IRQxx is being shared by drivers with different interrupt levels

Hi
Oracle Solaris 10 8/11 s10x_u10wos_17b X86
HP DL380 G5
We have some messages in /var/adm/messages:
Oct 24 07:39:15 phssmb0a unix: [ID 954099 kern.info] NOTICE: IRQ17 is being shared by drivers with different interrupt levels.
Oct 24 07:39:40 phssmb0a unix: [ID 954099 kern.info] NOTICE: IRQ16 is being shared by drivers with different interrupt levels.
This may result in reduced system performance
echo ::interrupts -d | mdb -k
IRQ Vect IPL Bus Trg Type CPU Share APIC/INT# Driver Name(s)
1 0x40 5 ISA Edg Fixed 3 1 0x0/0x1 i8042#0
3 0xb1 12 ISA Edg Fixed 6 1 0x0/0x3 asy#1
4 0xb0 12 ISA Edg Fixed 5 1 0x0/0x4 asy#0
9 0x81 9 PCI Lvl Fixed 1 1 0x0/0x9 acpi_wrapper_isr
12 0x41 5 ISA Edg Fixed 4 1 0x0/0xc i8042#0
14 0x46 5 ISA Edg Fixed 2 1 0x0/0xe ata#0
16 0x84 9 PCI Lvl Fixed 7 2 0x0/0x10 ehci#0, uhci#0
17 0x85 9 PCI Lvl Fixed 0 1 0x0/0x11 uhci#1
18 0x86 9 PCI Lvl Fixed 3 2 0x0/0x12 uhci#2, cpqary3#0
19 0x87 9 PCI Lvl Fixed 1 1 0x0/0x13 uhci#3
22 0x88 9 PCI Lvl Fixed 2 2 0x0/0x16 uhci#4, cpqci#0
24 0x82 7 Edg MSI 2 1 - pcieb#1
25 0x30 4 Edg MSI 4 1 - pcieb#0
26 0x83 7 Edg MSI 5 1 - pcieb#2
27 0x31 4 Edg MSI 6 1 - pcieb#4
28 0x42 5 Edg MSI-X 5 1 - qlc#0
29 0x43 5 Edg MSI-X 6 1 - qlc#0
30 0x44 5 Edg MSI-X 7 1 - qlc#1
31 0x45 5 Edg MSI-X 0 1 - qlc#1
32 0x60 6 Edg MSI 1 1 - e1000g#0
160 0xa0 0 Edg IPI all 0 - poke_cpu
192 0xc0 13 Edg IPI all 1 - xc_serv
208 0xd0 14 Edg IPI all 1 - kcpc_hw_overflow_intr
209 0xd1 14 Edg IPI all 1 - cbe_fire
210 0xd3 14 Edg IPI all 1 - cbe_fire
240 0xe0 15 Edg IPI all 1 - xc_serv
241 0xe1 15 Edg IPI all 1 - apic_error_intr
What is the solution, help needed please
Walter

I am looking at something similar.
On boot I receive the above notices for IRQ 17 and IRQ18. Not seeing any further messages after boot, though.
# echo ::interrupts -d | mdb -k
IRQ Vect IPL Bus Trg Type CPU Share APIC/INT# Driver Name(s)
9 0x80 9 PCI Lvl Fixed 1 1 0x0/0x9 acpi_wrapper_isr
16 0x20 1 PCI Lvl Fixed 0 1 0x0/0x10 sdhost#0
17 0x81 9 PCI Lvl Fixed 1 4 0x0/0x11 ehci#2, ehci#1, ehci#0, yge#0
18 0x82 9 PCI Lvl Fixed 0 5 0x0/0x12 ohci#3, ohci#2, ohci#1, ohci#0, yge#1
19 0x40 5 PCI Lvl Fixed 0 2 0x0/0x13 pci-ide#0, pci-ide#0
24 0x83 7 PCI Edg MSI 1 1 - pcieb#0
25 0x30 4 PCI Edg MSI 0 1 - pcieb#1
26 0x84 7 PCI Edg MSI 1 1 - pcieb#2
27 0x31 4 PCI Edg MSI 0 1 - pcieb#4
28 0x85 7 PCI Edg MSI 1 1 - pcieb#5
29 0x60 6 PCI Edg MSI 1 1 - rge#0
160 0xa0 11 Edg IPI all 0 - poke_cpu
208 0xd0 14 Edg IPI all 1 - kcpc_hw_overflow_intr
209 0xd1 14 Edg IPI all 1 - cbe_fire
210 0xd3 14 Edg IPI all 1 - cbe_fire
240 0xe0 15 Edg IPI all 1 - xc_serv
241 0xe1 15 Edg IPI all 1 - apic_error_intr

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    <td>Fire Calls</td>
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$myFile = "/var/home/hondovfd/hondovfd.org/www/membersonly/firecalls.txt";
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
fclose($fh);
echo $theData;
?></td>
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}, true);
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<div class="top"></div><div class="wrap">
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<tr>
    <td height="47" class="h2">Members Only Area</td>
</tr>
<tr>
    <td><p><a href="/membersonly/documents.php">Useful Documents</a></p>
      <p><a href="/membersonly/IncidentCount01_08.pdf">Current Call Statistics</a> as of 9/3/09</p>
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you don't need all that bloat. set a session during login of some kind of uniquely identifying id. i.e.
$_SESSION['id'] = $row_rs['id'];
then on the pages you need to protect, check it like this....
<?php
session_start();
if (!(isset($_SESSION['id']) && $_SESSION['id'] != '')) {
die(header("Location: http://www.notinprotectedareas.com")); }
?>
you can use an include file i.e.
<?php require_once('login_check.php'); ?>
where file is name login_check.php to make your auth controls clean on your protected pages.

How to save Jobs with different priority level in a Queue?

Hi, Friends,
I have a set of Job (see below) objects.
I would make a queue: if they have the save priority level, first in and first out. this is easy to do by ArrayList. however, If they have different priority level, I would like make the Jobs with the highest level first out.
How can I implemented this idea in Java?
Regards,
Youbin
public class Job {
private short _priorityLevel = 0;
public void setPriorityLevel(short priorityLevel) {
this._priorityLevel = priorityLevel;
public short getPriorityLevel() {
return _priorityLevel;

Hi,
Here is my test code, it works:
public class Job implements Comparable{
private int _priorityLevel=0;
private String _jobDescription=null;
public Job() {
public void setPriorityLevel(int priorityLevel) {
this._priorityLevel=priorityLevel;
public int getPriorityLevel() {
return this._priorityLevel;
public void setJobDescription(String jobDescription) {
this._jobDescription=jobDescription;
public String getJobDescription() {
return this._jobDescription;
public int compareTo(Object obj) {
return (this._priorityLevel-((Job)obj)._priorityLevel);
import java.util.LinkedList;
import java.util.Iterator;
import java.util.Collections;
import java.util.Collection;
public class test {
public test() {
public static void main(String[] args) {
Job job1 = new Job();
job1.setJobDescription("Job1");
job1.setPriorityLevel(2);
Job job2 = new Job();
job2.setJobDescription("Job2");
job2.setPriorityLevel(2);
Job job3 = new Job();
job3.setJobDescription("Job3");
job3.setPriorityLevel(2);
Job job4 = new Job();
job4.setJobDescription("Job4");
job4.setPriorityLevel(1);
Job job5 = new Job();
job5.setJobDescription("Job5");
job5.setPriorityLevel(1);
Job job6 = new Job();
job6.setJobDescription("Job6");
job6.setPriorityLevel(1);
LinkedList linkedList = new LinkedList();
linkedList.addLast(job1);
linkedList.addLast(job2);
linkedList.addLast(job4);
Iterator ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
System.out.println("---------");
Collections.sort(linkedList);
ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
System.out.println("---------");
linkedList.addLast(job3);
ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
System.out.println("---------");
Collections.sort(linkedList);
ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
System.out.println("---------");
linkedList.addLast(job5);
linkedList.addLast(job6);
ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
System.out.println("---------");
Collections.sort(linkedList);
ite=linkedList.iterator();
while (ite.hasNext()) {
System.out.println(((Job)ite.next()).getJobDescription());
}

Reclassification - Posting Logic with Different Posting Levels

Hi *,
we've a reclassification task on posting level 30.
In SAP online help I've found the statement "The system includes all values of the triggering object(s) entered or posted with a posting level less than or equal to 30.". So I assume that also PL 12 and 22 is covered by our reclassification task. However, I've realized that the task doesn't consider postings on PL 12 or PL22. Within the SAP help I couldn't find a remark that cons group changes are exluded.
Does anyone know whether cons group changes have to be considered by the system?
Thanks in advance!
Daniel

Hi Daniel,
AFAIK, 00, 01, 10, 20 and 30 PLs are considered by the system in case of reclass on the PL 30.
PLs of cons groups changes ( 02, 12 and 22) are not considered.

Restoring the backup on other server with different patch level

Hi Gurus,
I have one HP-UX B11.31 server which holds ORACLE software with 10.2.0.4 patch level, and I have restored one database with the same patch level from HP DataProtector successfully. Now, I want to restore two node RAC database backup with Oracle Patch level of 10.2.0.2 into the Restore server which is of 10.2.0.4 patch level, the RAC database uses ASM, here are the steps which I am going to follow;
1. Create a new database with the same schema as like the RAC database in ASM.
2. Restore & Recover the RAC database backup from Data Protector.
But, I have one question, can I restore & recover the backup which is in lower grade Oracle software patch level i.e; 10.2.0.2 on a higher grade Oracle software patch level ie; 10.2.0.4 ???
?:|
Even after restoring & recovering can the database will work? PLEASE guide.
Thanks in Advance.

Thanks again!!!
The point of upgrading the database comes when there is already a database and one is upgrading the ORACLE software version and then upgrading the database to its version using the scripts you suggest.
Here is the scenario where I have to restore and recover a 10.2.0.2 RAC database backup on 10.2.0.4 sotware version,
*my question is that, whether there will be any conflict of patch version as the Oracle Brain will be of the latest version? Oracle software will successfully restore and recover the database backup with a lower patch version? or it will throw any error when restoring the backup like compatibility unmatched between the software and the backup you are trying to restore & recover?*
yes the RAC database is in ASM.
Thanks & Regards

HT202213 Can I use home sharing on devices with different apple ids?

I have my computer set up with my Id. Can my daughter use home sharing on her device with a different Id?

I do not think so. See:
Understanding Home Sharing
Troubleshooting Home Sharing

Sharing iphoto library with different users

I have a new imac, set up different users for myself and my wife. We have been uploading our photos to iphoto on my account and evertime she would like to access them she has to log out and into my account.
Any way to share the library between users?

There is a bug in iPhoto 11 that prevents two users having the app opened at the same time, so Sharing using the preferences method is pretty much pointless until that's fixed.
That said:
For iPhoto 09 (version 8.0.2) and later:
What you mean by 'share'.
If you want the other user to be able to see the pics, but not add to, change or alter your library, then enable Sharing in your iPhoto (Preferences -> Sharing), leave iPhoto running and use Fast User Switching to open the other account. In that account, enable 'Look For Shared Libraries'. Your Library will appear in the other source pane.
Any user can drag a pic from the Shared Library to their own in the iPhoto Window.
Remember iPhoto must be running in both accounts for this to work.
If you want the other user to have the same access to the library as you: to be able to add, edit, organise, keyword etc.
Quit iPhoto in both accounts. Move the Library to the Users / Shared Folder
(You can also use an external HD set to ignore permissions, a Disk Image or even partition your Hard Disk.)
In each account in turn: Double click on the Library to open it. (You may be asked to repair the Library Permissions.) From that point on, this will be the default library location. Both accounts will have full access to the library, in fact, both accounts will 'own' it.
However, there is a catch with this system and it is a significant one. iPhoto is not a multi-user app., it does not have the code to negotiate two users simultaneously writing to the database, and trying will cause db corruption. So only one user at a time, and back up, back up back up.
Regards
TD

Sharing a computer with different user/accounts libraries

Is it possible to use my parents MacBook iTunes in the Netherlands to open a new Library and associate that with my own US account so I can synchronize my iPhone and iPod with my stuff? That would spare me dragging along our Macbook every time but I have a feeling that this is going to be a problem... Can anyone advise or speak from experience having tried this?
Thanks, Floor

I guess no info on this. I will try and see how I fare. if anyone is interested let me know in which case i can share findings.
One way round this might eb sharing libraries but I am not sure that is legal strictly as I suppose parents MAC in the Netherlands does not classify as a household MAC....

IRQxx is being shared by drivers with different interrupt levels

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