How to split a string around "." expression

Question

My code is:
public String removeExtn(String resource){
          String[] splittedName = resource.split(".");
System.out.println("LENGHT IS: "+ splittedName.length);
          if(splittedName.length >= 3)
               resource = splittedName[0]+ "." + splittedName[1];
          return resourceName;
     * @param args
     public static void main(String[] args) {
          Test obj = new Test();          
          System.out.println(obj.removeExtn("myfile.xml.sample"));
But it doesn't split the string around "." and given the arraylength 0. But if I try to use any another character (e.g. "," or ";") it works perfectly fine.
Please help me.
Thanks in advance.
Mansi

Answer 1

Hi mansi,
I had a same kind of problem a few days back.
What I learned was the split() method has a string expression in it, which is usually noted as regex .
'Regex' is just a short form for 'regular expression'
You may directly use the string variable you would split around in some cases or may want to use a '\\' before some of the characters.
I can't place whole information here .So, let me give you that sun site link I read it from.
This link deals with the whole string class.
You may want to ctrl+F and split to read on split method.
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.htmlThis link talks about the regular expressions
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html#sumI got his for you from that link :
\p{Punct} Punctuation: For One of !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ This is for your knowledge.
And if you want a quick fix just for your code...
that'ld be using a
split(\p{.}) in place where u used a split(.)I have not tried that ...but u may want to!
Hope that helps.
Message was edited by:
Kishorei20
Message was edited by:
Kishorei20