How to Ensure Symbol State Persists?

Question

Okay, so I have a symbol that I want to show/hide; it's a named MovieClip with two labelled frames ("show" and "hide" in that order), the default is to be shown, and both frames have a stop() command.
This seems fine however at one point in my animation I trigger the symbol to hide via foo.gotoAndStop("hide"), but when the animation loops the symbol reappears (or rather, returns to the "show" frame).
Now, obviously this is annoying, but other symbols that function in the exact same way appear to be working as expected, so I'm at a complete loss as to why this one symbol in particular seems to be resetting? Is there some characteristic of the animation that might be causing Flash to see the symbol as if it were a new instance? I've checked that the symbol's name is constant throughout the animation, and I'm really only using classic tweens; certainly nothing that stands out as different in way compared to the other, working symbols.
Aside from completely re-creating the animation for that symbol I'm not sure what else I can try, so any suggestions are welcomed!

Answer 1

Okay, I'm going to try to highlight what I'm seeing by taking a snapshot of the timeline where the problem occurs:
The selected layer has the problem symbol, the layer immediately above is the mask layer. The blue circle indicates the frame at which the symbol is hidden (or shown) by a script further up in the timeline. The symbol displays as expected for the duration of the blue tween. At the green circle, a new tween begins but the symbol remains unchanged, continuing to be shown or hidden as expected for the during of that tween. The red circle however is where the symbol apparently resets to the default (showing) frame, and loses any other state assigned to it (e.g - if I were to set a variable upon it such as foo.bar = "foobar").
Why would the symbol retain state through the green circle, but not the red one? It seems that at the green circle the symbol is still the same instance, but at the red circle it is not, even though nothing seems to be happening any differently.