Help? can't see the problem
Hi folks
I know that there is a "bug" in the attached code, but I
just don't see it. There is NO validation taking place. I can put
this page up and hit the submit button with NO DATA in the filed,
and it is accepted. I wanted to used the mask="AAAAAAAAA" or
pattern=[A-Za-z] with validate="noblanks, regex", but again...There
is SOMETHING wrong in the code (probably the <CFINPUT> area,
but again...don't see it.
Can some of you please look with fresher eyes (and a more
open mind) and see if you can see this error?
Many Thanks
Hi Dan,
thanks for the input. I have tried changing the validateat to
all three accepted methods, and get the same result. (and I did try
that again this morning just after reading your message). Still no
luck. It's bizarre!
Thanks again.
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i'm trying to write a simple image viewer application.
Can you see the problem. i can't. i'll appreciate any advice or help?
import java.awt.*;
import java.awt.image.*;
import java.awt.event.*;
import java.io.*;
public class SimpleViewer extends Frame {
protected Image awtImage;
public void loadAndDisplay(String filename) {
Image img = readImage(filename);
awtImage = img;
int width = img.getWidth(this);
int height = img.getHeight(this);
displayImage(img, width, height);
public void displayImage(Image img, int width, int height) {
addWindowListener(
new WindowAdapter() {
public void windowClosing(WindowEvent e){
System.exit(0);
setTitle("Simple Viewer ");
pack();
setSize(new Dimension(width, height));
show();
repaint();
public image readImage(String filename) {
Image image = Toolkit.getDefaultToolkit().getImage(imageName);
MediaTracker imageTracker = new MediaTracker(this);
imageTracker.addImage(image, 0);
try{
imageTracker.waitForID(0);
}catch(InterruptedException e){ return null;}
return image;
public void paint(Graphics g){
Rectangle rect = this.getBounds();
if(awtImage != null) {
g.drawImage(awtImage, 0,0,rect.width, rect.height, this);
public static void main(String[] args){
SimpleViewer ip = new SimpleViewer();
if(args.length <1) {
System.out.println("Enter a valid image file name");
System.exit(0);
ip.loadAndDisplay(args[0]);
}check this line and tell me what you see... after all, it's the source of your compiler errors...
public image readImage(String filename) {
Image image = Toolkit.getDefaultToolkit().getImage(imageName);once you figure that out, it will work...
( hint : check variable names and capitalization of names )
- MaxxDmg...
- ' He who never sleeps... ' -
HELP Can you see the missing parenthesis ?!
Dear People,
I am doing a simple program that creates a ContactBook and allows keyboard entry of lastName, telephoneNumber and emailAddress.
I have a few error messages that say parenthesis missing but I don't
see any missing ! :
"Note.java": Error #: 200 : '{' expected at line 15
"Note.java": Error #: 200 : '}' expected at line 59
"TryContactBook.java": Error #: 200 : ')' expected at line 30
"TryContactBook.java": Error #: 200 : ')' expected at line 42
below is the coding
thank you in advance
Stan
import java.util.*;
public class TryContactBook
private Note note;
public static void main(String[] args)
ContactBook myContactBook = new ContactBook();
FormattedInput input = new FormattedInput();
Note note = new Note();
System.out.println("Enter the number of new notes you wish to record ");
int numberOfNotes = input.readInt();
System.out.println("Ready to record " + numberOfNotes + "note(s) ");
for (int i = 0; i < numberOfNotes; i++)
try
System.out.print("Enter a last name: ");
note.setLastNaame(input.readString());
System.out.println("last name input is: " + notes.getLastName());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException thrown when inputting last name. \n" +
e.getMessage());
try
System.out.println("Enter a telephone number ");
note.setTelephoneNumber(input.readString();
System.out.println("telephone number input is: " + notes.getTelephoneNumber());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException thrown when inputting last name. \n" +
e.getMessage());
try
System.out.println("Enter an e-mail address ");
note.setTelephoneNumber(input.readString();
System.out.println("e-mail address input is: " + notes.getEmailAddress());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException thrown when inputting last name. \n" +
e.getMessage());
=====================================================================
import java.util.*;
* A class to maintain an arbitrarily long list of contacts.
* Notes are numbered for external reference by a human user.
* In this version, note numbers start at 0.
* @author Stan Dominski
public class ContactBook
// Storage for an arbitrary number of notes.
private ArrayList notes;
* Perform any initialization that is required for the
* notebook.
public ContactBook()
notes = new ArrayList();
* Store a new note into the notebook.
* @param note The note to be stored.
public void storeNote(String note)
notes.add(note);
* @return The number of notes currently in the notebook.
public int numberOfNotes()
return notes.size();
* Show a note.
* @param noteNumber The number of the note to be shown.
public void showNote(int noteNumber)
if(noteNumber < 0 || noteNumber > numberOfNotes())
// This is not a valid note number, so do nothing.
else
// This is a valid note number, so we can print it.
System.out.println(notes.get(noteNumber));
* Remove a note from the notebook if it exists.
* @param noteNumber The number of the note to be removed.
public void removeNote(int noteNumber)
if(noteNumber < 0 || noteNumber > numberOfNotes())
System.out.println("noteNumber is not valid.");
else
notes.remove(noteNumber);
* List all the notes in the notebook
public void listNotes()
Iterator i = notes.iterator();
Iterator myIterator = notes.iterator();
while(i.hasNext() && myIterator.hasNext())
System.out.print(notes.indexOf(i.next() ) + ":" );
System.out.println("" + myIterator.next());
=======================================================================
import java.util.*;
public class Note
private ArrayList contactInfo;
private String lastName;
private String telephoneNumber;
private String emailAddress;
public class Note()
contactInfo = new ArrayList();
this.lastName = lastName;
this.telephoneNumber = telephoneNumber;
this.emailAddress = emailAddress;
public void setLastName(String lastName)
this.lastName = lastName;
public String getLastName()
return lastName;
public void setTelephoneNumber(String telephoneNumber)
this.telephoneNumnber = telephoneNumber;
public String getTelephoneNumber()
return telephoneNumber;
public void setEmailAddress(String emailAddress)
this.emailAddress = emailAddress;
public String getEmailAddress()
return emailAddress;
======================================================================
import java.io.*;
import java.util.*;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class FormattedInput
public String readString() throws InvalidUserInputException
if(readToken() == tokenizer.TT_WORD || ttype == '\"' || ttype == '\'')
return tokenizer.sval;
else
throw new InvalidUserInputException(" readString() failed. ..... Input data is not a string");
// Method to read an int value
public int readInt() throws InvalidUserInputException
if (readToken() != tokenizer.TT_NUMBER)
throw new InvalidUserInputException(" readInt() failed. " + " input data not numeric");
else
return (int)tokenizer.nval; // value is numeric so return as int
//helper method to read the next token
private int readToken()
try
ttype = tokenizer.nextToken();
return ttype;
catch(IOException e)
e.printStackTrace(System.err);
System.exit(1);
return 0;
//object to tokenize input from the standard input stream
private StreamTokenizer tokenizer = new StreamTokenizer(
new BufferedReader(
new InputStreamReader(System.in)));
private int ttype; //stores the token type code
======================================================================
import java.io.StreamTokenizer;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.BufferedReader;
public class InvalidUserInputException extends Exception
public InvalidUserInputException() { }
public InvalidUserInputException(String message)
super(message);I have out comments on the errors I found. There might be more.
I couldn't get the indentation to work so it will look a bit funny.
//David
"Note.java": Error #: 200 : '{' expected at line 15
"Note.java": Error #: 200 : '}' expected at line 59
"TryContactBook.java": Error #: 200 : ')' expected at
line 30
"TryContactBook.java": Error #: 200 : ')' expected at
line 42
import java.util.*;
public class TryContactBook
private Note note;
public static void main(String[] args)
ContactBook myContactBook = new ContactBook();
FormattedInput input = new FormattedInput();
Note note = new Note();
System.out.println("Enter the number of new notes you wish to record ");
int numberOfNotes = input.readInt();
System.out.println("Ready to record " + numberOfNotes + "note(s) ");
for (int i = 0; i < numberOfNotes; i++)
try
System.out.print("Enter a last name: ");
note.setLastNaame(input.readString());
System.out.println("last name input is: " +
is: " + notes.getLastName());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException
xception thrown when inputting last name. \n" +
e.getMessage());
try
System.out.println("Enter a telephone
telephone number ");
note.setTelephoneNumber(input.readString()); // 1 error
System.out.println("telephone number input
er input is: " + notes.getTelephoneNumber());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException
xception thrown when inputting last name. \n" +
e.getMessage());
try
System.out.println("Enter an e-mail address
l address ");
note.setTelephoneNumber(input.readString()); // 2 error
System.out.println("e-mail address input
ss input is: " + notes.getEmailAddress());
catch (InvalidUserInputException e)
System.out.println("InvalidUserInputException
xception thrown when inputting last name. \n" +
e.getMessage());
=======================================================
=============
import java.util.*;
* A class to maintain an arbitrarily long list of
contacts.
* Notes are numbered for external reference by a human
user.
* In this version, note numbers start at 0.
* @author Stan Dominski
public class ContactBook
// Storage for an arbitrary number of notes.
private ArrayList notes;
* Perform any initialization that is required for
for the
* notebook.
public ContactBook()
notes = new ArrayList();
* Store a new note into the notebook.
* @param note The note to be stored.
public void storeNote(String note)
notes.add(note);
* @return The number of notes currently in the
the notebook.
public int numberOfNotes()
return notes.size();
* Show a note.
* @param noteNumber The number of the note to be
o be shown.
public void showNote(int noteNumber)
if(noteNumber < 0 || noteNumber >
umber > numberOfNotes())
// This is not a valid note number, so do
mber, so do nothing.
else
// This is a valid note number, so we can
, so we can print it.
System.out.println(notes.get(noteNumber));
* Remove a note from the notebook if it exists.
* @param noteNumber The number of the note to be
o be removed.
public void removeNote(int noteNumber)
if(noteNumber < 0 || noteNumber >
mber > numberOfNotes())
System.out.println("noteNumber is not
is not valid.");
else
notes.remove(noteNumber);
* List all the notes in the notebook
public void listNotes()
Iterator i = notes.iterator();
Iterator myIterator = notes.iterator();
while(i.hasNext() && myIterator.hasNext())
System.out.print(notes.indexOf(i.next() )
f(i.next() ) + ":" );
System.out.println("" +
println("" + myIterator.next());
=======================================================
===============
import java.util.*;
public class Note
private ArrayList contactInfo;
private String lastName;
private String telephoneNumber;
private String emailAddress;
public class Note()
contactInfo = new ArrayList();
this.lastName = lastName;
this.telephoneNumber = telephoneNumber;
this.emailAddress = emailAddress;
public void setLastName(String lastName)
this.lastName = lastName;
public String getLastName()
return lastName;
public void setTelephoneNumber(String
neNumber(String telephoneNumber)
this.telephoneNumnber =
telephoneNumnber = telephoneNumber;
public String getTelephoneNumber()
return telephoneNumber;
public void setEmailAddress(String
lAddress(String emailAddress)
this.emailAddress = emailAddress;
public String getEmailAddress()
return emailAddress;
}} // 3 error
=======================================================
==============
import java.io.*;
import java.util.*;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class FormattedInput
public String readString() throws
rows InvalidUserInputException
if(readToken() == tokenizer.TT_WORD || ttype ==
ype == '\"' || ttype == '\'')
return tokenizer.sval;
else
throw new InvalidUserInputException("
eption(" readString() failed. ..... Input data is not
a string");
// Method to read an int value
public int readInt() throws
InvalidUserInputException
if (readToken() != tokenizer.TT_NUMBER)
throw new InvalidUserInputException(" readInt()
nt() failed. " + " input data not numeric");
else
return (int)tokenizer.nval; // value is numeric
eric so return as int
//helper method to read the next token
private int readToken()
try
ttype = tokenizer.nextToken();
return ttype;
catch(IOException e)
e.printStackTrace(System.err);
System.exit(1);
return 0;
//object to tokenize input from the standard
andard input stream
private StreamTokenizer tokenizer = new
= new StreamTokenizer(
new
new
new
new BufferedReader(
new
new
new
new
new
new
new
new InputStreamReader(System.in)));
private int ttype; //stores
stores the token type code
=======================================================
==============
import java.io.StreamTokenizer;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.BufferedReader;
public class InvalidUserInputException extends
Exception
public InvalidUserInputException() { }
public InvalidUserInputException(String
tring message)
super(message); -
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Hello ,
I am facing a very old school kind of problem .....about spool file ....
The scenario -
I have made a script by name DB_Status_checkup.sql which i want to fire on the database to check the database status. In this script their are many queries regarding the data dictionary views to know about the database. It consist of nearly 25-30 different select queries..
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ORACLE 10g R2
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Thanks in advance ...Why don't you just use database control, instead of re-inventing the wheel?
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Sybrand Bakker
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