Index and partition not visible !!!

Question

Hello,
I am creation a table with partition by range and primary key constraint like
CREATE TABLE employees
(employee_id NUMBER(4) NOT NULL,
last_name VARCHAR2(10),
department_id NUMBER(2),
CONSTRAINT SUP_EMP_PK
PRIMARY KEY
(employee_id,department_id)
PARTITION BY RANGE (department_id)
(PARTITION employees_part1 VALUES LESS THAN (10) TABLESPACE DATA_003_P001_HUB3);
but when I query the user_ind_partitions as
select * from user_ind_partitions where partition_name='employee_part1';
it returns nothing
Why is this problem coming up?
Help..
Regards
Abhinav

Answer 1

Actually the problem statement is:
I have table as :
CREATE TABLE SUPERVISION_BPS
ID NUMBER NOT NULL,
servicetype NUMBER NOT NULL,
type VARCHAR2(6 BYTE) NOT NULL,
insertDate DATE NOT NULL,
filename VARCHAR2(100 BYTE) NOT NULL,
numberOK NUMBER NOT NULL,
numberKO NUMBER NOT NULL,
numberCRE NUMBER NOT NULL,
numberUPD NUMBER NOT NULL,
numberDEL NUMBER NOT NULL,
CONSTRAINT SUP_BPS_PK
PRIMARY KEY
(ID, servicetype, type)
using index local
TABLESPACE DATA_003_P001_HUB3
PARTITION BY RANGE (InsertDate)
PARTITION "PARTITION_LAST" VALUES LESS THAN (MAXVALUE)
create sequence seq_sup_bps start with 1 increment by 1;
The problem is whenever I am deleting a partition as
alter table &1 drop partition &2;
and rebuilding the partition as:
alter index &1 parallel;
alter index &1 rebuild partition &2 compute statistics;
alter index &1 noparallel;
based on unused indexes
select user_ind_partitions.index_name || '|' || user_ind_partitions.partition_name
from user_indexes, user_ind_partitions
where user_indexes.index_name=user_ind_partitions.index_name
and user_ind_partitions.status='UNUSABLE'
and upper(user_indexes.table_name)='&2';
Now when the entry for the same primary key takes place, it gives an error putting the same value again.
Kindly help
Tried all bit have not found the solution.
Note: have tried removing UNUSABLE check but how to get it done as per the need.
Regards
Abhinav
Edited by: user8744860 on Jul 2, 2012 2:35 AM