Maxl parameterizing entire path using servername

I want to use environment (or local if environments not possible) to parameterize three paths for source files for Maxl imports and destination files for exports. Easy enough when the path is the essbase server ($Arborpath etc.) The problem arises when I want to use a path with a servername in a variable. For example:
import database sample.basic data from data_file "$Testpath\\Calcdat.txt" on error abort;
where Testpath = \\EssServerName\Dirname\SubDirname
at the moment TestPath = \\Forbin\MTGTools\Maxl BUT I've tried many permutations of slashes, double slashes, (even tried triple slashes on the servername which works in some circumstances), quotes etc. along with "' (double quotes surrounding single quotes)
I've gotten variations of this to work fine right up to the point of using the servername with the variable.
The expanded statement looks perfect in the console black screen but of course that's not reliable.
Thanks much for your help.
Ron

Okay, how about this:
spool on to "\\$COMPUTERNAME\\temp\\For_Ron.log" ;
login "admin" "password" on "$COMPUTERNAME" ;
exit ;Which produces the log file (in c:\temp):
MAXL> login "admin" "password" on "DEMO1113" ;
OK/INFO - 1051034 - Logging in user [admin].
OK/INFO - 1051035 - Last login on Tuesday, March 30, 2010 5:25:13 PM.
OK/INFO - 1241001 - Logged in to Essbase.
I'm not seeing a need for quadruple backslashes to get UNC naming, which I think is the need (if this indeed be on Windows). *nix I couldn't say.
I don't think import would be any different than spool, although I could always be surprised.
Regards,
Cameron Lackpour
Edited by: CL on Mar 30, 2010 5:28 PM
Of course I could be missing the whole point, again, so who knows.

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Ruth, UK

Hi Ruth,
Per my knowledge, there is no OOB way to retrieve the entire path of the managed metadata column value.
However, you can use the code sample to get the Managed Metadata Hierarchy, please refer to the link below:
http://msdn.microsoft.com/en-us/library/ff823725.aspx
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Victoria
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PDF Filename is entire path

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Had another look at this and I will try to be as brief as possible.
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Regards

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Problem Solved.
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Execute " net use \\servername\..... "

Hi.
If i run this command from my Windows XP machine.
net use \\timecare\winlas winlas /USER:winlasuser &&\\timecare\winlas\winlas.exe
It works perfect ....
But when I try it with Zenworks ..... it aint ... the cmd.exe just pops up and then
dissaperes, and then no more.

yes... but that didn´t help.
Had to make two ZFD objects.
The first one..
net use \\timecare\winlas \\timecare\winlas> winlas /USER:winlasuser
the second one..
\\timecare\winlas\winlas.exe
and the second one, has a dep. with the first one.
// Patrik
>>>
Från:craig wilson<[email protected]>
Till:novell.support.zenworks.desktop-management.7x.applications
Datum:2010-04-12 14:46
Ärende:Re: Execute " net use \\servername\..... "
the path to file should be net.exe
On 4/12/2010 6:58 AM, xilefp wrote:
> Hi.
> If i run this command from my Windows XP machine.
> net use \\timecare\winlas <file://\\timecare\winlas> winlas
> /USER:winlasuser &&\\timecare\winlas\winlas.exe
> It works perfect ....
> But when I try it with Zenworks ..... it aint ... the cmd.exe just pops
> up and then
> dissaperes, and then no more.

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hay,
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hey,
Thanks for your reply.
Instead of using logical file name as input, can we allow the user to select logical path using parameter?
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ambichan
Message was edited by: ambi chan

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To wit:
In step 1 above, I draw a line with the Pencil tool.
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I also realize that I can do this with the pen tool; but the pen tool is a more
precise tool (and somewhat more cumbersome), and I prefer to have more
of the rough-handed look from time to time.
Finally, I also know that I can use the direct selection tool to select endpoints
from two different paths and then join them using the join command;
but this seems to be more trouble than it's worth in many cases, especially
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Is my idea of how to use the existing tools wrong in this case?
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I'm on Illustrator CS5, Mac OS X 10.6.8, using a Wacom Intuos4 tablet.
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Thanks @rcraighead - the Live Paint process seems a bit overkill for simply adding
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which was tracing a bit over the last part of the existing path and then continuing
on to extend the path. It's a bit imprecise because the existing path gets slightly
modified, but it seems to work pretty well all in all. Nice idea indeed - thanks a million.
I also found that in AI CS5, I can use the selection tool to select all of the paths
in this case and then join them using the join command. I thought I needed to
select individual anchor points for this to work, but it actually works really
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were a lot more picky with the Join command, but then again this might just
have been my lack of understanding.
I'm curious to know what other solutions to the above problem that other users
might have, so I will leave this question unanswered for a bit...
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Jeff

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Hi all,
I am learning XPATH and XQUERY from the Book "Pro T-SQL 2008 Programmer's Guide" written by Michael Coles, (published by apress). I copied the Code Listing 12-8 FOR XML PATH Using XPath Node Tests (listed below) and executed it in my
SQL Server 2012 Management Studio:
--Coles12_8.sql // saved in C:/Documemnts/SQL Server Management Studio
-- Coles Listing 12-8 FOR XML PATH Using XPATH Node Tests
-- Retrieving Name and E-mail Addresses with FOR XML PATH in AdvantureWorks
-- 16 March 2015 0935 AM
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "test()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH;
I got the following error message:
Msg 6850, Level 16, State 1, Line 2
Column name 'test()' contains an invalid XML identifier as required by FOR XML; '('(0x0028) is the first character at fault.
I have no ideas why I got this error message. Please kindly help and advise me how to resolve this error.
Thanks in advance, Scott Chang

Hi Michelle, Thanks for your nice response.
I corrected the mistake and executed the revised code. It worked nicely.
I just have one question to ask you about the appearance of the xml output of my Co;les12_8.sql:
<row>
<?nameStyle 0?>
<Person ID="1" />
697-555-0142<Person><Name><First>Ken</First><Middle>J</Middle><Last>Sánchez</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="2" />
819-555-0175<Person><Name><First>Terri</First><Middle>Lee</Middle><Last>Duffy</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="3" />
212-555-0187<Person><Name><First>Roberto</First><Last>Tamburello</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="4" />
612-555-0100<Person><Name><First>Rob</First><Last>Walters</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="5" />
849-555-0139<Person><Name><First>Gail</First><Middle>A</Middle><Last>Erickson</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="6" />
122-555-0189<Person><Name><First>Jossef</First><Middle>H</Middle><Last>Goldberg</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="7" />
181-555-0156<Person><Name><First>Dylan</First><Middle>A</Middle><Last>Miller</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="8" />
815-555-0138<Person><Name><First>Diane</First><Middle>L</Middle><Last>Margheim</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="9" />
185-555-0186<Person><Name><First>Gigi</First><Middle>N</Middle><Last>Matthew</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="10" />
330-555-2568<Person><Name><First>Michael</First><Last>Raheem</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="11" />
719-555-0181<Person><Name><First>Ovidiu</First><Middle>V</Middle><Last>Cracium</Last></Name><Email>[email protected]</Email></Person></row>
<row>
I feel this xml output is not like the regular xml output. Do you know why it is diffrent from the regular xml xml output? Please comment on this matter.
Thanks,
Scott Chang
What do you mean by regular xml document? Are you referring to fact that its missing a root element? if yes it can be added as below
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "text()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH('ElementName'),ROOT('RootName');
replace ElementName and RootName with whatever name you need to set for element as well as the root element
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How to Capitalize the first letter or an entire word using a shortcut on the keyboard just like in microsoft that uses shift+F3

please how can one How to Capitalize the first letter or an entire word using a shortcut on the keyboard just like in microsoft that uses shift+F3

What do you mean there was "no effect?" I'm not aware of any effects.
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Hi
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Display the entire path to the term in the field option programmatically

hi,
I am having hundreds of doc libs with a taxonomy column .now i want to change the property diaplay format:
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hi Benjamin,
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http://msdn.microsoft.com/en-us/library/microsoft.sharepoint.taxonomy.taxonomyfield.ispathrendered(v=office.14).aspx
Please remember to click 'Mark as Answer' on the answer if it helps you

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Pam, here's how I solved this one. Note the order of the bindings and the order of the bindings in the CFC must be the same as well. Hopefully this helps:

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Ustilago wrote:
Hi All! I am a newbie with OS X and I am wondering as to how to add a directory into the PATH using the terminal. Thank you very much!
Welcome to Apple Discussions!!
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if [ -r ~/.bashrc ]; then
. ~/.bashrc
fi
If you have further questions, you might find posting them in the UNIX forum better. One of the regular posters there, Bill Scott, has this page which you may find useful: Unix Links, especially under the Mac OS X heading.

Maxl parameterizing entire path using servername

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