Noob question about trying to duplicate rows in a table

Simplification of problem is I've got a table with user_id, name, year where user_id is pk. I would like to take all the rows that match year=2008 and insert them into the same table, but start the user_id at a certain number and set year=2009.
I know this doesn't work, but it's what I want to do in noob-code:
INSERT into TABLE (
user_id, name, year
) VALUES (
SELECT user_id_seq.nextval after starting at 3500, name, 2009 from same table doing insert to where year = 2008
I've contemplated using a temporary table, I've also seen mention of cursors, but don't quite understand what they are. I'm really, really new to Oracle and SQL in general, but am familiar with programming and shell scripts. I know more in depth searching might land me what I want, but I think my search syntax would be just as weak as my knowledge of the material. I'm just thinking this is something so basic and easy that my searches aren't using the right terms to catch a hit.

Hi,
Welcome to the forum!
You can INSERT all the results of a query by substituting the query where you otherwise would have "VALUES (list)".
For example:
INSERT into TABLE_X
       (user_id,              name, year)
SELECT user_id_seq.NEXTVAL, name, 2009
FROM    table_x
WHERE   year = 2008;This assumes that the sequence user_id_seq exists and is ready to issue the correct value. (It's unclear if that's part of the problem.)
Temporary tables and cursors (which are a way of getting query results in PL/SQL) are only useful for inserting in rare situations, where you have to do very odd, convoluted things. Think (at least) twice about how to do what you need to in SQL, and if you can't think of a way, then ask.
Yes, basic things often are hard to search for, especially if you don't know the right terms.
There are several good teach-yourself SQL books that explain this kind of thing. Getting one would be a good investment.
[All the Oracle manuals|http://www.oracle.com/pls/db111/portal.all_books] are on line. There's an example of this in the SQL Reference manual, under THE INSERT command.
Edited by: Frank Kulash on Nov 26, 2008 12:59 PM
Clarified usefulness of cursors. They have a lot of good, common functions, but helping with INSERTs is not one of them.

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Thanks.
Message Edited by jermin on 06-24-2008 02:09 PM

Re: 2 noob questions about speaker settings?slightlys I have a slightly different set up.
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How to eliminate the duplicate rows in the table

How can we eliminate the duplicate rows in the table. Is it possible to write a single query or should we write a pl/sql block to do it

Scope works outwards.
SQL> DECLARE
2    n NUMBER;
3 BEGIN
4    n := 0;
5    DECLARE
6      n number;
7    BEGIN
8      n := 2;
9      dbms_output.put_line(n);
10    END;
11 END;
12 /
2
PL/SQL procedure successfully completed.
SQL> DECLARE
2    n NUMBER;
3 BEGIN
4    n := 0;
5    DECLARE
6      x number;
7    BEGIN
8       dbms_output.put_line(n);
9       n := 2;
10        dbms_output.put_line(n);
11    END;
12 END;
13 /
0
2
PL/SQL procedure successfully completed.
SQL> ed
Wrote file afiedt.buf
1 DECLARE
2    n NUMBER;
3 BEGIN
4    n := 0;
5    DECLARE
6      x number;
7    BEGIN
8       dbms_output.put_line(n);
9       x := 2;
10     END;
11       dbms_output.put_line(x);
12 EXCEPTION
13     WHEN others THEN      dbms_output.put_line('oh no!');
14* END;
15 /
     dbms_output.put_line(x);
ERROR at line 11:
ORA-06550: line 11, column 27:
PLS-00201: identifier 'X' must be declared
ORA-06550: line 11, column 6:
PL/SQL: Statement ignored
SQL> Cheers, APC

Need to remove duplicate rows from a table

Hi Gurus ,
I am using oracle 11.2.0.3 .
SQL> desc osstage.S_EVT_ACT_X;
Name                                      Null?    Type
ROW_ID                                    NOT NULL VARCHAR2(15 CHAR)
LAST_UPD                                  NOT NULL DATE
PAR_ROW_ID                                NOT NULL VARCHAR2(15 CHAR)
ATTRIB_17                                          NUMBER(22,7)
ATTRIB_26                                          DATE
ATTRIB_02                                          VARCHAR2(100 CHAR)
PROCESS_TIMESTAMP                                  TIMESTAMP(6);
now when i give the below command it gives the error as someone has disabled the constraint accidently .
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1;
Error starting at line 3 in command:
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1
Error report:
SQL Error: ORA-02437: cannot validate (OSSTAGE.S_EVT_ACT_X_P1) - primary key violated
02437. 00000 - "cannot validate (%s.%s) - primary key violated"
*Cause:    attempted to validate a primary key with duplicate values or null
           values.
*Action:   remove the duplicates and null values before enabling a primary
           key.
Can you please guide me with this issue .

Please refer
Script: Deleting Duplicate Rows from a Table (Doc ID 31413.1)
How to Find or Delete Duplicate Rows in a Table (Doc ID 1004425.6)

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SQL Server 2014 - Delete duplicate rows in a table except one

Hi all,
I have a table that contains duplicate rows. Using grouping I can easily identify those rows.
As of now, I count the grouped records and copy one of the group in a temporary table together with its count of elements. Than I loop over this table and delete N - 1 rows of each group from the original table. Unfortunately this is done with two cursors
and WHILE loops.
Is anybody out there who could give some hints how to handle deletion of duplicated rows leaving one in place using pure SQL? I tried a full delete of all elements of a group and then an INSERT of one row to recreate a row again. But this is not
very elegant and close to using cursors.
Regards Uwe

Hi all,
based on input below from Uri, I have developed a little more general solution for removal of duplicates. I did that, because I'm sure that for many beginners in SQL it is easier specialize a proposal by removing parts of it than adding new functionality.
Here is my code.
-- Remove duplicates from a table and document the deleted rows
DECLARE @MyTable Table (Col1 int, Col2 int, Col3 int, Col4 int);
DECLARE @OutTable Table (Col1 int, Col2 int, Col3 int, Col4 int);
INSERT INTO @MyTable VALUES
(1, 10, 100, 7),
(2, 20, 200, 2),
(2, 20, 200, 1),
(3, 30, 300, 3),
(1, 10, 200, 4),
(1, 10, 100, 5),
(1, 10, 100, 6);
WITH cte (RN, Col1, Col2, Col3, Col4)
AS (SELECT ROW_NUMBER() OVER (PARTITION BY Col1, Col2, Col3 ORDER BY (SELECT 0)) AS RN, Col1, Col2, Col3, Col4
FROM @MyTable)
DELETE FROM cte
OUTPUT DELETED.Col1, DELETED.Col2, DELETED.Col3, DELETED.Col4
INTO @OutTable (Col1, Col2, Col3, Col4)
WHERE RN > 1;
SELECT * FROM @OutTable;
And this is the result:
The MS 139444 article Satish mentioned is focussed on duplicate PKs removal. Thanks for the hint.
Thanks to you all for your rapid response.
Regards Uwe

Duplicate rows in 5 table

I have five tables(A,B,C,D,E), and I am trying to check for duplicate rows in all the tables, I tried using inner join, but the first three join did not return any table. is there another way.the tables only have two columns , the email(different values)
and authour (which is the same person in the table)
when i tried
select * from TABLE A
INNER JOIN TABLE B
ON TABLEA. EMAIL = TABLEB.EMAIL
INNER JOIN TABLEC
ON TABLEA.EMAIL=TABLEC.EMAIL
it came back with no result, the other way I am thinking is to unioun all all the tables and try to use count and group by ,but this will only show me the duplicates and not the authours
please any other way

it came back with no result, the other way I am thinking is to unioun all all the tables and try to use count and group by (but I could not insert my result in a new table)
please any other way
I dont understand your point here...Are you trying the below?
Create Table T1(name varchar(50),Email Varchar(50))
Insert into T1 Values('SQL','[email protected]'),('.NET','[email protected]')
Create Table T2(name varchar(50),Email Varchar(50))
Insert into T2 Values('Server','[email protected]'),('BizTalk','[email protected]')
Create Table T3(name varchar(50),Email Varchar(50))
Insert into T2 Values('Sql','[email protected]'),('server','[email protected]')
;With cte as
(Select * From T1
Union All
Select * From T2
Union All
Select * From T3)
Select name,email, count(1) From cte Group by name , email having count(1)>1
Drop table T1,T2,T3
I was able to insert the union product in a table, and i used this
SELECT EMAIL,AUTHOR,COUNT(EMAIL) AS AMOUNT FROM ALLEMAIL
GROUP BY AUTHOR,EMAIL
ORDER BY AMOUNT DESC, email desc
but its showing the email and the count but its appearing like the duplicate is only associated with one authour

First attempt to remove duplicate rows from a table...

I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
tell application "Numbers"
activate
tell document 1
-- DETERMINE THE CURRENT SHEET
set currentsheetindex to 0
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of (tables whose selection range is not missing value)
end tell
if x is not 0 then
set the currentsheetindex to i
exit repeat
end if
end repeat
if the currentsheetindex is 0 then error "No sheet has a selected table."
-- GET THE TABLE WITH CELLS
tell sheet currentsheetindex
set the current_table to the first table whose selection range is not missing value
end tell
end tell
log current_table
tell current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
repeat with i from 1 to (z - 1)
set m to m & value of (cell i of row j)
end repeat
set value of cell z of row j to m
end repeat
set MyRange to value of every cell of column z
repeat with i from 1 to (count of items of MyRange)
set n to item i of MyRange
if n is in list1 then
set end of list1 to "Delete"
else
set end of list1 to n
end if
end repeat
repeat with i from (count of items of list1) to 1 by -1
set n to item i of list1
if n = "Delete" then remove row i
end repeat
remove column z
end tell
end tell
Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
Thanks,
Jason
Message was edited by: jaxjason

Hi jason
I hope that with the added comments it will be clear.
Ask if something is always opaque.
set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
tell application "Numbers09"
tell document current_Doc to tell sheet current_Sheet to tell table current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
tell row j
repeat with i from 1 to (z - 1)
set m to m & value of cell i
end repeat
set value of cell z to m
end tell
end repeat
set theRange to value of every cell of column z
repeat with i from (count of items of theRange) to 1 by -1
(* As I scan the table backwards (starting from the bottom row),
I may remove a row immediately when I discover that it is a duplicate *)
set n to item i of theRange
if n is in list1 then
remove row i
else
set end of list1 to n
end if
end repeat
remove column z
end tell
end tell
--=====
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers09" to tell document 1
set theSheet to ""
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
(* Open a trap to catch the selection range.
The structure of this item
«class
can't be coerced as text.
So, when the instruction (selection range of table y) as text
receive 'missing value' it behaves correctly and the lup continue.
But, when it receive THE true selection range, it generates an error
whose message is errMsg and number is errNum.
We grab them just after the on error instruction *)
try
(selection range of table y) as text
on error errMsg number errNum (*
As we reached THE selection range, we are here.
We grab the errMsg here. In French it looks like:
"Impossible de transformer «class
The handler cuts it in pieces using quots as delimiters.
item 1 (_) "Impossible de transformer «class » "
item 2 (theRange) "A2:M25"
item 3 (_) " of «class NmTb» "
item 4 (theTable) "Tableau 1"
item 5 (_) " of «class NmSh» "
item 6 (theSheet) "Feuille 1"
item 7 (_) " of document "
item 8 (theDoc) "Sans titre"
item 9 ( I drop it ) " of application "
item 10 ( I drop it ) "Numbers"
item 11 (I drop it ) " en type string."
I grab these items in the list
{_, theRange, _, theTable, _, theSheet, _, theDoc}
Yes, underscore is a valid name of variable.
I often uses it when I want to drop something.
An alternate way would be to code:
set ll to my decoupe(errMsg, quote)
set theRange to item 2 of ll
set theTable to item 4 of ll
set theSheet to item 8 of ll
set theDoc to item 10 of ll
it works exactly the same but it's not so elegant.
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
exit repeat (*
as we grabbed the interesting datas, we exit the lup indexed by y.*)
end try
end repeat -- y
if theSheet > "" then exit repeat (*
If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
end if
end tell -- sheet
end repeat -- i
(* We may arrive here with two kinds of results.
if we grabbed a selection, theSheet is something like "Feuille 1"
if we didn't grabbed a selection, theSheet is the "" defined on entry
and we generate an error which is not trapped so it stops the program *)
if theSheet = "" then error "No sheet has a selected table."
end tell -- document
(* Now, we send to the caller the interesting datas :
theRange "A2:M25"
theTable "Tableau 1"
theSheet "Feuille 1"
theDoc "Sans titre" *)
return {theRange, theTable, theSheet, theDoc}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d (*
Cut the text t in pieces using d as delimiter *)
set l to text items of t
set AppleScript's text item delimiters to "" (*
Resets the delimiters to the standard value. *)
(* Send the list to the caller *)
return l
end decoupe
--=====
Have fun
And if it's not clear enough, you may ask for more explanations.
Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19)

Question about the MAKZN field in the RBKP table

Hello all.
I have a question about the MAKZN field. Does anyone know what field in MIRO is assigned to this field? We have an issue where a line item amount was not selected invoice was out of balance but the agent selected accept and post. And invoice posted. but I am interested in knowing where the amount if keyed in because when I go to the RBKP table I see an amount entered in the MAKZN (manually accept net difference amount)

Hi,
it seems as if the value was calculated internally:
program SAPLMR1M
dynpro 6000
PAI module fcode_6000
Include LMR1MI3W
*-------- buchen ------------------------------------------------------*
    WHEN fcobu OR fcomanak.
*--- identical code in PAI Module FCODE_6250 --------------------------*
      PERFORM ota_check USING vf_kred-xcpdk rbkpv-xcpdd
                        CHANGING rc.
      IF rc NE 0.
        CLEAR ok-code.
        EXIT.
      ENDIF.
      IF ok-code = fcomanak.
        PERFORM diff_akzeptieren.
        ok-code = fcobu.
      ENDIF.
where:
fcomanak          LIKE ok-code VALUE 'MANAK', " Manuell akzeptiert
*&      Form DIFF_AKZEPTIEREN
*       Differenz manuell akzeptieren
FORM diff_akzeptieren.
*       Manuell akzeptierter Betrag
    rbkpv-makzn = rbkpv-makzn + rbkpv-diffn.
    rbkpv-makzmw = rbkpv-makzmw + rbkpv-diffmw.
*       Differenzbeträge
    CLEAR: rbkpv-diffn, rbkpv-diffmw.
ENDFORM.                             " DIFF_AKZEPTIEREN
maybe it´s happenning when releasing manually the invoice in MRBR?
Best regards.

Urgent - Deletion of duplicate rows in a table - Help me

Hi friends,
Here is my purchase_order_line table desc,
SQL> desc purchase_order_line;
Name Null? Type
PURCHASE_ORDER_LINE_ID NOT NULL NUMBER
DESTINATION_ID NOT NULL NUMBER
PURCHASE_ORDER_ID NOT NULL NUMBER
LINE_NO NOT NULL NUMBER
PART_NO VARCHAR2(10)
PART_DESC NOT NULL VARCHAR2(100)
ORDER_QTY NOT NULL NUMBER
ORDER_DATE NOT NULL DATE
DUE_DATE DATE
VERSION_NO NOT NULL NUMBER
VERSION_DATE NOT NULL DATE
purchase_order_line_id is a primary key.
If you ignore the primary key column temporarily,
for the rest of 2 to 11 columns, i have a duplicate data in this table.
I want to clear out all duplicates.
Suppose if I have 3 similar rows(exclude primarykey), then delete first two rows and leave the last one.
OR delete last two rows and leave the first one.
What is the best solution for this ?
thanks for help.
Sridhar

here is some example that might be of help.
SQL> select case_number, case_status_desc status, case_ownr owner,
2         case_yr year, doc_id
3 from wrt_case
4 order by doc_id;
CASE_NUMBER          STATUS     OWNER YEAR      DOC_ID
2006-786             ACTIVE     E     2006    22072734
2006-786             ACTIVE     E     2006    22072734
2006-786             ACTIVE     E     2006    22081673
2006-786             ACTIVE     E     2006    22081673
2006-786             ACTIVE     E     2006    22143005
2006-786             ACTIVE     E     2006    22143005
2006-786             ACTIVE     E     2006    22243094
2006-786             ACTIVE     E     2006    22243094
8 rows selected.
SQL> Select case_number, case_status_desc status, case_ownr owner,
2                 case_yr year, doc_id, rowid,
3                 row_number() over (partition by doc_id order by doc_id) as rn
4    From wrt_case;
CASE_NUMBER          STATUS     OWNER YEAR      DOC_ID ROWID                      RN
2006-786             ACTIVE     E     2006    22072734 AAD8bTAAJAAAJ4nAAA          1
2006-786             ACTIVE     E     2006    22072734 AAD8bTAAJAAAJ4nAAC          2
2006-786             ACTIVE     E     2006    22081673 AAD8bTAAJAAAJ4nAAB          1
2006-786             ACTIVE     E     2006    22081673 AAD8bTAAJAAAJ4nAAD          2
2006-786             ACTIVE     E     2006    22143005 AAD8bTAAJAAAJ4nAAE          1
2006-786             ACTIVE     E     2006    22143005 AAD8bTAAJAAAJ4nAAF          2
2006-786             ACTIVE     E     2006    22243094 AAD8bTAAJAAAJ4nAAG          1
2006-786             ACTIVE     E     2006    22243094 AAD8bTAAJAAAJ4nAAH          2
8 rows selected.
SQL> Delete From wrt_case
2   Where rowid in (Select t.rid
3                     From (Select case_number, case_status_desc status, case_ownr owner,
4                                  case_yr year, doc_id, rowid as rid,
5                                  row_number() over (partition by doc_id order by doc_id) as rn
6                             From wrt_case) t
7                   Where t.rn > 1);
4 rows deleted.
SQL> select case_number, case_status_desc status, case_ownr owner,
2         case_yr year, doc_id, rowid
3 from wrt_case
4 order by doc_id;
CASE_NUMBER          STATUS     OWNER YEAR      DOC_ID ROWID
2006-786             ACTIVE     E     2006    22072734 AAD8bTAAJAAAJ4nAAA
2006-786             ACTIVE     E     2006    22081673 AAD8bTAAJAAAJ4nAAB
2006-786             ACTIVE     E     2006    22143005 AAD8bTAAJAAAJ4nAAE
2006-786             ACTIVE     E     2006    22243094 AAD8bTAAJAAAJ4nAAG
SQL>

Noob questions about front row and back up...

Dear all,
Please can you assist with the following for a proud new mac owner?
1) Why do some songs/albums not play in front row but work in itunes?
2) I have an external hard drive, iomega 500gb, which is very noisy. So i keep it switched off from the back. Can time machine still back up or does the external HDD have to be switched on?
Many thanks...

Hi Fireball Dragon
1. I don't have a definite answer for you, but it sounds like a problem with your iTunes Library or the way you Imported your music into it. Go to: *Applications > Utilities > Disk Utility* and run *Disk Utility Repair Permissions.*
Also how are you selecting Music to play in Front Row, Shuffle or by Albums, Artist, Songs?
2. No Time Machine will not backup with the External HD turned off, but it will resume backup as soon as it is switched on mounted. I personally don't run Time Machine backups every hour, I only switch it on for a few backups every day or after adding important files.
Dennis

Noob question about DIV tags

Learning DW and CSS so patience is in order .
I've being reading numerous posts here and on the web about avoiding tables for laying out web pages. I can see the advantages in terms of cleaner codes and easiness of updating and changing sites at a later time. So I started learning about DIV tags (although tables is very easy for me) and have practice a few times with fairly good results, love the absolute positioning with it. Having said that, for the love of me, can't find a way of centering horizontally a page designed with DIV tags (due to ignorance), for example, 1 column/three rows page, after defining styles, size and colors I enclosed everything in another DIV tag, wrapper I think is called, but have not found a way of centering it on the page, text-aligment on the DIV tag only centers the text not the DIV itself, how to go about this? Help is appreciated.

love the absolute positioning with it.
Get over it. It's a trojan horse. Absolute positioning is not a general layout method.
To center ANY block (non-absolutely positioned) element, use CSS to give it a width and left/right margins of 'auto'. For example -
<div id="foo">...</div>
That div will be centered with this CSS -
#foo { width:300px; margin:0 auto; }
I think you are on the wrong path already, though. Stick with tables (which you say are very easy for you) UNTIL you a) understand CSS well enough to understand what absolute positioning is and why I say it's bad, and b) understand how to use float, margin, and padding to place things on the page. Then you are ready to move away from tables.

Ultra-noob question about creating clips

Sorry if this is answered elsewhere - I don't even know where to look.
I'm working on a simple editing project. I've sucked in (I forget the proper term) an entire DV tape of material into one big file. Now I'm trying to pick out the good shots and save them as separate clips - about 50 of them. These clips will then be converted to a different format and reassembled using some special software outside of FCE to create an interactive web video.
There seem to be about a gajillion ways of doing this. Master clips, independent clips, sub-clips. Right now I'm having a problem with clip names because of the master/associate business. I want to organize individual clips into folders (Folder A -> Clips A1, A2, A3, etc). But when I try to name a clip, ALL the names change. And no amount of setting the clip as Independent seems to affect it. Not only that, but I'm so green I still can't figure out what to highlight - the clip in the timeline or the clip in the folder or both.
Can someone point me in the right direction? I don't even know what to ask.

G'Day ap0110,
Welcome aboard the FCE forum.
Here is another method:
Double click the long clip in the Browser and it opens in the Viewer.
Mark an In and Out point in the Viewer. You will have two black triangles facing one-another in the Viewer scrubber bar when completed. Notice the bit in between the triangles is lighter in color than the rest. This bit can be made into a re-namable Sub-Clip.
Go to Modify> Make Subclip. Command-U (keyboard shortcut).
The modified clip now appears in the Browser ready to be re-named. Enter new name.
Do this as many times as required.
Right click in the Browser and a pop up appears with an option to create a _New Bin_.
Drag the newly named Sub Clips into a Bin of your choice.
Al

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