Missing help with similar word

Question

It is problem with search words in help.
It is FF version independed.
I use this category, because no one from listed fits.
for example. I looking for help with word "cookie". Help should search for 'cookie' and "cookies'.
another example with polish language.
I tryed to find help about word 'ciastko'. no one were found, i should write word 'ciasteczko', that list me usefull help topics.
'ciastko', 'ciasteczko', 'ciastka', 'ciasteczka' are about the same thing 'cookie', but are variants by plural/singular and diminutive. Difference is the same like between 'cookie' and 'cake', but all means the same 'cookie' in polish language.
this problem affects many words in many languages.

Answer 1

I have a basic Vowel coding that doeswnt work...
public class vowel{
String word = "heyyou";
String vowels = "aeiouy";
int[] countv = new int[vowels.length()];
int countv2;
int i=0;
if(i<word.length();) { i++ {
if (int j=0 && j<vowels.length()) {
return j++;
if (word.charAt(i)==vowels.charAt(j)) {
countV[j]++; countV2++;
for (int i=0; i<vowels.length(); i++) {
System.out.println("Vowel "vowels.charAt(i)" = "+vcnt);
System.out.println("Consonants = "+(word.length()-vtot)); }
I also have a basic Palindrome code that works as a boolean but I need to make it return what the palindromes are and how many of them are there. I wanna know how I would do this.
public class Palindrome{
public static boolean isPalindrome(String word) {
int left = 0;
int right = word.length() -1;
while (left < right) {       
if (word.charAt(left) != word.charAt(right)) {
return false;
left++;
right--;
return true;
I would also like to know how to actually start writing the word counter.