How to get Cube and Dimension ID from SSAS Database programatically

Question

Hi All,
I am processing one SSAS cube from SSIS package and processing the cubes dynamically .For this am putting the Cube ID ,Cube name, Dimension ID, Dimension Name in a table and generating the XML programmatically.
 I can right click the properties of the dimension and cube and will get the ID information. But is there any way we can get the ID information programmatically .So that On the fly I will get the information and create the XML without storing
the these information in table.
We are using 2008 R2
Thanks in advance
Roshan

Answer 1

Hi,
Here is the C# code you want. Try it and see.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using AMO = Microsoft.AnalysisServices;
namespace ConsoleApplication4
class Program
static void Main(string[] args)
AMO.Server oServer = new AMO.Server();
oServer.Connect(@"Provider=MSOLAP.5;Integrated Security=SSPI;Persist Security Info=False;Initial Catalog=AdventureWorksDW;Data Source=DEVWKS6\MSSQLSERVERMDX");
foreach (AMO.Database db in oServer.Databases)
foreach (AMO.Cube cube in db.Cubes)
Console.WriteLine(System.String.Format("Cube Name : {0} Cube ID : {1}", cube.Name, cube.ID));
foreach (AMO.CubeDimension dim in cube.Dimensions)
Console.WriteLine(System.String.Format("Dimension Name : {0} Dimension ID : {1}", dim.Name, dim.ID));
System.Console.WriteLine("");
System.Console.WriteLine("");
oServer.Disconnect(true);
oServer.Dispose();
System.Console.ReadLine();
If you know your target SSAS Database Name, then you could use LINQ to narrow your search. Take a look into the following Code.
AMO.Database db = oServer.Databases.Cast<AMO.Database>().Where<AMO.Database>(SSASdb => SSASdb.Name == "AdventureWorksDW").FirstOrDefault();
foreach (AMO.Cube cube in db.Cubes)
Console.WriteLine(System.String.Format("Cube Name : {0} Cube ID : {1}", cube.Name, cube.ID));
foreach (AMO.CubeDimension dim in cube.Dimensions)
Console.WriteLine(System.String.Format("Dimension Name : {0} Dimension ID : {1}", dim.Name, dim.ID));
System.Console.WriteLine("");
Best Regards...
Chandima Lakmal Fonseka