OS command Encryption

Hi Guys,
I am trying to encrypt a file from XI and FTP to a different location. I am using PGP software for encryption and decryption. I am able to encrypt/decrypt the file from the OS level. The command I am using at OS level is:
pgp --home-dir /.pgp --encrypt test.txt --recipient 0xC483S9E6
If I use the same command in Sender File adapter in Run Operating System Command After Processing it is not encrypting. Now if I run the entire scenario the file is writing but it is not encrypting the file. Can you tell me where I am exactly going wrong?
---Satish

Hi,
Try using the full path while calling.
Better use a batch file where you can write all the code and call the batch file from the adapter.
First ensure that the batch file is called, say for example write a command like MD
server\foldet\Test and see if the folder Test is created. This will ensure you that the batch file is being triggered.
I was facing this kind of problem and I solved it by doing another scenario which just reads a file and saves with the same name in the same path. In this scenario call the batch file this will encrypt. My be this looks bit untidy but you can use this as a work around.
Thanks,
Prakash

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I have a disk without "Windows" and "Program Files" Folder with the userprofiles without a backup of recovery agent and related certificates.
By USMT or in another way it is possible a deployment and recovery (also partial) of these userprofiles folders? These data can be accessible in some way or there are lost forevar?
During USMT deployment by scanstate/loadstate cmdline tools: I used to be specify a KeyString
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Thank you.

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Hetti
Arachchige V Aravinda had written is very important to know when you copy or move ecrypted folder and files in a different partition or in a another disk.
Thanks Hetti
Arachchige V Aravinda for your good info and tips.

Please help me with my code (has conversion from string to int)

import javax.microedition.midlet.*;
import javax.microedition.lcdui.*;
public class Test3 extends MIDlet implements CommandListener
{   Form mForm;
    Command mCommandQuit;
    Command mCommandItem;
    TextField input,prime1,prime2,prime3,output;
    Display mDisplay;
    int i,j=0,k1,k2,p,q,b;
    //int [] current=new int [1000];
    String mstring,a="";
    String [] temp=new String [1000];
    public void startApp()
    {System.out.println("startApp");
     mForm=new Form("RSA Encryption");
     mCommandQuit=new Command("QUIT",Command.EXIT,0);
     mCommandItem=new Command("ENCRYPT",Command.ITEM,0);
     mForm.append("Enter text:\n");
     input=new TextField(null,"",100, TextField.ANY);
     mForm.append(input);
     mForm.append("Enter first prime number(p):\n");
     prime1=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime1);
     mForm.append("Enter second prime number(q):\n");
     prime2=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime2);
     mForm.append("Enter d:\n");
     prime3=new TextField(null,"",100, TextField.ANY);
     mForm.append(prime3);
     mForm.addCommand(mCommandQuit);
     mForm.addCommand(mCommandItem);
     mDisplay=Display.getDisplay(this);
     mDisplay.setCurrent(mForm);
     mForm.setCommandListener(this);
    public void pauseApp()
    {System.out.println("pauseApp");
    public void destroyApp(boolean unconditional)
    {System.out.println("destroyApp");
    public void commandAction(Command c, Displayable d)
    {System.out.println("commandAction");
     if(c==mCommandQuit)
        notifyDestroyed();
     else if(c==mCommandItem)
     {p = Integer.parseInt(prime1.getString());
         q = Integer.parseInt(prime2.getString());
         b = Integer.parseInt(prime3.getString());
         //breaking up of big string into ints
         mstring=input.getString();
         temp[0]="";
         for(i=1;i<mstring.length();i++)
            {if (mstring.charAt(i) == ' ')
                {j++;
                 temp[j]="";
             else
                {temp[j]=temp[j]+mstring.charAt(i);
         mForm.append("\n\nThe array is:\n");
         for(i=0;i<temp.length && temp!=null;i++)
{k1=Integer.parseInt(temp[i]); ***********************
k2=k1;
for(j=1;j<b;j++)
{k1=k1*k2;
k1=k1 %(p*q);
k2=k1 %(p*q);
a=a+new Character((char)k2).toString();
output=new TextField(null,a,100, TextField.ANY);
mForm.append(output);
}hi
this code basically takes an input of string like " 179 84 48 48 155 " (with spaces)
then it creates smaller strings in an array like "179","84","48","48","155" without the spaces
then it creates int values 179,84,48,48,155 and finally after some math functions it prints the corresponding letters.
the problem is that it is not printing the letter because of some exceptions-->java.lang.NumberFormatException .it comes in the line where i have put stars
could anybody please help me print the letters

thanks for all ur help guys, but me and my team member solved it on our own. here is the new code:
import javax.microedition.midlet.*;
import javax.microedition.lcdui.*;
public class Test3 extends MIDlet implements CommandListener
{   Form mForm;
    Command mCommandQuit;
    Command mCommandItem;
    TextField input,prime1,prime2,prime3,output;
    Display mDisplay;
    int i,j=0,l,k1,k2,p,q,n,b;
    String mstring,a = "";
    String [] temp=new String [1000];
    public void startApp()
    {System.out.println("startApp");
     mForm=new Form("RSA Encryption");
     mCommandQuit=new Command("QUIT",Command.EXIT,0);
     mCommandItem=new Command("DECRYPT",Command.ITEM,0);
     mForm.append("Enter text:\n");
     input=new TextField(null,"",100, TextField.ANY);
     mForm.append(input);
     mForm.append("Enter first prime number(p):\n");
     prime1=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime1);
     mForm.append("Enter second prime number(q):\n");
     prime2=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime2);
     mForm.append("Enter d:\n");
     prime3=new TextField(null,"",100, TextField.NUMERIC);
     mForm.append(prime3);
     mForm.addCommand(mCommandQuit);
     mForm.addCommand(mCommandItem);
     mDisplay=Display.getDisplay(this);
     mDisplay.setCurrent(mForm);
     mForm.setCommandListener(this);
    public void pauseApp()
    {System.out.println("pauseApp");
    public void destroyApp(boolean unconditional)
    {System.out.println("destroyApp");
    public void commandAction(Command c, Displayable d)
    {System.out.println("commandAction");
     if(c==mCommandQuit)
        notifyDestroyed();
     else if(c==mCommandItem)
     {p = Integer.parseInt(prime1.getString());
         q = Integer.parseInt(prime2.getString());
         b = Integer.parseInt(prime3.getString());
         n=p*q;
         //breaking up of big string into ints
         mstring=input.getString();
         temp[0]="";
         for(i=1;i<mstring.length();i++)
            {if (mstring.charAt(i) == ' ')
                {j++;
                 temp[j]="";
             else
                {temp[j]=temp[j]+mstring.charAt(i);
         l=j;
         mForm.append("\n\nThe result is:\n");
         for(i=0;i<l;i++)
            {k1=Integer.valueOf(temp).intValue();
k2=k1;
for(j=1;j<b;j++)
{k2=k2*k1;
k2=k2 %n;
k1=k2 %n;
a=a+new Character((char)k1).toString();
output=new TextField(null,a,100, TextField.ANY);
mForm.append(output);

Line console password vs privilege mode enable secret

Hi all,
Below is my running config ->
line con 0
exec-timeout 0 0
privilege level 15
password cisco
logging synchronous
login
q1) how come every time i will enter privilege mode once i enter the console password ? can I choose to enter normal user mode instead ? is it via setting the privilege level ?
q2) I understand that for enable privilege mode, i can set secret/encrypted password for the enabling.
R1#config t
R1(config)#enable secret cisco
Where does the encryption take place ? is it only to just md5 the password text in the configuration file only ? if i were to sniff the password over the network, i will still see clear text "cisco" ?
q3) Why can't i do so (setting secret/encrypted) password for line (vty,con etc) login ?
q4) for q3, after google, i realize i need to issue service password-Encryption
a) does this command "encrypt" again my current enable secret password ? -- i think its no cause i see no changes in show run
b) why do we have to issue this command to encrypt my line,vty etc password ? why can't we use the "secret" command ?
c) what the different between this "service password-Encryption" and "secret" ? why do we need to have both ?
q5) is all the service password-Encryption, enable secret etc, just basically hashing or encrypting the actual text password in the config file. is there anyway of encryption over the network ?
Thanks,
Noob

a) why vty, console line cannot have hashed password like enable secret ? -- the only way to use secret is to have login local and create local username with secret password
Because they can't, its as simple as that really.
Like you said, the only way to protect the password using an MD5 hash is to create a username and password and ensure you use the secret command like:
username admin secret password
b) is all the service password-Encryption, enable secret etc, just basically hashing or encrypting the actual text password in the config file. is there anyway of encryption over the network ?
Its just using an MD5 hash
Where its encrypted or not over the network will depend on whether you use Telnet or SSH to connect to the switch.
Telnet is plain text so even using an MD5 password will still be visible if someone were to packet capture your telnet session.
SSH in encrypted so use this whenever possible.

Preverify ERROR for in Eclipse while using SATSA-crypto.jar

I have created simple application to encrypt the string using Cipher class like below:
This code snippet I got from the forums.nokia;
In this The string "THIS IS A SECRET MESSAGE" is encrypted and decrypted using the key "SECRET!!" .
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import javax.microedition.lcdui.Command;
import javax.microedition.lcdui.CommandListener;
import javax.microedition.lcdui.Displayable;
import javax.microedition.lcdui.Form;
import javax.microedition.lcdui.Item;
import javax.microedition.lcdui.TextBox;
import javax.microedition.lcdui.TextField;
import javax.crypto.BadPaddingException;
import javax.crypto.Cipher;
import javax.crypto.IllegalBlockSizeException;
import javax.crypto.NoSuchPaddingException;
import javax.crypto.ShortBufferException;
import javax.crypto.spec.SecretKeySpec;
public class FirstForm extends Form implements CommandListener {
     TextField txtData=new TextField("Enter the Data","",10,TextField.ANY);
     Command cmdEncrypt=new Command("Encrypt",Command.SCREEN,1);
     public FirstForm(String arg0)
          super(arg0);
          this.append(txtData);
          this.addCommand(cmdEncrypt);
          this.setCommandListener(this);
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          if(cmd==this.cmdEncrypt)
               System.out.println("Command Is Pressed.......");
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               byte[] enMsg = new byte[10000];
               byte[] deMsg = new byte[10000];
               //create new cipher using DES algorithm
               try {
                    Cipher c = Cipher.getInstance("DES");
                    //our raw byte[] key - please note that since we use DES algorithm,
                    //the key must be 8 bytes long
                    byte[] b = "SECRET!!".getBytes();
                    //init the cipher to encrypt the data
                    c.init(Cipher.ENCRYPT_MODE, new SecretKeySpec(b,0,b.length,"DES"));
                    int numBytes = c.doFinal(msg, 0, msg.length, enMsg, 0);
                    System.out.println("Encrypted Message is"+enMsg);
                    //init the cipher to decrypt the data
                    c.init(Cipher.DECRYPT_MODE, new SecretKeySpec(b,0,b.length,"DES"));
                    numBytes = c.doFinal(enMsg, 0, numBytes, deMsg, 0);
                    String s = new String(deMsg,0,numBytes);
                    System.out.println("Decrypted Message is"+s);
               } catch (InvalidKeyException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (NoSuchAlgorithmException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (NoSuchPaddingException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (IllegalStateException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (ShortBufferException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (IllegalBlockSizeException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
               } catch (BadPaddingException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
}after clicking on command button the Encrypted and decrypted sting is shown on the console
I have tested this code with wtk2.5.2.
This code works fine with sun'sWTK 2.5.2
But when; I have created project with the eclippse and wtk22
1) I added the satsa-crypto.jar in projrct->Properties->java-Builder-Path in "Library tab"
2)I Had also checked the checkbox before satsa-crypto.jar "Order-Of-Export Tab"
I am using the Ant Built
After Building I got Error saying::
Buildfile: D:\nitins_workspace\Encrypt\build.xml
init:
j2mepolish:
[j2mepolish] info: the license attribute is no longer supported. Please place your license.key file either to ${project.home} or to ${polish.home}.
[j2mepolish] J2ME Polish 2.0-RC4 (GPL License)
[j2mepolish] Loading device database...
[j2mepolish] Using locale [de_DE]...
[j2mepolish] assembling resources for device [Generic/midp2].
[j2mepolish] preprocessing for device [Generic/midp2].
[j2mepolish] compiling for device [Generic/midp2].
[j2mepolish-javac-Generic/midp2] Compiling 24 source files to D:\nitins_workspace\Encrypt\build\real\Generic\midp2\de_DE\classes
[j2mepolish] obfuscating for device [Generic/midp2].
[j2mepolish] proguard: ProGuard, version 3.5
[j2mepolish] proguard: Preparing output jar [D:\nitins_workspace\Encrypt\build\real\dest.jar]
[j2mepolish] preverifying for device [Generic/midp2].
[j2mepolish] preverify:Error preverifying class u
[j2mepolish] preverify:    VERIFIER ERROR u.a(ILm;Lw;)V:
[j2mepolish] preverify:Cannot find class com/sun/midp/ssl/Key
[j2mepolish] Preverify call failed: 1
[j2mepolish] C:\WTK22\bin\preverify.exe -classpath D:\Java\J2ME-Polish\import\midp-2.0.jar;D:\Java\J2ME-Polish\import\cldc-1.0.jar; -d D:\nitins_workspace\Encrypt\build\real\Generic\midp2\de_DE\obfuscated -nofp -nofinalize -nonative D:\nitins_workspace\Encrypt\build\real\Generic\midp2\de_DE\obfuscated
BUILD FAILED
D:\nitins_workspace\Encrypt\build.xml:109: Unable to preverify for device [Generic/midp2] - preverify returned result 1
Total time: 7 seconds What may be the reason of this??

I think you need to post the stack trace error message to get a response.

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Thommo wrote:
Are you able to delete files via your Pc or are you able to remove the card from your phone and connect it to a Pc for file deletion - There is a free program called Unlocker currently on version 1.9.2 which is excellent at deleting files that don't want to be deleted - You would install the program then right click the file and choose Unlocker and then when the program starts choose delete
I guess he will not be able to move the SD card to the computer since it's encrypted and is working only with that particular device, but he should be able to access it via PC.
If you can try to uninstall Spotify from your phone. I assume Spotify is not working due to some rubbish inside it's directory, but on the other hand you can't delete the folder because it may be used by Spotify. If you uninstall app folder may be unlocked.
Best regards,
Sergio PL
Xperia Z1 / Nexus 7 (2012)

How to encrypt file on linux using Gnupg command in Java Embedding in BPEL.

Hi All,
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try {
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Hi,
Here is a example of encrypting the login credentials in a maxl scipt.
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e.g.
Public Key for Encryption: 5407,1453704157
Private Key for Decryption: 406488703,1453704157
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login admin password on localhost;
logout;
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http://john-goodwin.blogspot.com/

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I'm just wondering, if it would still be possible to retrieve encrypted files (such as home folders using legacy filevault) from Mac OS X 10.8.5 after clean install of new OS and performing command-p and -r during bootup? Any help would be greatly appreciated.

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I'm trying to encrypt a PDF with a password and receive this error.
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Anybody know how to fix this?
Version: 7.0.2
OS: Win

I was also getting this error, when trying to set usage rights on a document and then encrypt it with a password. I found a solution which works (more like a workaround, as this feels like a bug):
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2. Call pdfDocument.encryptWithPassword()
3. Call pdfDocument.save(), write resulting bytes to temp file
4. Reopen this file with pdfFactory.openPdfWithPassword()
5. Now you can call pdfDocument.setUsageRights() and pdfDocument.save()

Filevault encryption paused, despite reset of PRAM and using terminal commands

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I attempted making a new user to see if this would bypass it, but it didn't.
I have reset the PRAM and have repaired the HDD both in recovery and normal, neither work.
I have also used terminal command "sudo fdesetup disable" to attempt turning it off, but that doesn't work either.
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If you don't already have a current backup of all data, back up before proceeding. There are ways to back up a computer that isn't fully functional. Ask if you need guidance.
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Then, from the menu bar, select
File ▹ Turn Off Encryption
Enter the password again.
You can then restart as usual, if the system is working. Decryption will be completed in the background. It may take several hours, and during that time performance will be reduced.
If you can't turn off encryption in Disk Utility because the menu item is grayed out, you'll have to erase the volume and then restore the data from a backup. Select the Erase tab, and then select
Mac OS Extended (Journaled)
from the Format menu.
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Can an Access 2013 accdb file be encrypted using command line switches?

Can an Access 2013 accdb file be encrypted using command line switches?
I found all the command switches, but nothing about encrypting. And I've searched online and found nothing.
Can this be done?
Thanks!

Hi Sharon2000,
I think you could try the Database.NewPassword Method (DAO) in the VBScript file, and you could get more information about it from the link below:
#Database.NewPassword Method (DAO)
https://msdn.microsoft.com/en-us/library/office/ff844754.aspx
Here is a simple demo to achieve your issue.
Best Regards,
Edward
We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
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Does java card support PIN encryption on APDU Verify Command???

hello
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thanks a lot

Many Java cards support the GlobalPlatform Open Platform specification
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where the off-card entity authenticates itself to an application,
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