Missing Organizational Unit Data in Organizational Data Sales
Hi,
when using and working with CRM transactions, I cannot put in the neccessary Organizational Data Saes according to my wishes. (every field should be filled in,)
Org. Unit, Object name, Org. unit, Sales Org. Sales Off. Sales Group, Dis. Chan., Division
VKORG001 Sales Area.. o 50000015 VKORG001 01 01
=> no data are set for Sales Office and Sales Group so far in "F4" entry
This data occur in our Org.Modell and can be choosen manually as well. BUT as soon as they are maintained, the field "Organizational Unit" is empty again and so the transaction has error again.
Any idea about?
Thanks for your support.
Regards,
Markus
Hi Markus,
In CRM goto tcode - SPRO - Customer Relationship Management - Master Data - Organizational Management - Assignment of Organizational Units from SAP ECC - Assign SAP CRM Sales Offices to SAP ECC Sales Offices & Assign SAP CRM Sales Groups to SAP ECC Sales Groups - To maintain Sales Office and Sales Groups.
Then goto tcode PPOMA_CRM and configure the organization model as per your requirements.
Check the below link for further explanations about Sales Area Data.
Re: CRM Middleware- Customer Master Download
Hope this helps.
Thanks.
Best Regards,
Arun Sankar.
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The Responsibility 9e.g. employee self service) is linked to a menu. The menu contains (amongst other things) functions. If the function is associated to a menu prompt, then when the user clicks on the prompt (e.g. Change Job) the function is invoked. When the function is invoked, it calls the workflow described in the function call.
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Hierarchical + Analytical query for organizational unit parameters
Hello gurus,
I try for a couples of hour ago to make a query work as I would like.
Our application need to store some parameters for our organization units. These organization units are typically organized in in an hierarchy manner: one top unit with many level of child units. The parameters are stored into another table with 1:1 relationship.
For sake of visualisation, here is the data for the organization unit and parameter table in a more visual format:
SQL> select * from organization_unit;
UNIT_CODE UNIT_NAME PARENT_UNIT_CODE
00000 Top level
10 L2 unit #10 00000
10-01 L3 unit #10-01 10
10-02 L3 unit #10-02 10
20 L2 unit #20 00000
20-01 L3 unit #20-01 20
20-02 L3 unit #20-02 20
SQL> select * from org_unit_parameters;
UNIT_CODE PARAM1 PARAM2 PARAM3 PARAM4
00000 Default value Default value Default value {null}
10 {null} Value from 10 Value from 10 {null}
10-01 {null} {null} Value from 10-01 {null}
10-02 {null} {null} {null} Value from 10-02
20 Value from 20 Value from 20 Value from 20 {null}
20-01 {null} Value from 20-01 {null} {null}
20-02 {null} Value from 20-02 {null} {null}The application will query the parameter table to get a parameter value for a given unit.
The parameter resolution algorithm is rather simple: when querying a unit, the applicable parameter is the one defined at the requested level. If the parameter is not defined (null) at the requested level, the parameter value that must be returned is the next defined one in the parent hierarchy. In some rare cases, it can be null if a parameter is not defined anywhere from the requested level to top.
I've made a query that seems to work when querying for one unit at a time. It use hierarchical operators (start with + connect by) with a bit of analytical functions. Here is a test & raw output example:
SQL> WITH hierarchy
2 AS
3 (
4 SELECT ou.unit_code,
5 LEVEL AS lvl
6 FROM organization_unit ou
7 START WITH
8 ou.unit_code = '20-01'
9 CONNECT BY
10 ou.unit_code = PRIOR ou.parent_unit_code
11 )
12 SELECT h.*,
13 p.param1 AS param1_raw,
14 LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param1_with_last,
15 FIRST_VALUE(p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param1_with_first,
16 p.param2 AS param2_raw,
17 LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param2_with_last,
18 FIRST_VALUE(p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param2_with_first,
19 p.param3 AS param3_raw,
20 LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param3_with_last,
21 FIRST_VALUE(p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param3_with_first,
22 p.param4 AS param4_raw,
23 LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param4_with_last,
24 FIRST_VALUE(p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param4_with_first
25 FROM hierarchy h
26 LEFT JOIN org_unit_parameters p
27 ON h.unit_code = p.unit_code
28 ORDER BY h.lvl DESC;
UNIT_CODE LVL PARAM1_RAW PARAM1_WITH_LAST PARAM1_WITH_FIRST PARAM2_RAW PARAM2_WITH_LAST PARAM2_WITH_FIRST PARAM3_RAW PARAM3_WITH_LAST PARAM3_WITH_FIRST PARAM4_RAW PARAM4_WITH_LAST PARAM4_WITH_FIRST
00000 3 Default value Default value Value from 20 Default value Default value Value from 20-01 Default value Default value Value from 20 {null} {null} {null}
20 2 Value from 20 Value from 20 Value from 20 Value from 20 Value from 20 Value from 20-01 Value from 20 Value from 20 Value from 20 {null} {null} {null}
20-01 1 {null} Value from 20 {null} Value from 20-01 Value from 20-01 Value from 20-01 {null} Value from 20 {null} {null} {null} {null}Seems pretty good, the upper parameters are well «propagated» down with LAST_VALUE function. But, I don't understand why the use of FIRST_VALUE and oppposite ordering doesn't give the same result. A little more playing with the last query for getting the final result for a given unit code:
SQL> SELECT *
2 FROM
3 (
4 WITH hierarchy
5 AS
6 (
7 SELECT ou.unit_code,
8 LEVEL AS lvl
9 FROM organization_unit ou
10 START WITH
11 ou.unit_code = '20-01'
12 CONNECT BY
13 ou.unit_code = PRIOR ou.parent_unit_code
14 )
15 SELECT h.*,
16 LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param1,
17 LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param2,
18 LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param3,
19 LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param4
20 FROM hierarchy h
21 LEFT JOIN org_unit_parameters p
22 ON h.unit_code = p.unit_code
23 ORDER BY h.lvl
24 )
25 WHERE ROWNUM = 1;
UNIT_CODE LVL PARAM1 PARAM2 PARAM3 PARAM4
20-01 1 Value from 20 Value from 20-01 Value from 20 {null}Works well!
But, my ultimate goal is to create a view that resolve correctly all these parameters for each level of the organization with proper propagation rather then querying for each unit at a time. I played a bit, but without success. :( My current raw query is this one:
SQL> WITH hierarchy
2 AS
3 (
4 SELECT ou.unit_code,
5 LPAD(' ',2*(LEVEL-1)) || ou.unit_code AS tree,
6 LEVEL AS lvl
7 FROM organization_unit ou
8 START WITH
9 parent_unit_code IS NULL
10 CONNECT BY
11 PRIOR unit_code = parent_unit_code
12 )
13 SELECT h.*,
14 p.param1 AS param1_raw,
15 LAST_VALUE (p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param1_with_last,
16 FIRST_VALUE(p.param1 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param1_with_first,
17 p.param2 AS param2_raw,
18 LAST_VALUE (p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param2_with_last,
19 FIRST_VALUE(p.param2 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param2_with_first,
20 p.param3 AS param3_raw,
21 LAST_VALUE (p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param3_with_last,
22 FIRST_VALUE(p.param3 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param3_with_first,
23 p.param4 AS param4_raw,
24 LAST_VALUE (p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl DESC) AS param4_with_last,
25 FIRST_VALUE(p.param4 IGNORE NULLS) OVER (ORDER BY h.lvl ASC) AS param4_with_first
26 FROM hierarchy h
27 LEFT JOIN org_unit_parameters p
28 ON h.unit_code = p.unit_code
29 ORDER BY h.unit_code;
UNIT_CODE TREE LVL PARAM1_RAW PARAM1_WITH_LAST PARAM1_WITH_FIRST PARAM2_RAW PARAM2_WITH_LAST PARAM2_WITH_FIRST PARAM3_RAW PARAM3_WITH_LAST PARAM3_WITH_FIRST PARAM4_RAW PARAM4_WITH_LAST PARAM4_WITH_FIRST
00000 00000 1 Default value Default value Default value Default value Default value Default value Default value Default value Default value {null} Value from 10-02 {null}
10 10 2 {null} Value from 20 Default value Value from 10 Value from 10 Default value Value from 10 Value from 10 Default value {null} Value from 10-02 {null}
10-01 10-01 3 {null} {null} Default value {null} Value from 20-02 Default value Value from 10-01 Value from 10-01 Default value {null} Value from 10-02 Value from 10-02
10-02 10-02 3 {null} {null} Default value {null} Value from 20-02 Default value {null} Value from 10-01 Default value Value from 10-02 Value from 10-02 Value from 10-02
20 20 2 Value from 20 Value from 20 Default value Value from 20 Value from 10 Default value Value from 20 Value from 10 Default value {null} Value from 10-02 {null}
20-01 20-01 3 {null} {null} Default value Value from 20-01 Value from 20-02 Default value {null} Value from 10-01 Default value {null} Value from 10-02 Value from 10-02
20-02 20-02 3 {null} {null} Default value Value from 20-02 Value from 20-02 Default value {null} Value from 10-01 Default value {null} Value from 10-02 Value from 10-02As you can see, it's not as I expected. I know there's something to do with a PARTITION BY clause, but don't know how.
Is anyone knows how to solve my problem?
Thanks
Bruno
For reproductibility purposes, here is the code to create sturcture and data:
Here is the format of my tables and some samble data:
CREATE TABLE organization_unit (
unit_code VARCHAR2(5 CHAR) NOT NULL PRIMARY KEY,
unit_name VARCHAR2(100 CHAR) NOT NULL,
parent_unit_code VARCHAR2(5 CHAR)
CREATE TABLE org_unit_parameters (
unit_code VARCHAR2(5 CHAR) NOT NULL PRIMARY KEY,
param1 VARCHAR2(100 CHAR),
param2 VARCHAR2(100 CHAR),
param3 VARCHAR2(100 CHAR),
param4 VARCHAR2(100 CHAR)
-- Inserting data
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('00000', 'Top level', NULL);
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('10', 'L2 unit #10', '00000');
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('10-01', 'L3 unit #10-01', '10');
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('10-02', 'L3 unit #10-02', '10');
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('20', 'L2 unit #20', '00000');
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('20-01', 'L3 unit #20-01', '20');
INSERT INTO organization_unit (unit_code, unit_name, parent_unit_code)
VALUES ('20-02', 'L3 unit #20-02', '20');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3)
VALUES ('00000', 'Default value', 'Default value', 'Default value');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2, param3)
VALUES ('10', 'Value from 10', 'Value from 10');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param3)
VALUES ('10-01', 'Value from 10-01');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param4)
VALUES ('10-02', 'Value from 10-02');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param1, param2, param3)
VALUES ('20', 'Value from 20', 'Value from 20', 'Value from 20');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2)
VALUES ('20-01', 'Value from 20-01');
INSERT INTO ORG_UNIT_PARAMETERS (unit_code, param2)
VALUES ('20-02', 'Value from 20-02');
COMMIT;Now, I hoppe I got your reqs:
WITH hierarchy AS (
SELECT ou.unit_code,
LPAD(' ',2*(LEVEL-1)) || ou.unit_code AS tree,
LEVEL AS lvl,
param1 AS param1_raw,
param2 AS param2_raw,
param3 AS param3_raw,
param4 AS param4_raw,
SYS_CONNECT_BY_PATH(p.param1,'#') || '#' AS param1_path,
SYS_CONNECT_BY_PATH(p.param2,'#') || '#' AS param2_path,
SYS_CONNECT_BY_PATH(p.param3,'#') || '#' AS param3_path,
SYS_CONNECT_BY_PATH(p.param4,'#') || '#' AS param4_path
FROM organization_unit ou LEFT JOIN org_unit_parameters p
ON ou.unit_code = p.unit_code
START WITH parent_unit_code IS NULL
CONNECT BY PRIOR ou.unit_code = parent_unit_code
SELECT unit_code,
tree,
lvl,
param1_raw,
REGEXP_SUBSTR(param1_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param1_path,'[^#]+'))) AS param1_with_last,
REGEXP_SUBSTR(param1_path,'[^#]+') AS param1_with_first,
param2_raw,
REGEXP_SUBSTR(param2_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param2_path,'[^#]+'))) AS param2_with_last,
REGEXP_SUBSTR(param2_path,'[^#]+') AS param2_with_first,
param3_raw,
REGEXP_SUBSTR(param3_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param3_path,'[^#]+'))) AS param3_with_last,
REGEXP_SUBSTR(param3_path,'[^#]+') AS param3_with_first,
param4_raw,
REGEXP_SUBSTR(param4_path,'[^#]+',1,GREATEST(1,REGEXP_COUNT(param4_path,'[^#]+'))) AS param4_with_last,
REGEXP_SUBSTR(param4_path,'[^#]+') AS param4_with_first
FROM hierarchy
ORDER BY unit_code
UNIT_ TREE LVL PARAM1_RAW PARAM1_WITH_LAST PARAM1_WITH_FIRS PARAM2_RAW PARAM2_WITH_LAST PARAM2_WITH_FIRS PARAM3_RAW PARAM3_WITH_LAST PARAM3_WITH_FIRS PARAM4_RAW PARAM4_WITH_LAST PARAM4_WITH_FIRS
00000 00000 1 Default value Default value Default value Default value Default value Default value Default value Default value Default value
10 10 2 Default value Default value Value from 10 Value from 10 Default value Value from 10 Value from 10 Default value
10-01 10-01 3 Default value Default value Value from 10 Default value Value from 10-01 Value from 10-01 Default value
10-02 10-02 3 Default value Default value Value from 10 Default value Value from 10 Default value Value from 10-02 Value from 10-02 Value from 10-02
20 20 2 Value from 20 Value from 20 Default value Value from 20 Value from 20 Default value Value from 20 Value from 20 Default value
20-01 20-01 3 Value from 20 Default value Value from 20-01 Value from 20-01 Default value Value from 20 Default value
20-02 20-02 3 Value from 20 Default value Value from 20-02 Value from 20-02 Default value Value from 20 Default value
7 rows selected.
SQL> SY.
Edited by: Solomon Yakobson on Nov 12, 2010 10:09 AM -
View of organizational unit in Service request
Hi everyone,
In our service request, we are trying to visualise all the organizational unit (of the organization model) of a BP.
We achieve to see the direct service group where the BP is assigned but we are trying to see more of the link to the organizational model.
For example : our organizational model looks like this:
For user AJAUSSAUD1, I can see the direct link to PSE Equiment in my service request (this is determined in the partner schema determination)
However, we would like to be able to see MC1 (here 3 level above) in the service request.
We are using service organization as function and all the organizational unit are determined as service organization as we are using it to authorizations access.
Does anyone know if there is a way to see the link with all the organizational unit of a user in a service request?
Would it be with the attribute available in the ppoma-crm, but how to add the field and make them available in the service request view?
Thank you,
Regards,
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As far as I know, there is no standard way to view an organizational hierarchy in a service request. You will need to do some developments. There are two options -
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Remember once these 3 fields are added at database level, they are available for all transaction types of one order. These fields can be made available to BW queues also at time of adding them.
2. If you do not want the 3 org levels to be stored in data base table
This would mean you only want these fields for display to end user.
Add 3 model nodes in the web ui component. In the getter method of 1st field, add select query or call function to get parent of determined service org. Similarly for other 2 fields.
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EXPORTING
act_otype = 'O'
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act_wegid = lv_wegid
act_begda = lv_effective_date
act_endda = lv_effective_date
act_tdepth = 1
act_tflag = ''
act_vflag = ''
authority_check = 'X'
TABLES
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EXCEPTIONS
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no_entry_found = 2
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Organizational Unit is managed by Position
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In which table i can get this relation ship.hai..
standard reports are available in easy access
Existing Organizational Units (Report RHXEXI00)
Staff Functions for Organizational Units (Report RHXSTAB0)
Organizational Structure with Persons (Report RHXSTR02)
Organizational Structure with Work Centers (Report RHXSTR02)
Existing Jobs (Report RHXEXI02)
Job Index (Report RHSTEL00)
Job Description (Report RHXDESC0)
Complete Job Description (Report RHXSCRP0)
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Staff Assignments (Report RHSBES00)
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Planned Labor Costs (Report RHSOLO00/RHXSOLO00)
Vacant Positions (Report RHVOPOS0)
Obsolete Positions (Report RHVOPOS1)
Complete Position Description (Report RHXSCRP1)
Reporting Structure without Persons (Report RHSTR05)
Reporting Structure with Persons (Report RHSTR04)
Existing Work Centers (Report RHXEXI05)
Work Centers per Organizational Unit (Report RHXSTRU06)
Existing Tasks (Report RHXEXI04)
Activity Profile of Positions (Report RHXSTR07)
Activity Profile of Positions with Persons (Report RHXSTR08)
Existing Objects (Report RHEXIST0)
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Hi All,
I had a requirement for bulk upload of Appraisal documents.
I am an ABAP Consultant.
Here client wants the Employee group as a Selection Criteria.
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Actually this is my requirement and if any alternate solutions & suggestions are also welcome.
Thanks for your time.
Edited by: nayani pavan on Dec 30, 2008 3:17 PMHi Madhu,
Thanks for your reply, it is helpful and I need this query.
Suppose for an organizational unit there will be subordinate organizational unit.
That means how can I found whether is there any subordinate organizational unit for any organizational unit.
Hi Ananth,
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Edited by: nayani pavan on Dec 30, 2008 3:56 PM -
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http://docs.oracle.com/cd/E27559_01/dev.1112/e27150/toc.htm
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CRM 7.0, sales order is using org rule ORGMAN_23 which has FM CRM_ORGMAN_ORGOBJECTS_FIND_11
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CRM_ORGMAN_ORGOBJECTS_FIND_1
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CRM_ORGMAN_ORGOBJECTS_FIND_3 ......
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You need to adjust your org structure in ppoma_crm.
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(If you are using rule ORGMAN_23).
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Best regards,
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Existing CRM orgnization unit master data
Tab Funtion:
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- Sales Office: 0100
- Sales Group: blank
Tab attribute:
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We would like to maintain multile R/3-Sales groups to a CRM-Organization Unit.
Sales group: 10A, 10B, 10C, 10D
Would someone know how this requirement can be fixed ?
ThanksHi Marisa,
Multiple Sales Groups can be assigned to a single Sales Ofifice through "Enhanced Org Structure". Please run the report CRMC_ORGMAN_SWITCH_TO_ENH_MODEL to convert the standard org structure into an enhanced structure.
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middleware developerHello נתן,
Thanks for using Apple Support Communities.
Follow the instructions in the following article to restore your iPhone to its factory settings:
Use iTunes to restore your iOS device to factory settings
http://support.apple.com/kb/ht1414
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CPU Upgrade on Satellite L30-134
Has anyone managed to upgrade the CPU on one of these yet??? Ive already maxed out the memory, but its still a bit slow if you know what I mean...:P Ive been looking at the Core2 SLV3W 2x1.33Ghz, same operating temperature and FSB, both socket 478/9
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I'm trying to install CS2 on a mac OS X version 10.9.4. When I try to open the installer file I get a message "You can't open the application Adobe Installer because PowerPC applications are no longer supported. Does anyone know what I should do?
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Purchasing music from Ipad within Itunes
I had purchased a song, downloaded it and then could not find in my Ipad. I went to download again and ended up having to buy the song again. I ended up connecting to my computer and downloading the song this way. Anyone know what I might have done w
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I get error 13019 when syncing my nano. I never had sync music checked, always did it manually. When plugged in it shows that the music is on there but as soon as i disconnect it shows that it was never there. How can i fix this?
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Hi--- I am trying to see the connected users in my database, but i can see all users are in INACTIVE status what does it mean. i am using TOAD to see this view, in another window(putty) i connected with other user lets say "scott" and i am accessing