How to build a new Lightroom Catalogue from a RAID recovery

Recently my 9TB Raid 5 server catalogue was corrupted and the drive were put through an extensive RAID recovery. I will b recieving 4TB of the 9 back with CR2, TIFF, .mov and JPEG files. We are not sure if all the data is in these files. What is the most efficient way to create a new catalogue with all the complete files? Is there another program to analyze the files before beginning in LIghtroom?
Thanks
Tom

Do you have a backup of the catalog file? That's the best way to restore things.

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I agree with Mr. Hall that using mx.controls.Alert in Flex may be a better route.
Show the Alert like this:
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How do I move Lightroom to a new computer? | The Lightroom Queen
How do I move my catalog, photos and other Lightroom files to a new computer? - The Lightroom Queen Help Desk & Members …

How to build a cluster array dynamically from another cluster array?

I'm working on a problem where I seem to be getting lost in a sea of
possibilities, none of which strikes me as optimum. Here's what I need to do.
I've got an input array of clusters (ARR1). Each cluster contains the
following components: an integer (INT1), a ring variable (RING1), a boolean
(BOOL1) and a cluster which itself is simply a bunch of ring variables
(CLUST1) Now, I need to transform that into a set of clusters (CLUST3) each of
which contains an array of characters (CHARARY2), a copy of the ring variable
(RING2), a copy of the boolean variable (BOOL2) and a copy of the cluster
(CLUST2).
To build the CLUST3, I need to find all elements within ARR1 that have the
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So if I had the following array to start with:
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0 3 1 F {Values1}
1 2 1 T {Values2}
2 4 0 F {Values1}
3 6 0 F {Values3}
4 1 2 T {Values2}
5 4 2 T {Values2}
6 3 0 T {Values3}
7 4 2 T {Values3}
I should end up with the following clusters:
CHARARY2 RING2 BOOL1 CLUST1
"3" 1 F Don't care
"2" 1 T {Values2}
"4","6" 0 F Don't care
"1","4" 2 T {Values2}
"3" 0 T {Values3}
"4" 2 T {Values3}
What methods would you suggest for accomplishing this easily and efficiently?
Alex Rast
[email protected]
[email protected]

Tedious but not conceptually difficult.
ARR1 goes into a for loop, auto indexed on the FOR loop. The for loop has a
shift register which will be used to build the output array. Nested within
the for loop is another for loop, which the shift register array goes into,
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The inner loop compares the current element of ARR1 with the output array
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input by your criteria, then the boolean register is set false; otherwise it
is left alone.
After the nested FOR loop you have a case fed from the boolean shift
register; if the boolean is true, the new element is unique and should be
added to the array. If it is false then a previous element has been found
making the present one redundant, and the array should be passed through
without adding the element.
In the true case, you simply unbundle the original element into its
components and build the new element, using "build array".
Notes for if the above is easy for you;
1) if handling lots of data then pre-initialise the shift register of your
outer loop with the same number of elements as your input array. Use
"Replace Array Subset" instead of "Build Array" to insert the current
element into the pre-allocated memory rather than having to create a new
array and copy all the current data across, which is what "Build Array" is
doing. Use "Array Subset" at the end to obtain a new array containing just
the elements you've used, removing the unused ones at the end.
2) Again for large datasets- the use of a while loop instead of the inner
for loop is more efficient since you can halt the while loop as soon as a
duplicate is found. With the described approach you have to go through the
whole array even if the first element turns out to be a duplicate- much
wasted computer time.
Alex Rast wrote in message
news:[email protected]...
> I'm working on a problem where I seem to be getting lost in a sea of
> possibilities, none of which strikes me as optimum. Here's what I need to
do.
>
> I've got an input array of clusters (ARR1). Each cluster contains the
> following components: an integer (INT1), a ring variable (RING1), a
boolean
> (BOOL1) and a cluster which itself is simply a bunch of ring variables
> (CLUST1) Now, I need to transform that into a set of clusters (CLUST3)
each of
> which contains an array of characters (CHARARY2), a copy of the ring
variable
> (RING2), a copy of the boolean variable (BOOL2) and a copy of the cluster
> (CLUST2).
>
> To build the CLUST3, I need to find all elements within ARR1 that have the
> same unique combination of RING1 and BOOL1, and if BOOL1 is True, then
RING1
> in addition, build an array of all the INT1 values corresponding to each
> unique combination above converted to character, and then bundle this
array
> plus the unique combination of the other variables into a new cluster. In
> general I could have several such clusters.
>
> So if I had the following array to start with:
>
> Index INT1 RING1 BOOL1 CLUST1
> ---------------------------------------------------
> 0 3 1 F {Values1}
> 1 2 1 T {Values2}
> 2 4 0 F {Values1}
> 3 6 0 F {Values3}
> 4 1 2 T {Values2}
> 5 4 2 T {Values2}
> 6 3 0 T {Values3}
> 7 4 2 T {Values3}
>
> I should end up with the following clusters:
>
> CHARARY2 RING2 BOOL1 CLUST1
> -----------------------------------------------------
> "3" 1 F Don't care
> "2" 1 T {Values2}
> "4","6" 0 F Don't care
> "1","4" 2 T {Values2}
> "3" 0 T {Values3}
> "4" 2 T {Values3}
>
> What methods would you suggest for accomplishing this easily and
efficiently?
>
> Alex Rast
> [email protected]
> [email protected]

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thanx
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Kumar Allamraju <[email protected]> wrote:
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Francesco wrote:
Hi all,
I'd need to build additional Weblogic Servers,
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How to build a new Lightroom Catalogue from a RAID recovery

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