JTree Drag & Drop question. DragSourceDragEvent vs DropTargetDragEvent

Question

I'm implementing Drag and Drop within a JTree.
I need to get the TreeNode as the user drags over it. This method works for a DropTargetDragEvent:
private TreeNode getNodeForEvent(DropTargetDragEvent dtde)
              Point p = dtde.getLocation();
              DropTargetContext dsc = dtde.getDropTargetContext();
              JTree tree = (JTree)dsc.getComponent();
              TreePath path = tree.getClosestPathForLocation(p.x, p.y);
              System.out.println("DropTargetDragEvent: Closet path for tree locaiton is " + path);
              return (TreeNode)path.getLastPathComponent();
        } But this method for DragSourceDragEvent returns a node much farther down on the JTree than where the user is dragging.
private TreeNode getNodeForEvent(DragSourceDragEvent dsde)
         Point p = dsde.getLocation();
         DragSourceContext dsc = dsde.getDragSourceContext();
         JTree tree = (JTree)dsc.getComponent();
         TreePath path = tree.getClosestPathForLocation(p.x, p.y);
         System.out.println("DragSourceDragEvent: Closet path for tree locaiton is " + path);
         return (TreeNode)path.getLastPathComponent();
   } Am I missing something? The first method I found on this site. The 2nd method I modified since I need the node based on a DragSourceDragEvent because that's where I can set a custom cursor based on the node type.
Has anyone run into this before?
Thanks

Answer 1

I've figured out why this is happening but am not sure how to fix it.
For DropTargetDragEvent getLocation() returns the cursors position within the component.
For DragSouceDragEvent getLocation returns the cursors position on the screen.
Sortof makes sense but I don't know how to get a position over a component from the position on the screen.