Finding 3 rd point if 2 points and and 2 distances  are given

hi guys,
i got a problem while solving a geometry problem. problem description is as follows.
i have 2 points p1(x1, y1), p2(x2, y2), and i have to find the a point p3 which is d1 distance from p1, and d2 distance form p2.
here i have to get 2 points for point p3(x3, y3) because i dont know which direction it is.
how to solve this can anybody help me please.
regards,
vemula kiran kumar.
Message was edited by:
kirankumarvemula

hi,
i tried to solve as u said.
mean while i tried in some other manner. please can u tellme whether this is correct way or not.
please see my code.
* CirclesIntersectionPoints.java
* Created on March 15, 2007, 4:25 PM
* Vemula KiranKumar,
* Associate ID - 1997.
* GeoSpace Integrated Solutions,
* Hyderabad.
package com.org.Demarcation.importcoord;
* @author Vemula KiranKumar.
import java.lang.Math;
class CalculatePoints1 {
public static void main(String[] args)      {
CirclesIntersectionPoints newPoints = new CirclesIntersectionPoints(-9, 1, 7, 5, -5, 18);
System.out.println("In the main program-x1--->"+newPoints.getX1());
System.out.println("In the main program-y1--->"+newPoints.getY1());
System.out.println("In the main program-x2--->"+newPoints.getX2());
System.out.println("In the main program-y2--->"+newPoints.getY2());
*     This class is used to find the intersection points of two circles
*     Let Circle1 have a center point A(a,b), and Circle 2 have a center point B(p,q)
* and radious of circle 1 is r1, radious of circle 2 is r2,
* intersection points of circle 1 and circle 2 are E(X1, Y1) and (X2, Y2) that have to calculated by this program.
* procedure: -
* K = (1/4)squreroot(((r1+r2)^-d^)(d^-(r1-r2)^))
*     d^ = (x2-x1)^ + (y2-y1)^
* K is the area of the triangle formed by the centers of the two circles and one of their points of intersection;
* d is the distance between the circles centers;
*     r1, r2 are the circles' radii; (x1,y1) and (x2,y2) are the circles' centers
* The two solutions, then, are
* x = (1/2)(x2+x1) + (1/2)(x2-x1)(r1^-r2^)/d^ � 2(y2-y1)K/d^
* y = (1/2)(y2+y1) + (1/2)(y2-y1)(r1^-r2^)/d^ � -2(x2-x1)K/d^
class CirclesIntersectionPoints {
/* Default Constructor */
public CirclesIntersectionPoints(){
this.a=0;
this.b=0;
this.r1=0;
this.p=0;
this.q=0;
this.r2=0;
this.X1=0;
this.Y1=0;
this.X2=0;
this.Y2=0;
/* Parameterised constructor*/
public CirclesIntersectionPoints(double x1, double y1, double d1, double x2, double y2, double d2){
setA(x1);
setB(y1);
setR1(d1);
setP(x2);
setQ(y2);
setR2(d2);
System.out.println(this.a+", "+this.b+", "+this.r1+", "+this.p+", "+this.q+", "+this.r2 +" --> Real values ");
try {
interSectionPoints(); // finding the intersection points.
} catch (Exception ex) {
ex.printStackTrace();
} // finding the intersection points.
/*----------------Given Point 1(x1, y1) distance d1-------------*/
public double getA(){
return this.a;
private void setA(double x1){
this.a = x1;
public double getB(){
return this.b;
private void setB(double y1){
this.b = y1;
public double getR1(){
return this.r1;
private void setR1(double d1){
this.r1 = d1;
/*----------------Given Point 2(x2, y2) distance d2-------------*/
public double getP(){
return this.p;
private void setP(double x2){
this.p = x2;
public double getQ(){
return this.q;
private void setQ(double y2){
this.q = y2;
public double getR2(){
return this.r2;
private void setR2(double d2){
this.r2 = d2;
/*----------------New Point (X1, Y1) -------------*/
public double getX1(){
return this.p;
private void setX1(double newx1){
this.X1 = newx1;
public double getY1(){
return this.Y1;
private void setY1(double newy1){
this.Y1 = newy1;
/*----------------New Point (X2, Y2) -------------*/
public double getX2(){
return this.X2;
private void setX2(double newx2){
this.X2 = newx2;
public double getY2(){
return this.Y2;
private void setY2(double newy2){
this.Y2 = newy2;
/*----------------end of the getter setter ----------------------*/
* finding the Intersection points.
* x = (1/2)(x2+x1) + (1/2)(x2-x1)(r1^-r2^)/d^ � 2(y2-y1)K/d^
* y = (1/2)(y2+y1) + (1/2)(y2-y1)(r1^-r2^)/d^ � -2(x2-x1)K/d^
public void interSectionPoints() {
double aa = 0, bb = 0, rr1 = 0, pp = 0, qq = 0, rr2 = 0, sqrdistance = 0, areaoftri = 0;
double partx1 = 0, partx2 = 0, partx3 = 0;
double party1 = 0, party2 = 0, party3 = 0;
double x1 = 0, x2 = 0, y1 = 0, y2 = 0;
aa = getA();
bb = getB();
rr1 = getR1();
pp = getP();
qq = getQ();
rr2 = getR2();
sqrdistance = sqrdistBetweenCenters(); // getting the distance between the centers of circles.
areaoftri = areaofTriangle(); // getting the area of triangle.
* Now Calculate the partx1, partx2, partx3 for XX1, XX2 coordnates,
* and Calculate the party1, party2, party3 for YY1, YY2 coordnates.
* _x1 = partx1 + partx2 + partx3
* _x2 = partx1 + partx2 - partx3
* _y1 = party1 + party2 + party3        
* _y2 = party1 + party2 - party3        
sqrdistance = sqrdistBetweenCenters();
areaoftri = areaofTriangle();
* finding the X coordinates.
partx1 = (pp + aa) / 2;
partx2 = ((pp - aa) * ( (Math.pow(rr1,2) ) - (Math.pow(rr2,2)) ))/ (2 * sqrdistance);
partx3 = (2 * (qq - bb) * areaoftri) / sqrdistance;
_x1 = partx1 + partx2 + partx3;
_x2 = partx1 + partx2 - partx3;
* Setting the x coordinates
setX1(_x1);
setX2(_x2);
* finding the Y coordinates.
party1 = (qq + bb) / 2;
party2 = ((qq - bb) * ( (Math.pow(rr1,2) ) - (Math.pow(rr2,2)) ))/ (2 * sqrdistance);;
party3 = -(2 * (pp - aa) * areaoftri) / sqrdistance;
_y1 = party1 + party2 + party3;
_y2 = party1 + party2 - party3;
System.out.println("*******************");
System.out.println(_y1);
System.out.println(_y2);
setY1(_y1);
setY2(_y2);
* This method will calculate the K, area of the triangle ABE.
* K = (1/4)squreroot(((r1+r2)^-d^)(d^-(r1-r2)^))
* where d is the distance between the two centers.
* (a, b) --> center of circle 1, with radii r1(given distance d1)
* (p, q) --> center of circle 2, with radii r2(given distance d2)
public double areaofTriangle(){
double areaoftri = 0;
double part1 = 0;
double part2 = 0;
double sqrdistance = 0; //distance between
double aa,bb,rr1,pp,qq,rr2;
aa = getA();
bb = getB();
rr1 = getR1();
pp = getP();
qq = getQ();
rr2 = getR2();
System.out.println(aa+", "+bb+", "+rr1+", "+pp+", "+qq+", "+rr2+" -->OK Test Passed.");
* getting the square of distance between
* centers of 2 circles.
sqrdistance= sqrdistBetweenCenters();
System.out.println("squre distance is --->"+sqrdistance+" -->OK Test Passed.");
* calculating part1, part 2 and subsitute in formula
* K = (1/4)squreroot((part1)*(part2))
part1 = Math.pow((rr1 + rr2),2)- sqrdistance;
part2 = sqrdistance - Math.pow((rr1 - rr2),2);
areaoftri = (Math.sqrt(part1*part2))/4;
System.out.println("Area of Triangle is --->"+areaoftri+" ---> Not OK not Tested Yet");
return areaoftri;
* This method calculate the squre of distance between
* the two points of the circle centers
public double sqrdistBetweenCenters(){
double sqrdistance = 0;
double aa = 0, bb = 0, pp = 0, qq = 0;
aa = getA();
bb = getB();
pp = getP();
qq = getQ();
sqrdistance = (Math.pow((pp-aa),2)) + (Math.pow((qq-bb),2));
return sqrdistance; // OK. Test Passed.(kiran)
protected String kirankumarVemula;
/* Given Point 1(x1, y1) with distance d1*/
private double a;
private double b;
private double r1;
/* Given Point 2 (x2, y2) with distance d2*/
private double p;
private double q;
private double r2;
/* Calculated Point 1 */
private double X1;
private double Y1;
/* Calculated Point 2 */
private double X2;
private double Y2;
}

Similar Messages

  • What are unicode code points and how many are there and which are surrogate

    what are unicode code points and how many are there and which are surrogate

    Hi
    see the links
    The Link will be helpful to you.
    Re: Upgrade 4.6 to ECC - What are the responsibilites
    regarding Unicode influence in Standard programs
    Very good document:
    http://www.doag.org/pub/docs/sig/sap/2004-03/Buhlinger_Maxi_Version.pdf
    https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/d37d1ad9-0b01-0010-ed9f-bc3222312dd8
    https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/589d18d9-0b01-0010-ac8a-8a22852061a2
    https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/f8e316d9-0b01-0010-8e95-829a58c1511a
    Reward points for useful Answers
    Regards
    Anji

  • Recovery points and consistency checks are failing for one disk on file server. Access is denied (0x80070005)

     Good day! I've built a new DPM 2012 R2 server and migrated or re-created jobs from my older 2012 SP1 DPM servers as trying to upgrade them was not working out. The DPM R2 server is running great besides this one issue. The problem is with a file
    and print server at a remote office. Since it has around 750 GB of user data on it I chose to do manual replica creation on the data disk, (E:) but created the C:\ drive replica normally, over the WAN. The manual replica creation was successful, and the initial
    consistency check and recovery point creation worked as expected, however, since then it will not create another RP or run a CC on the E:\ drive. Recovery points on the C:\ drive are being created properly. When I try to run a CC I get this error: "An
    unexpected error occurred while the job was running. (ID 104 Details: Access is denied (0x80070005))" I've tried to drop protection on the two directories of the E:\ drive (retaining data) and re-create, but that didn't help. I've even done a recovery
    from the initial RP to verify that it was created properly, and that worked as well.

    Hi,
    Access Denied error is usually caused by Antivirus software.  Please disable real time scanning on the DPM Server for DPMRA process. 
    928840 You receive job status failure messages in Data Protection Manager
    http://support.microsoft.com/default.aspx?scid=kb;EN-US;928840
    For DPM 2012 the path has changed.
    To resolve this problem, configure the antivirus program to exclude real-time monitoring of the Dpmra.exe program on the Data Protection Manager server. By default, the Dpmra.exe file is located in the following folder:
    %ProgramFiles%\Microsoft System Center 2012\DPM\DPM\Bin
    Please remember to click “Mark as Answer” on the post that helps you, and to click “Unmark as Answer” if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread. Regards, Mike J. [MSFT]
    This posting is provided "AS IS" with no warranties, and confers no rights.

  • [OT] Geographical points and the distance between them

    I need to solve problems on the topic of addresses and the distance between them. I understand that I first need to convert an address into a pair of longitude and latitude. After my reading so far, I can use a GIS DB to achieve this goal. That is a lot of work since the issue is only one aspect of the application development. Does anyone know any other approaches?
    Thanks.

    [http://lmgtfy.com/?q=java%2Bcode%2Bdistance%2Bbetween%2Blatitude%2Blongitude%2Bpoints]

  • Workout app and MapMyRun Distances Are Inconsistent

    I have been tracking my runs with the Workout App, and the distance/pace/calorie calculations seem to be much different from those calculated by MapMyRun (and other distance tracking devices as well). The Workout app Will consistently underestimate the distance of my run (3.5 miles versus 4 miles respectively). I was curious to see if anyone else had the same problem. I have carried my iPhone with me on all my runs.

    Same here.  Just took my watch (with phone) for first time for run this morning.  Had previously used a Garmin watch.  Ran the same course/path that consistently was always 7.0 miles on the Garmin (and verified mapping on my computer the path in Google maps).  This morning, I set watch for 7.0 mile goal to run same path.  Had to actually run 7.75 (according to Garmin watch my daughter was wearing while with me) to get to 7 miles.  Wish I could see a visual map of where the phone/watch THOUGHT I was.  So far, not happy.  I know it's not the watch.  It's the phone since that's where the GPS is coming from.  Wonder if I need to return my phone. (6+)?

  • Can I have iTunes find my missing info for my songs and albums that are already on my computer?

    I have missing info on a lot of my songs and the albums I had put them on by CD awhile ago without internet and I cant redo them because I dont have the CDs anymore. Can I have iTunes find the info for them?

    Google "TuneUp" it should be the first result. TuneUp is a paid application though, there's another application called MusicBraiz which is free, but this one is a little complicated I think. Hope that helps

  • Unloading point and Goods recipient in Purchase Requisition

    Hi,
    I have a requirement to update Good Recipient and Unloading point in Purchase requisition.
    I am using BAdI ME_PROCESS_REQ_CUST and PROCESS_ACCOUNT Method.
    in PROCESS_ACCOUNT method I am using IM_ACCOUNT_REF and GET_DATA and SET_DATA methods. and this is working fine for me.
    I need your help in resolving below problem.
    If Purchase already planned with some Materials by an individual, is now added more Materials by another individual, the system should assign the values of the Goods Recipient  and Unloading Point of the second individual to the Material items in the document. The Goods Recipient and Unloading Point values of the existing Material items in the document should remain unchanged, unless these values are specifically changed by the user editing the document or the Material number of the original item has been changed by the user, following which the Goods Recipient  and Unloading Point values of the current user should be adopted instead, overwriting the existing values.
    GET_DATA and SET_DATA methods does not have the inforamtion Material number filed.
    I have also checked GET_PERSISTANT_DATA and GET_PREVIOUS_DATA.
    Please let me know which BAdI and method i can use to cater this requirement. or any Enhancement points.
    Thanks in Advance.

    Hi,
    Reason for not getting populated these fields from PR to PO
    through ME59N or ME21N is because in general, in case of service
    environment, these are not available as explained in attached
    note 118008. Their role is taken by the so-called user fields
    since release 4.0 which are declared as text fields and play
    a purely informative role only....
    These two fields have never been included into the standard
    functionalities due to the basic business process which does not
    include these fields for service transactions/functionalities.
    The fields "unloading point" and "Goods recipient" are not available
    for services in R/3.
    >>The same functionality exists for blanket pos.<<<
    One reason for this is that the account-assignment screen is filled
    by the user on sub-item level. The system aggregates this information
    to item level. This is not possible for the unloading point and goods
    recipient, because there can be several unloading points / goods re-
    cipients for one purchase/requisition order item.
    This functionality won't be available in standard R/3.
    See also note
    633986     FAQ: Account assignment in the service
    Br
    Nadia Orlandi

  • Standard point & Shoot or more advanced Point and shoot?

    My Sony Cybershot 7.2 finally kicked the bucket. Was a great camera that endured hunting trips and everything else.  Now I need to replace it. Should I go with another standard point and shoot?  What is the advantages of a more advanced point and shoot?  you know,The ones that look like the DSLR, but aren't.
    I am specificly looking at the Sony DSC-H50, but there are other cyber-shots with more pixels that are less money, but they are the standard style.  I'm starting to feel a bit overwhelmed. 

    I'm not a big fan of the "bridge camera" category (P&S cameras shaped like a DSLR) - basically all of the disadvantages of a DSLR (size, size, and size), with few of the advantages (you're still stuck with a non-interchangeable lens and contrast detection autofocus.  Also, ultrazoom P&S lenses tend to be pretty bad.  We have some Fuji bridge cameras at work that suffer from awful barrel distortion.)
    In my opinion, "advanced point and shoot" cameras are those that have a mostly typical P&S form factor but slightly bigger with lots of advanced features.  Off the top of my head, the three main contenders are:
    Canon G10
    Panasonic LX3/Leica D-LUX4 (basically same camera, the Leica has a different name and much higher price)
    Nikon ???? (can't remember exactly which model)
    The G10 and LX3 are models that pro photographers go for when they can't carry around a DSLR.  In fact there was quite a stir of controversy when the president of Pentax USA started carrying around a D-LUX4.  (Pentax focuses on DSLRs and basic P&S cameras, not the advanced P&S market)
    *disclaimer* I am not now, nor have I ever been, an employee of Best Buy, Geek Squad, nor of any of their affiliate, parent, or subsidiary companies.

  • 2LIS_12_VCITM populates the same Shipping Point and Receiving Plant

    Hi Gurus,
    We are using 2LIS_12_VCITM extractor which answers all delivery-related requirements. However when I checked the data in RSA3, Shipping Point and Receiving Plant are the same. So I checked some sample deliveries in table LIKP and it shows the correct shipping point and receiving plant (which are different to each other). I checked VL03N and table LIKP is giving the correct shipping points and receiving plants. Receiving Plant or LIKP-WERKS and Shipping Point or LIKP-VSTEL. My question is how this happened? Consequently, when I initialized in BW, shipping point and receiving plants are the same which should not be.
    Thanks for all the help.

    The data for the 2LIS_12_VCITM is not just sourced by LIKP (Delivery Header), but by LIPS (Delivery Item) too.
    Plant, in this extractor, is sourced by LIPS-WERKS instead of LIKP-WERKS. The receiving plant is LIPS-UMWRK. If you require this data, you will have to enhance the structure and create the User Exit code in tcode CMOD to extract that particular data.

  • CTI route point and CTI ports not registering - UCCX 10.5 and CUCM 10.5 - PARTIAL SERVICE

    I'm trying to integrate CUCM 10.5 and UCCX 10.5.
    For some reason CTI route point and CTI ports are not registering on the CUCM and the status of the UCCX is "PARTIAL SERVICE".
    On the UCCX Cisco Unified CCX Engine is in status "PARTIAL SERVICE" and the Unified CM Telephony Subsystem shows status "OUT OF SERVICE".
    I tried with completely new installation of UCCX twice and got the same result twice.
    But when I tried integrating UCCX 10 with the same CUCM 10.5 from above everything works fine and all the ports are registering right away.
    In all the cases I have done the same configuration.
    The versions of CUCM is 10.5.2.10000-5.
    The version of UCCX is 10.5.1.10000-24.
    The version of UCCX 10 with which it works fine is 10.0.1.11001-37.
    Does anyone have an idea what might be the problem?

    No I haven't. Unfortunately I don't have a 32bit Excel at the moment to try.
    Can you please tell me this: I'm installing a new BE6000 system that came with this problematic version of UCCX (10.5.1.10000-24). I have been testing during the weekend with 3 versions of UCCX:
    -10.0.1.11001-37
    -10.6.1.10000-39 and
    -10.5.1.10000-24
    I got the best results with version 10.0.
    Can I install that version (10.0) in BE6000 instead of the one that came preinstalled (10.5.1)?
    This is my first BE6000 installation and I'm not sure if this is OK?
    I installed a newer version of CUCM than the one that came preinstalled because I hit bug CSCup60269 but I'm not sure If I can go to a lower version for CCX.

  • What's focus-angle and  focus-distance in CSS radial-gradients?

    Reading the reference ( http://docs.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html#typepaint ) I found these two values you can set in a radial-gradient definition:
    radial-gradient([ *focus-angle* <angle>, ]? [ *focus-distance* <percentage>, ]? [ center <point>, ]? radius [ <length> | <percentage> ] [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
    Could someone enlighten me what they mean? I wrote a little tool for visual definition of Gradients (http://88.198.17.44/blog/2012/04/13/it-works-fxexperience-tools-gradienteditor-plugin/) as an extension to FXExperience Tools, and I'd like to include it if it makes sense.
    Thanks
    Toni

    focus-angle and focus-distance are together used to determine the focal point of the radial pattern.
    See this image: http://www.webdesign.org/img_articles/6822/gradient.jpg

  • How to find a second point on a line given a point and distance

    Hi All,
    My requirement is: Given a point on a line and distance, I have to find the second point. All geometries are in LRS.
    I tried using SDO_LRS.LOCATE_PT, it is returning the second point from the start of the segment but I want to locate the point from the given start point. Kindly suggest in how to solve this.
    SQL Used:
    SELECT SDO_LRS.LOCATE_PT(a.shape, m.diminfo, 9, 0)
    FROM lrs_access_fiber a, user_sdo_geom_metadata m
    WHERE m.table_name = 'LRS_ACCESS_FIBER' AND m.column_name = 'SHAPE' AND a.unique_id = 1996;
    Regards
    Venkat

    Hi Luc,
    Thanks for the information. I have implemented this in a slightly different way like:
    1. Firstly, found the distance (Distance_a of the point selected from the start point of the segment using:
    SELECT SDO_LRS.GET_MEASURE(SDO_LRS.PROJECT_PT(a.shape, m.diminfo,MDSYS.SDO_GEOMETRY(2301, 8307, NULL, MDSYS.SDO_ELEM_INFO_ARRAY(1, 1, 1), MDSYS.SDO_ORDINATE_ARRAY(xa,ya, NULL)) ), m.diminfo ) into Distance_a FROM LRS_ACCESS_FIBER a, user_sdo_geom_metadata m WHERE m.table_name = 'LRS_ACCESS_FIBER' AND m.column_name = 'SHAPE' AND a.unique_id = Input_Fiber_Id;
    2. Then added the given distance (b) to this computed distance (Distance_a ) to get the distance of the second point (Distance_b).
    Distance_b := abs (Distance_a + b);
    3. Then used SDO_LRS.LOCATE_PT with offset=0 and distance=Distance_b to get the second point.
    select SDO_LRS.LOCATE_PT(a.shape, distance_pt, 0) into point_geometry from LRS_ACCESS_FIBER a where a.unique_id = input_fiber_id;
    Please give your inputs and feedback.
    Regards
    Venkat

  • Is there a way to change the color of the Bezier Curves and points to a different color other than black  I find it perplexing while setting points and curves working on a photo that needs to be separated from it's background for placement on transparent

    Is there a way to change the color of the Bezier Curves and points to a different color other than black  I find it perplexing while setting points and curves working on a photo that needs to be separated from it's background for placement on transparent backgrounds. Any thoughts?

    Yes. Well, sort of: instead of a "path", set the pen tool to "shape" in the tool properties. Then set the fill colour to transparent, and the stroke colour to the colour you want. You can also set the stroke width.
    Not perfect, but at least you can see the path more clearly - the anchor points and handles still remain the default colour. Open the path panel, and right-mouse click the path shape to create a selection based on that shape. The Paths panel menu also allows you to create work paths based on that shape.
    Unfortunately when you try to move the handles the black thin outline appears again until you release the mouse button.
    This is one of several things that works better in Photoline: in Photoline, once the path is set to a specific colour, editing the path uses the actual colour and stroke width. which is extremely handy for creating path based selection with awkward background colours and/or a high resolution screen. In Photoline the handles and bezier points are also much, much larger, which makes it rather simpler to work with as well - especially on a higher resolution screen. And when selected the handles and points are a clear red with a black outline - again easier to spot and identify. I just works better, in my opinion.

  • Point and Find

    For some reason, the camera never activates in this app. So I cannot "point and find"!
    It's an E63 - any ideas? Have I missed something?

    thirdwall wrote:
    Is the Point and Find application available on  the E72? I can find the download on the website for the E71 but not the E72 or are they one and the same?
    Simple answer is there is no version for the E72, and the E72 is not the same as the E71.
    The E72 is a 3rd Edition FP2 phone (aka S60 3.2) and the E71 is a 3rd Edition FP1 phone (S60 3.1). These are actually radically different platforms, at least under the hood even if they look similar to you and I.
    This is the reasoning given by the devs as to why they haven't done one for the E72, though a reply I got said they were concentrating on Touch devices (5th edition), but that doesn't explain why they did a version for the E71 and not the E72.
    I realise that cross platform compatibility within S60 is actually pretty hard, as apps have to be modified and rebuilt with the relevant SDK I think for the platform. It's frankly a mess. The situation is being resolved in later Symbian releases to make software cross platform (and in theory if they're Qt, they'd work on MeeGo too).
    Still doesn't explain why they thought developing a version for the outdated old FP1 E71 would be a good idea in preference to the new flagship FP2 E72 which would have better hardware to support it.
    Anyway, the replies I had all seem to hint that it's just not going to happen unless there's enough demand. Yet again the E72 is being neglected.
    E72-1 UK CV 052.005

  • Point and find and energy profiler for N900?

    hi are there any plans on a N900 version of point and find or energy profiler as i used them alot on my n95 i wound love to use them on my N900? many thanks
    Nokia N900 v3.2010.02-8.203.1 RX-51

    hi are there any plans on a N900 version of point and find or energy profiler as i used them alot on my n95 i wound love to use them on my N900? many thanks
    As this is a users forum you need to contact Nokia/Ovi Store  contact button top of the page .
            jje

Maybe you are looking for