Group by in update and index

Hi All,
I was trying to run an update SQL statement as follows:
update tableA a set a.foo =
(select b.foo
from another_schema.tableB b
where b.bar = a.bar
group by b.bar,b.foo);
I have an index in tableA on the bar column (it is a number(10,0) type column), also in tableB there
are no more then 3 rows per unique bar column value. The update was taking more then 10 minutes (tableA has around 208K rows and tableB around 212K rows). I went into Enterprise Manager and looked at the performance analysis and run the Oracle advisor that recommended to create an index on tableB containing two segments bar,foo. I added this index and the update took 13 seconds. Why did this index help if oracle does the join first it only has to group up to 3 rows at a time also notice the there are only around 1000 joined rows where such case happens. Can someone explain this ?
thanks
Tal

Why do you use "group by" when you don't use an aggregate-function ?

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user9356129 wrote:
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What i am trying to understand is whether the index is recalculated as soon as oracle sees the change?
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Will it be generated if i am updating column2 ( with non-unique index) ?In this case not only table-blocks will be changed to reflect your update, but also index-blocks (that hold B-tree information) will be changed (in memory).
>
What i am interested to know is how transactions boundaries impact the calculation of index. Will oracle always generate transactional entries and recalculate affected indexes even before the transaction is committed and the data change is made permanent ?Yes (to the part following 'and' of the latter sentence. I don't know what you mean by "transactional entries").
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Group by in update and index

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