How to find a column by sampling data?

Can any one help me to identify the columns
which are ssn by sampling the data in the database or to run a query/script against each table so that the result
will tell you that the data in a a particular column seems to be a ssn ?[I have identified the columns in tables
which has ssn as there column names]. Please help...

You can use regexp to check the rows.
select ssn from some_table
where regexp_like(ssn,'^[0-9]{3}-[0-9]{3}-[0-9]{4}$')
OR
with ssns as
        ( select '123-254-5455' ssn from dual
union all select '.23-254-5455' ssn from dual
union all select '1232545455' ssn from dual
union all select '12a2545455' ssn from dual
union all select '1x3-s54-5455' ssn from dual
union all select '123-254-54552' ssn from dual
union all select '0123-254-5552' ssn from dual
select ssn ,regexp_replace(ssn,'^[0-9]{3}[-][0-9]{3}[-][0-9]{4}$','VALID') xc
from ssns
SSN           XC
123-254-5455 VALID
.23-254-5455 .23-254-5455
1232545455    1232545455
12a2545455    12a2545455
1x3-s54-5455 1x3-s54-5455
123-254-54552 123-254-54552
0123-254-5552 0123-254-5552You can check how many valid ssn's are in a column
SS
Edited by: Sänjay on Jun 25, 2009 9:34 AM
Added my example cases

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