date('03-JAN-2005', 'dd-mon-yyyy'),
            to_date('04-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 4, to_date('04-JAN-2005', 'dd-mon-yyyy'),
            to_date('05-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 5, to_date('06-JAN-2005', 'dd-mon-yyyy'),
            to_date('07-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 6, to_date('16-JAN-2005', 'dd-mon-yyyy'),
            to_date('17-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 7, to_date('17-JAN-2005', 'dd-mon-yyyy'),
            to_date('18-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 8, to_date('18-JAN-2005', 'dd-mon-yyyy'),
            to_date('19-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       ( 9, to_date('19-JAN-2005', 'dd-mon-yyyy'),
            to_date('20-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       (10, to_date('21-JAN-2005', 'dd-mon-yyyy'),
            to_date('22-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       (11, to_date('26-JAN-2005', 'dd-mon-yyyy'),
            to_date('27-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       (12, to_date('27-JAN-2005', 'dd-mon-yyyy'),
            to_date('28-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       (13, to_date('28-JAN-2005', 'dd-mon-yyyy'),
            to_date('29-JAN-2005', 'dd-mon-yyyy'));
insert into v values
       (14, to_date('29-JAN-2005', 'dd-mon-yyyy'),
            to_date('30-JAN-2005', 'dd-mon-yyyy'));

Hi, John,
Not that you asked, but as you proabably know, analytic functions are much better at doing this kind of thing.
You may be amazed (as I continually am) by how simple and efficient these queries can be.
For example:
WITH     got_grp          AS
     SELECT     proj_id, proj_start, proj_end
     ,     proj_end - SUM (proj_end - proj_start) OVER (ORDER BY proj_start)     AS grp
     FROM     v
SELECT       ROW_NUMBER () OVER (ORDER BY grp)     AS proj_grp
,       MIN (proj_start)                         AS proj_start
,       MAX (proj_end)               AS proj_end
FROM       got_grp
GROUP BY grp
ORDER BY proj_start
;Produces the results you want:
PROJ_GRP PROJ_START PROJ_END
         1 01-Jan-2005 05-Jan-2005
         2 06-Jan-2005 07-Jan-2005
         3 16-Jan-2005 20-Jan-2005
         4 21-Jan-2005 22-Jan-2005
         5 26-Jan-2005 30-Jan-2005This is problem is an example of Neighbor-Defined Groups . You want to GROUP BY something that has 5 distinct values, to get the 5 rows above, but there's nothing in the table itself that tells you to which group each row belongs. The groups are not defined by any column in hte table, but by relationships between rows. In this case, a row is in the same group as its neighbor (the row immediatly before or after it when sorted by proj_start or proj_end) if proj_end of the earlier row is the same as proj_start of the later row. That is, there is nothing about 03-Jan-2005 that says the row with proj_id=2 is in the first group, or even that it is in the same group with its neighbor, the row with proj_id=3. Only the relation between those rows, the fact that the earlier row has end_date=03-Jan-2005 and the later row has start_date=03-Jan-2003, that says these neighbors belong to the same group.
You're figuring out when a new group starts, and then counting how many groups have already started to see to which group each row belongs. That's a prefectly natural procedural way of approaching the problem. But SQL is not a procedural language, and sometimes another approach is much more efficient. In this case, as in many others, a Constant Difference defines the groups. The difference between proj_end (or proj_start, it doesn't matter in this case) and the total duratiojn of the rows up to that date determines a group. The actual value of that difference means nothing to you or anybody else, so I used ROW_NUMBER in the query above to map those distinct values into consecutive integers 1, 2, 3, ... which are a much simpler way to identify the groups.
Note that the query above only requires one pass through the table, and only requires one sub-query. It does not need a WITH clause; you could easily make got_grp an in-line view.
If you used analytic functions (LEAD or LAG) to compute flag, and then to compute proj_grp (COUNT or SUM), you would need two sub-queries, one for each analytic function, but you would still only need one pass through the table. Also, those sub-queries could be in-line views; yiou would not need to use a WITH clause.

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Can't figure out the correct xPath for this...

Hi,
I'm using Oracle Service Bus and got into a problem with xPath.
I need to get two parameters - userId and password - from this XML.
* All I managed to do is get them with _$body//*:userId/text()_ but then I get a string that contacs both occurrences of this parameter on this XML and I only need one!
* I also tried getting the exact path using _$body/Butterfly/errorData/UserData/userId/text()_ but got nothing. When trying to add the NS (like bas:userId) It's doesn't comply with validation.
Here's my XML. I would really appreciate your help here!
<soapenv:Body xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<Butterfly xmlns="http://xml.netbeans.org/schema/Butterfly" xmlns:msgns="http: //j2ee.netbeans.org/wsdl/EquipmentController" xmlns:ns1="http://xml.netbeans.org /schema/Butterfly" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<errorData xmlns="">
<equ:UserData xmlns:equ="http://xml.netbeans.org/schema/EquipmentSchema" x="" mlns:swap="http://xml.netbeans.org/NewDetails" xmlns:bas="http://xml.netbeans.org /schema/BaseSchema">
<bas: password >1</bas:password>
<bas: userId >1</bas:userId>
<bas:FirstIssue>1</bas:FirstIssue>
</equ:UserData>
<operation>CloseArgs</operation>
<service>FinishProcess_Proxy</service>
<project>MajorProcess</project>
<request_data_xml>
<equ:NewDetailsParams xmlns:equ="http://xml.netbeans.org/schema/Equipment Schema">
<equ:UserData>
<bas: password xmlns:swap="http://xml.netbeans.org/NewDetails" xmlns:b="" as="http://xml.netbeans.org/schema/BaseSchema">1</bas:password>
<bas:FirstIssue xmlns:swap="http://xml.netbeans.org/NewDetails" xm="" lns:bas="http://xml.netbeans.org/schema/BaseSchema">1</bas:FirstIssue>
<bas: userId xmlns:swap="http://xml.netbeans.org/NewDetails" xmlns:bas="http://xml.netbeans.org/schema/BaseSchema">1</bas:userId>
</equ:UserData>
<equ:NewDetailsSetDT>
<equ:Data>
<swap:Code xmlns:swap="http://xml.netbeans.org/NewDetails">110</swap:Code>
<swap:Reason xmlns:swap="http://xml.netbeans.org/NewDetails">60</swap:Reason>
</equ:Data>
</equ:NewDetailsSetDT>
<equ:Off>1</equ:Off>
</equ:NewDetailsParams>
</request_data_xml>
</errorData>
</Butterfly>
</soapenv:Body>
Edited by: kobyssh on 03:28 04/02/2010

Hi gentleman,
you need the text of userid and username,I think you need add the namespace which contains tow parts:one is the wsdl defination namespace and the other is
the namespace which you defination just as bas:http://xml.netbeans.org /schema/BaseSchema.
by the way you can use the OSB XQuery expression which don't need to write the xpath,you can drag it from variable structrue.
Rgds,
Jacky(Yang Yi.)

How to figure out the correct screen resolution?

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I bought an iPhone from someone out of the paper and they didn't log out of their iCloud account.

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(113082)

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HT4865 So who believes Apple should be a bit more cautionary about the sharing of iMessages and other content when several members of a family share the same iCloud account and unknowing can audit each other's iMessages, Contacts, and god only knows what

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No argument from me about the vagaries of using and sharing Apple IDs. This can lead to unintended consequences, especially in a family situation.
If you're sharing the same ID for FaceTime, you might want to go to Settings>FaceTime, tap the ID, sign out, then sign in with separate IDs there too. Otherwise, you'll end up getting each other's FaceTime calls.
Also, if you need to migrate everyone's devices to separate iCloud accounts to keep your synced data separated, you can do this by saving any photo stream photos you wish to keep to your camera roll (unless already there) by opening your my photo stream album, tapping Select, tapping the photos, tap the share icon (box with upward facing arrow), then tapping Save to Camera Roll. If you are syncing notes with iCloud, you'll need to open each of your notes and email them to yourself so you can later copy and paste the text into new notes created in your new account. Then go to Settings>iCloud, tap Delete Account (which only deletes it from this device, not from iCloud), choose Keep on My iDevice and provide the password to turn off Find My iPhone. Then sign back in with a different Apple ID to create your new account and choose Merge to upload your data. Once everyone's devices are on separate accounts, you can go to icloud.com and delete each other's data from your accounts.

How to use family sharing when already sharing the same iCloud account

My wife and I started separate iTunes account many years ago, and thus made many purchases on each account. Some time later we started using iCloud, and when we did, we decided we wanted to share the same iCloud account so my wife, for example, could add entries in the Notes app and I'd be able to see them, and vise versa. In addition, we have another iPhone for our daughter, and with that she has her own iCloud account in use on her phone, however, she is signed into my iTunes account on her phone (so her/my purchases were on the same iTunes account, namely mine).
Now, years later, Family Sharing came along and I'm trying to figure out how I can also make that work with the iTunes and iCloud setup we currently have. My hope, with the Family Sharing feature, is that my wife's purchases (on her iTunes account) and my purchases on my iTunes account would be able to be shared. That said, how should I go about setting up Family Sharing such

sounds like you only need to share with the other account that your daughter used. the same id in icloud on wifes devie is fine. this article will help. Sharing purchased content with Family Sharing - Apple Support Peace, Clyde

Figuring out the correct icloud account

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