Line graph, order by caluse

Hi,
version:11.1.1.6
In line bar charts ,can we control the order of value of X-axis ? I find its not following from criteria !
Thanks,
Hesh

I got it right now, few columns were in exclude section
Thanks,
hesh

Similar Messages

Change sort order in line graph

Sorry, my mistake !
In one of the ColLabels i had placed the xsl:sort line ABOVE the xsl:for-each.
So, now it is working.
In a line graph I need to change the sort order of the elements in my XML file.
I need the elements to be sorted by month number, so that january comes first, then february etc.
I have an element in the XML file called DATE which has the format 'YYYYMMDD'
I tried first to change the sort command for the Label.
<ColLabels>
<xsl:for-each select=".//XX_ROW" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:sort select="substring(DATE,5,2)"/>
That worked fine, the label values are resorted as I wanted.
Of course, I also have to set the same sort order for the data values.
So I did that in the same way :
<RowData>
<xsl:for-each select=".//XX_ROW" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:sort select="substring(DATE,5,2)"/>
But, to my surprise, I got an error :
Caused by: oracle.xdo.parser.v2.XSLException: <Line 70, Column 45>:
XML-22047: (Error) Invalid instantiation of 'xsl:sort' in 'RowData' context.
Does anybody understand why this was not possible ?
Is there another syntax for sorting in the RowData ?
What's the use of being able to sort the X axis lable, if I am not able to sort the data ?
Edited by: user792912 on 2011-maj-30 05:11

This was an error I had made in the graph code.
The xsl:sort line must be placed AFTER the xsl:for-each !

Creating a Double Line Graph

Hello,
I'm trying to create a graph from the information seen in the table below. I need to plot on the X- Axis, the T0,T1,T2 values. There will be two data sets for the line graph, Subject A and Subject B, the value from which will be plotted on the Y-Axis. I've spent about an hour now, trying to order the values to create the graph I need.
Another way of saying this, is that I'm plotting the differences in Subject A versus Subject B over a period of Time (T0, T1, T2).
It should look something like this:
Help Please!
-KB

Hi KBaines,
Please don't worry about wasting anyone's time. Many users in this forum look upon Numbers problems as a challenge. If you solved your own problem, please post your solution to help others.
Regards,
Ian.

Creating multiple Line Graph having common values..

Hi...
I've created one application process for creating Multiple Line Graph.
And i've integreted two tables in this graph, where values may be common for both the tables. In this case, for common values, instead of getting overlapped I'm getting scattered graph(its totally abnormal). Please help me if you 've any idea about this issue.....?
Please go through the App Process and the output of the SQL query.
In output of the query, in the NAME column "Feb-2010" is common.
This is the SQL query OUTPUT:_
TABLE 1
NAME VALUE
Sept-2009 100
Oct-2009 95
Nov-2009 98
Feb-2010 97
TABLE 2
NAME VALUE
Jan-2010 93
Feb-2010 100
Mar-2010 98
Application Process :_
DECLARE
BEGIN
OWA_UTIL.mime_header ('text/xml', FALSE);
OWA_UTIL.http_header_close;
HTP.p ('<?xml version = "1.0" encoding="utf-8" standalone = "yes"?>');
HTP.p ('<anychart>');
HTP.p ('<settings>');
HTP.p ('<animation enabled="True"/>');
HTP.p ('</settings>');
HTP.p ('<charts>');
HTP.p ('<chart plot_type="CategorizedVertical">');
HTP.p ('<data_plot_settings default_series_type="Line">');
HTP.p ('<line_series>');
HTP.p ('<marker_settings>');
HTP.p ('<marker type="None" />');
HTP.p ('<states>');
HTP.p ('<hover>');
HTP.p ('<marker type="Diamond" />');
HTP.p ('</hover>');
HTP.p ('</states>');
HTP.p ('</marker_settings>');
HTP.p ('<tooltip_settings enabled="True">');
HTP.p ('<format>Year {%Name}{enabled:false} {%SeriesName} - {%Value}{numDecimals:0}%</format>');
HTP.p ('</tooltip_settings>');
HTP.p ('<effects enabled="True">');
HTP.p ('<drop_shadow enabled="False" />');
HTP.p ('<bevel enabled="true" distance="1" blur_x="2" blur_y="2" />');
HTP.p ('</effects>');
HTP.p ('<line_style>');
HTP.p ('<line thickness="3" /> ');
HTP.p ('</line_style>');
HTP.p ('</line_series>');
HTP.p ('</data_plot_settings>');
HTP.p ('<chart_settings>');
HTP.p ('<title enabled="true">');
HTP.p ('<text>Avg. %App. Uptime per month </text>');
HTP.p ('</title>');
HTP.p ('<axes>');
HTP.p ('<y_axis>');
HTP.p ('<title>');
HTP.p ('<text>Value</text> ');
HTP.p ('</title>');
HTP.p ('<scale minimum="90" maximum="101" major_interval="1" />');
HTP.p ('<labels>');
HTP.p ('<format>${%Value}{numDecimals:0}</format>');
HTP.p ('</labels>');
HTP.p ('<axis_markers>');
HTP.p ('</axis_markers>');
HTP.p ('</y_axis>');
HTP.p ('<x_axis tickmarks_placement="Center">');
HTP.p ('<title enabled="False" /> ');
HTP.p ('</x_axis>');
HTP.p (' </axes>');
HTP.p ('</chart_settings>');
HTP.p ('<data>');
FOR ObjRecord IN (select DISTINCT(K_OBJECT.OBJECT_ID) as OBJECT_ID,name from K_OBJECT, K_OBJ_TYPE_ASP_REL where K_OBJECT.OBJECT_ID=K_OBJ_TYPE_ASP_REL.OBJECT_ID and K_OBJ_TYPE_ASP_REL.OBJECT_TYPE_ID=1)
LOOP
HTP.p ('<series name="'|| ObjRecord.name ||'">');
FOR MonthlyValueRecord IN (select NAME,VALUE
from K_REPORT_RUN,K_ASPECT_VALUES,K_ASP_TIM_RPT_REL
where K_REPORT_RUN.RUN_ID=K_ASP_TIM_RPT_REL.RUN_ID
and
K_ASPECT_VALUES.ASPECT_VALUE_ID=K_ASP_TIM_RPT_REL.ASPECT_VALUE_ID
and
K_ASP_TIM_RPT_REL.ASPECT_ID=1
and
K_ASP_TIM_RPT_REL.OBJECT_ID=ObjRecord.OBJECT_ID
order by K_REPORT_RUN.STARTTIME)
LOOP
HTP.p ('<point name="'|| MonthlyValueRecord.name ||'" y="'|| MonthlyValueRecord.value ||'" />');
END LOOP;
HTP.p ('</series>');
END LOOP;
HTP.p ('</data>');
HTP.p ('</chart>');
HTP.p ('</charts>');
HTP.p ('</anychart>');
htmldb_application.g_unrecoverable_error := true;
END;
Edited by: user12873839 on Apr 9, 2010 3:58 AM
Edited by: user12873839 on Apr 9, 2010 4:02 AM
Edited by: user12873839 on Apr 9, 2010 8:00 AM

>
Help Needed Urgent.....
>
That is one surefire way to not get any help and certainly not urgently. I suggest that you amend the title of your post to something that reflects the actual issue. This will also help anyone with similar issues to find the thread.
When posting code please put {noformat}{noformat} (with the curly brackets and the word code in lower case) above and below it to preserve formatting like this...
{noformat}{noformat}
SELECT *
FROM emp
{noformat}{noformat}
This will be displayed on the forum like this...SELECT *
FROM emp
Cheers
Ben

Simple line graph problem

Hi there,
I want to create a very simple line graph, containing 1 line. Therefore i create a Graph.LINE_VERT_ABS type Graph and add the data using myGraph.setLocalRelationalData(al ArrayList). This arraylist contains values in the form of
setname jan 12.2
setname feb 14.5
setname march 8.1
etc
When i do this, I get the errormessage: "The data has an insufficient number of columns. This graph type requires at least 2 columns of data. The data provided has one column.".
When i add another dummy value to the arraylist:
dummy dummya 1
dummy dummyb 2
the graph displays correctly, but only with a additional line for the dummy values, also in the Legend.
What am i doing wrong. Surely it is possible to display just one line in the Graph??
Any help is appreciated.
Linda

In the arraylist, setname identifies a column. By default, columns are plotted as groups, or different points along the horizontal axis. In order to have a line or area graph, you need two groups. The data that you are passing has 1 group and 3 series. You should pass it as follows:
jan setname 12.2
feb setname 14.5
march setname 8.1
etc.
Passing data like this will give you three groups (jan, feb, march) and one series (setname).
By the way, what version of BI Beans are you using and how did find out about setLocalRelationalData? That API was never publicly released. It was replaced by setTabularData (same method renamed) and exposed in 9.0.3.
BI Beans Product Management

2D Line Graph Question

I have a 2D line graph that I built. At some points in the graph where the lines intersect the number values displayed on the graph get bunched up and it is hard to read. Is there a way to fix that? This is APEX 3.2 on Oracle 10.2.0.4 database. Thanks

You basically have only a couple of options here:
First, turn off the labels and possibly turn them into Hints. They wouldn't show on the chart, but when the user held over the data point, a tool tip would appear showing them the valuable.
Second, adjust elements of the chart. What you are really looking at here is that your data set is causing this specific issue and not the charting engine or anything like that. You could try to manually change the axis max and min to get more spacing, or you could adjust the height of the chart to get more spacing, but this may not be a viable option. You could have one set of labels above the plotted line and another set of labels below the plotted line that way the values do not overlap with anything. However, from a conceptual standpoint, it will be difficult to determine in code which line should have values above and which should have values below. When your data set changes, you may end up with labels in the wrong place if you hard code where they are at.
The current XML reference can be found at: http://www.anychart.com/products/anychart/docs/xmlReference/index.html however, that is for anychart 5. I'm looking for the link to the earlier versions...
You can use this to create custom xml where you can adjust the position of the labels.
Finally, you do not want expand the height of the chart between two points on the Y axis. That would change the structure of the chart and the visual properties of the chart and the shape of the data would be askew. You cannot do this for good reason. You can though use a logrithmic scale. In most cases though, this is not a practical solution. Data sets need to have very specific characteristics in order to be able to merit a logrithmic scale. Most queries require a simple linear scale.
Austin

Plot values in X-Axis in 2D line graph

Hi,
I am using 2D line graph to plot graph but the graph is to be ploted based on date i.e i have a range to be ploted in X-Axis i.e Dates how to plot that please suggest now the values are automatically it is getting ploted
This is query wht i am using
SELECT
pobj.name "Object Name",
tas.name "Task Name",
SUM (TCL.NUM_HOURS_DAY1+TCL.NUM_HOURS_DAY2+TCL.NUM_HOURS_DAY3+TCL.NUM_HOURS_DAY4+TCL.NUM_HOURS_DAY5+TCL.NUM_HOURS_DAY6+TCL.NUM_HOURS_DAY7) ) "Effort"
FROM
timecard_lines tcl,
project_objects pobj,
tasks tas,
projects pro,
timecard_headers thr,
employees epl,
object_task_estimate ote,
TIMECARD_PERIODS TP
WHERE
pro.id = :P61_PROJECTS and
tas.id = :P61_TASKS and
TP.ID = THR.TPD_ID AND
tcl.pobj_id = pobj.id AND
tcl.tas_id = tas.id AND
pro.id = pobj.pro_id AND
thr.id = tcl.thr_id AND
thr.emp_id = epl.id AND
ote.tas_id = tas.id AND
pobj.id = tcl.pobj_id
and
ote.pobj_id = pobj.id and
pro.id in
(SELECT pro.id
FROM projects pro, employee_project_pairs
epp, project_employee_roles per ,employees empl
WHERE empl.id = epp.emp_id
AND pro.id = epp.pro_id
AND epp.project_role_id = per.id )
group by pro.project_name,pobj.name,tas.name
order by pobj.name

Standard syntax on the Mac is Object, Action. The order is always Select an object (in this case, part of a spreadsheet), then perform an action on or with tat object (in this case, make a chart).
The same syntax applies to Copy or Cut (and to Paste, althyough it's not as obvious there—the object is whatever is currently on the Clipboard).
I don't think there is information on printing charts/graphs in the online help. A chart is a graphics object, and is printed as part of the document that contains it. Printing the spreadsheet should also print the chart, provided it is on a page that contains data (AppleWorks's default is to print only the rows and columns that contain data). If you want to print the chart without any of the data, drag the chart over the data to conceal it, and choose the Print options that do not show column or row headers and the cell grid. (These are probably in the AppleWorks options in your Print dialogue, but their position will depend on your print driver.)
Placing the object (the chart) in another document provides an easier method of printing only the chart, and the method you used (dragging the chart from the spreadsheet to the second document is a common and acceptable one. Dragging an object from one document to another places a copy of the object on the second document, and leaves the original on the original document. This is true in general, not just for charts.
In the case of a chart, the copy is a static object, while the original maintains its live connection to the underlying spreadsheet—changing a graphed value in the spreadsheet will change the graph to match the new value, but will not affect the copy in the second document.
Regards,
Barry

Problem Plotting a Line Graph

I am trying to plot some line graphs on Numbers and am a new user.
I can't seem to work out an issue. I want the numbers on the X axis to ascend from 0 onwards from left to right but at the moment they are descending from 10 to 0 left to right.
How can I change this so the graph is plotted logically?
Thanks in advance

There are two basic types of X-Y charts. All but one are "category" charts where the X axis is evenly spaced and the "numbers" are actually text. The data will be presented in the order listed in your table. The other is a scatter chart. The icon for this chart looks like a shotgun blast.
If your X axis numbers are evenly spaced (0,1,2,3...) you can use either type of chart. Sort your table in ascending order and it will chart as you want it to.
If your X axis numbers are not evenly spaced (such as 1,2,4,5,10) and you want the chart to be a true X-Y plot of the data, you have to use the scatter chart. In contrast to the category charts where the X axis values must be in a header column/row, a scatter chart requires the X and Y data to be in data cells. You may have to move your data over a column so the X data is not in a header column.

Line Graph Error

Hi,
I have a query like this below which will return 25 rows when i run this in a SQL work shop when i execute this in Line graph it only shows data for 15 rows remaining 10 rows are missing please suggest me what would be the mistake
Here no dates are repeated. i see lines only for 15 rows remaining 10 are missing this is happening if the data is 15 rows the limit for line graph or some changes can be made.
SELECT
null,
TP.WEEK_ENDING_DATE "Week Ending Date",
SUM(TCL.NUM_HOURS_DAY1+TCL.NUM_HOURS_DAY2+TCL.NUM_HOURS_DAY3+TCL.NUM_HOURS_DAY4+TCL.NUM_HOURS_DAY5+TCL.NUM_HOURS_DAY6+TCL.NUM_HOURS_DAY7) "Total Actual"
FROM
timecard_lines tcl,
project_objects pobj,
tasks tas,
projects pro,
timecard_headers thr,
employees epl,
TIMECARD_PERIODS TP
WHERE
PRO.ID = :P67_PROJECTS AND
TP.ID = THR.TPD_ID AND
tcl.pobj_id = pobj.id AND
tcl.tas_id = tas.id AND
pro.id = pobj.pro_id AND
thr.id = tcl.thr_id AND
thr.emp_id = epl.id AND
pobj.id = tcl.pobj_id
AND
pro.id in
(SELECT pro.id
FROM projects pro, employee_project_pairs
epp, project_employee_roles per ,employees empl
WHERE empl.id = epp.emp_id
AND pro.id = epp.pro_id
AND epp.project_role_id = per.id )
GROUP BY pro.project_name,TP.WEEK_ENDING_DATE
order by TP.WEEK_ENDING_DATE asc
Thanks
Sudhir

Hi,
You can't adjust the chart dimensions dynamically without constructing the whole thing dynamically. You can set "Use Custom XML" to Yes and then change the Height and Width settings of the chart_area tag. Labels can be rotated by setting "Labels Rotation" in the Display Settings section of the Chart Attributes to either 90 or 270.
Andy

How to draw cumulative line graph over the stacked bar chart?(SSRS)

Hello,
I need your help to draw a cumulative line graph over this bar chart.
I need your help to draw a cumulative line graph over this bar chart in SSRS.
The dimension (Category Group) is "Hour" in this case. and expression is sum of two distinct values like 'Y' and 'N' in Activity column(Series Groups). The sum(Activity=Y) in green color and sum(Activity='N') in Red color.
I require to draw a cumulative line graph in this same chart, that should give the result of cumulative Sum(Activity) for each hour?? I mean sum of (Y+N) for each hour and that should be cumulative over the hour.
I mean sum of (Y+N) for each hour and that should be cumulative over the hour.
SSRS Version details:
Microsoft SQL Server Reporting Services Designers
Version 10.50.1600.1
--Siva

Hi Siva,
It seems that you need to verify your email address to post images, etc
Besides, Microsoft® SQL Server™ 2008 Reporting Services: Step by Step is a good choice to you. With STEP BY STEP, you work at your own pace through hands-on, learn-by-doing exercises. A companion CD includes data sets and sample code. You can download
it from this link http://my.safaribooksonline.com/9780735626041 Click the Extras, you can get the samples and database from Supplemental Content.
And there are vast of valuable articles and SQL Server Reporting Services Books Online in MSDN ,you can click these link to begin your learning journey, SQL Server Reporting Services 2008 Books Online:
http://msdn.microsoft.com/en-us/library/ms159106(v=SQL.100).aspx
Besides these, there are still many valuable videos in Microsoft Webcast, click this link
https://msevents.microsoft.com/cui/SearchDisplay.aspx?culture=en-US#culture=en-US;eventType=0;sortKey=;sortOrder=;pageEvent=false;hdnInitialCount=;searchcontrol=yes;kwdAny=Reporting%20service to register with a windows live ID, then download the ones you
want.
Hope this helps.
Regards,
Charlie Liao
TechNet Community Support

Line Sort order differs from Shopping Cart to PO

All :
A number of shopping carts are raised on the back of a quotation received from vendors.
Where these quotes require a multi line Purchase Order, we enter the data in the same sequence as they appear on the quotation.
The Purchase Order should also therefore reflect the same sequence. For some reason this does not happen.
EG shopping cart shows items:
1st Line 30 Green Widgets
2nd Line 50 Blue Widgets
3rd Line 900 Red Widgets
BUT PO shows:
1st Line 50 Blue Widgets
2nd Line 30 Green Widgets
3rd Line 900 Red Widgets
Is there some setting I am missing somewhere? Or is there some sort of arcane sorting going on in the background that I don't know about.
Thanks for your time guys
Adrian

Hi
<b>Seems like a bug in the BAPI call at R/3 side.The sorting incase of multi line Purchase Orders is not happening correctly. Please give some more details.</b>
Please report the same bug to SAP by creating a OSS message as well, for faster processing of the query.
Regards
- Atul

Help needed in plotting Line Graph!!!!!!!!!Pls help!!

Hi, i need help in plotting a simple line graph showing the x&y axis and has to plot 3 different lines in the same graph.I have written a program and i need to implement this graph in it.Is there any tutorial for plotting line graphs,i mean steps included.
Please help!

You describe your need, but not where it originates from.
Is it a programming assignment? If so, I hope this is not your chosen major, as you will fail because you are a non-resourceful plagarist.
Do you need to simply graph some data? Use an existing package. There are free ones somewhere.
What do you mean "i have written a program and i need to implement this graph in it"? If you wrote the program, wouldn't you be done?
Enjoy programming

Help needed in plotting line graph!

Hi i need help in plotting a line graph complete with both axes shown,plus the legend on the side shown.
Pls help!!!!
rgds

Here's a simple line graph applet I did some time backimport java.awt.*;
public class LineGraff extends java.applet.Applet{
   double []toGraff = {6.0, -14.0, -164.0, -210.0, 108.0, 770.0,
                            1354.0, 896.0, -572.0, -1348.0, -780.0, -108.0};
   double []numsFromFile = {6.0, -14.0, -164.0, -210.0, 108.0, 770.0,
                            1354.0, 896.0, -572.0, -1348.0, -780.0, -108.0};
   int max, min, size, Hscale;
   double Vscale;
   public void init(){
      size = numsFromFile.length-1;
      java.util.Arrays.sort(numsFromFile);
      max = (int) numsFromFile[size];
      min = (int) numsFromFile[0];
      Vscale = max-min;
      Vscale = 200/Vscale;
     Hscale = Math.round(300/size);
   public void paint(Graphics g) {
      g.setFont(new Font("Arial",0,14));
      g.drawString("Example app: drawing a graph from a double array",25,18);
      g.setFont(new Font("Arial",0,10));
      g.setColor(Color.blue);
      g.fillRect(10,20,365,230);
      g.setColor(Color.cyan);
      g.drawLine(25,25,25,225);
      g.drawLine(25,140,330,140);
      g.setColor(Color.white);
      int intA = 30, intB = 0, intC = 0;
      int intD = (int) (Math.round(140 - (Vscale * toGraff[0])));
         for(int i=1; i <= size; i++) {
           intC = intA + Hscale;
           intB = intD;
           intD = (int) (Math.round(140 - (Vscale * toGraff[ i ])));
           g.drawLine(intA, intB, intC, intD);
              if(toGraff[ i ] > 0)
                 g.drawString(Double.toString(toGraff[ i-1 ]), intA+6, intB-3);
              else
                 g.drawString(Double.toString(toGraff[ i-1 ]), intA+6, intB+8);
           intA += Hscale;
      g.drawString(Double.toString(toGraff[size]), intA+6, intD-3);
}

How do I change the line color in a line graph?

I used Illustrator to create a line graph. (Not my desired option as I normally import them from R and then edit, but the textbook wanted to show that you can create graphs and edit them in Illustrator)
Anyway, I did all of the editing except that I can't change the color of the line. My assignment requires me to match the textbook example and the textbook does not provide instructions on how to do it. I've done just about any method I can think of and the line still stays light gray. I'm almost willing to just give up and lose the points but something as simple as color can't be this hard, right? Right?

Whenever I try to shift+direct select it thinks I want to move the line, so as I shift + direct select and drag my mouse across the line (to highlight it all) it moves a chunk of the line and turns it into a near perpendicular line.
I found the appearance window, it just says "Path" (the color I want it to be that it's not)
"Stroke" 4pt
"Fill" (the color I want it to be that it's not)
"Opacity": Default
And some other buttons. I think I'll try the help line tomorrow, I know I saw a customer service number somewhere and I'm only here because the chat was unavailable. This is only one of my 3 problems with my assignment so I'll search here for answers to the other two. Learning new things is rarely fun.

11.1.1.5 - Measure labels are appearing in legend (line graph)

I've created a line graph in 11.1.1.5. My legend is showing a combination of the column value and the measure name (e.g. Web Sales, Direct Sales, Retail Sales). I want my legend to simply say Web, Direct, and Retail, without the appended 'Sales' measure label.
The Measure Labels tile is currently residing in the Vary Color By (Horizontal Axis) zone, along with the legend column, so I guess it makes sense that the legend column and the measure labels would both show up in the legend (although I don't think that was the case in 11.1.1.3). However, there doesn't appear to be any place into which I can relocate the Measure Labels tile so that the word Sales DOESN'T appear on the line graph. If I move the Measures Labels tile into Graph Prompts, Sections, or Group By (Horizontal Axis), the word Sales appears in those locations. If I attempt to move that tile into the Lines (Vertical Axis) box, or into the Excluded box, it won't allow being dropped there.
Switching between line, bar, and area graphs reveals the same problem in all graph types.
Is there any way to supress the display of measure labels on graphs in 11.1.1.5?

Hi Paul,
This is the feature in 11g obiee displaying the Measue heading and dimension value... like u said right Web Sales...and so on.
Here in u case web is the value of dimension and Sales is heading of a measure.
One way is if u are not using any dimension apart from 1 dim and fact u can put measure labels in the group by axis and dimension column in the show in legend section then it will give u only web.
But if u have 2 dimension then we have to put this measure labels with either one of the dimensions in this case heading of the measure wil display.
Thanks
Subhash

Line graph, order by caluse

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