Linking to Open a file in java

Question

Hello,
I wanted to create a link in my program that opens an excel spread sheet, seperately from the program. (i.e opens in excel). Is it possible to do this?
Thanks
Stu
Message was edited by:
studomonly

Answer 1

import java.io.*;
import javax.swing.*;
import javax.swing.filechooser.*;
class OpenExcelDemo {
    public static void main(String[] args) {
        new OpenExcelDemo().go();
    void go() {
        JFileChooser jfc = new JFileChooser();
        FileNameExtensionFilter filter = new FileNameExtensionFilter("Excel Files", "xls", "csv");
        jfc.setFileFilter(filter);
        int returnVal = jfc.showOpenDialog(null);
        if(returnVal == JFileChooser.APPROVE_OPTION) {
           open(jfc.getSelectedFile());
    private void open(File f) {
        String[] commands = {
            "rundll32",
            "url.dll,FileProtocolHandler",
            f.getAbsolutePath()
        try {
            Runtime.getRuntime().exec(commands);
        } catch (IOException e) {
            e.printStackTrace();
}All normal caveats apply.
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