Java HTTP Post Raw Data

Question

Hi All,
I'm looking to make an HTTP post request given the raw data that I have. I've spent a while looking for the solution, made a handful of attempts and I'm looking for a little bit of help. The PHP code for what I'm looking to do looks like this:
<?
$url="http://localhost:3009";
$postdata="<?xml version=\"1.0\" encoding=\"UTF-8\"?>
<hi></hi>";
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata);
$result = curl_exec($ch);
curl_close($ch);
echo($result);
?>
My attempt was this:
     private String setXmlPostHeader(Document doc, PostMethod postMethod) throws java.io.IOException, java.io.UnsupportedEncodingException, javax.xml.transform.TransformerException
          ByteArrayOutputStream xmlBytes = new ByteArrayOutputStream();
          XML.serialize( doc, xmlBytes );
          final byte[] ba = xmlBytes.toByteArray();
          String data = new String(ba, "utf-8");
          InputStreamRequestEntity re = new InputStreamRequestEntity(new ByteArrayInputStream(ba));
          postMethod.setRequestEntity(re);
          postMethod.setRequestHeader("Content-type", MediaType.XML.toString() + "; charset=UTF-8");
          return data;
And then executing the postMethod, but this simply is a post containing no data. Does anyone see anything wrong that I'm doing? Is there an easy way to set the raw http post data in java like there is in php? Thanks.
-Ken

Answer 1

Look at the PostMethod documentation. You need to set the multipart request.