How to break this by month

Question

Hi,
please help me out from this problem.
I need to generate a query group by day for every month i have to show the total.
item_name sum(amt),start_date Total Amount
x 10000 01/01/2005
x 10005 01/02/2005
x 12348 01/31/2005 5999344(some of those 31 days amt appx).
x 23444 02/01/2005
x 12232 02/28/2005 3434344(appx)
like this i have to show for every month. Here I'm giving actual query.
SELECT c . sttl_item_nme ,
sum(a . sttl_amt)amt,a.start_dt_gmt
FROM nm_settlement a ,
nm_sttl_item_dtl b ,
nm_sttl_item_dtl_type c,
nm_sttl_component sc,
nm_xp xp
WHERE a . sttl_id = b . sttl_id
AND b . sttl_item_num = c . sttl_item_num
AND xP.xp_id = sc.xp_id
AND a.sttl_id = sc.sttl_id
AND a . ptcpt_cd = 'DEMO'
and xp. XP_NME ='DECO.BLRVR1'
AND a . start_dt_gmt > '04/01/2005'
AND A . end_dt_gmt < '04/30/2005'
AND c . sttl_item_nme = 'RT Uninstructed Deviation Amount'
group by a.start_dt_gmt,c.sttl_item_nme
order by a.start_dt_gmt
Thanks & Regards,
Ramana.

Answer 1

Hi Ramana,
I give you this example, please change this according to your code.
HTH
Ghulam
select ename, hiredate, sal, sum(sal) over (partition by to_char(hiredate, 'MM-YY') order by hiredate) monthly_total
  from emp
order by hiredate;
ENAME      HIREDATE          SAL MONTHLY_TOTAL
SMITH      17-12-1980        800           800
ALLEN      20-02-1981       1600          1600
WARD       22-02-1981       1250          2850
JONES      02-04-1981       2975          2975
BLAKE      01-05-1981       2850          2850
CLARK      09-06-1981       2450          2450
TURNER     08-09-1981       1500          1500
MARTIN     28-09-1981       1250          2750
KING       17-11-1981       5000          5000
JAMES      03-12-1981        950          3950
FORD       03-12-1981       3000          3950
MILLER     23-01-1982       1300          1300
SCOTT      09-12-1982       3000          3000
ADAMS      12-01-1983       1100          1100
14 rows selected.