Grading Program Help

Question

I'm taking a Java class and need some help with a program. I already turned it in, so I'm not looking for somebody to do the work for me. I just want to understand where I screwed up.
If the user enters 'numbers':
Get input for the grade number in decimal format. i.e. 74.22645 (enter it with 5 decimal places)
Utilize the Math class and round the number to zero decimal places, then use the int cast method (Page 82) to convert to an integer.(ensure you round it before type casting it)
Utilize a switch statement to determine the corresponding letter grade. Use the grading criteria from this course for the numbers. (ensure you accept all allowable numbers i.e. 70-79 and all in between)
Output the corresponding letter grade along with the initial number entered in decimal format utilizing the printf method and format specifiers. Output the number in only 3 decimal places.
34
if the user enters 'letters':
Get input for the grade letter in String format.
Utilize a switch statement to determine the corresponding output for the letter entered. (ensure you accept both upper and lower case letters.
Use the grading criteria from this course for the numbers. (you must use charAt( ) so the string will work with your switch)
Output the corresponding numbers values for the letter entered along with the letter initially entered.
import java.util.Scanner;
public class EdwardsToddProg4
public static void main(String[] args)
Scanner stdIn = new Scanner(System.in);
int choice;
double numberGrade;
int numericGrade;
String letterGrade;
System.out.println("Welcome to Todd’s Grading Program");
System.out.println("Enter 1 for number grades and 2 for letter grades.");
int selection = choice.charAt(0);
while (selection==1)
System.out.println("Enter a number grade in the following format, 88.12345");
//numberGrade += stdIn.nextLine ();
numberGrade = Math.round(numberGrade);
numericGrade = (int) (numberGrade);
switch (numericGrade)
case 1:
if (numericGrade >=90 && numericGrade <=100);
System.out.printf("\n You got an A because your grade is: %.2f \n",numberGrade);
break;
case 2:
if (numericGrade >=80 && numericGrade <=89);
System.out.printf("\n You got an B because your grade is: %.2f \n", numberGrade);
break;
case 3:
if (numericGrade >=70 && numericGrade <=79);
System.out.printf("\n You got an C because your grade is: %.2f \n",numberGrade);
break;
case 4:
if (numericGrade >=60 && numericGrade <=69);
System.out.printf("\n You got an D because your grade is: %.2f \n",numberGrade);
break;
case 5:
if (numericGrade <=59);
System.out.printf("\n You got an F because your grade is: %.2f \n",numberGrade);
break;
while (selection==2)
     System.out.println("Please enter your letter grade.");
     letterGrade += stdIn.nextLine ();
     switch (letterGrade)
          case A:
               System.out.println("90-100 =" +"A".equalsIgnoreCase("a"));
               break;
          case B:
               System.out.println("80-89.9 =" +"B".equalsIgnoreCase("b"));
               break;
          case C:
               System.out.println("70-79.9 =" +"C".equalsIgnoreCase("c"));
               break;
          case D:
               System.out.println("60-69.9 =" +"D".equalsIgnoreCase("d"));
               break;
          case F:
               System.out.println("0-59.9 =" +"F".equalsIgnoreCase("f"));
               break;
}

Answer 1

Okay, so I went back in and updated my program.
I got rid of int selection=choice.charAt(0); now i just have System.out.println("Enter 1 for number grades and 2 for letter grades.");
I updated my while statements to: while (choice==1) and while (choice==2)
the only errors i am getting now revolve around entering lettergrades: here's what i have.
while (choice==2) //changed selection to choice
     System.out.println("Please enter your letter grade.");
letterGrade.charAt(0);
switch (letterGrade) //changed to grade
          case A:
               System.out.println("90-100 =" +"A".equalsIgnoreCase("a"));
               break;
I'm still getting an error that says it's looking for an int in switch(letterGrade) statement and I'm not sure why...why does the switch need and int?
Also still getting beat up on my cases. I guess I thought that's what the charAt(0) would give me. if the user enters an A then case A applies. I'm guessing I thought wrong????