Overread lines in input file

Hi guys, i really hope u can help me.
We are trying to read a file via FTP which looks like this:
Dataname 639 539 00;;;;
Pos. :;Var;Name;GHNr.;Desc
4;1;ABB;639 539 00 9960/4;
5;1;ABC;639 539 00 9960/5;
Machine;;;;;
Porsche;;;mark;;
9 9 9 2 4 9 0 0 9 9 6 1;;;;;
Us.: 12.10.00 Em;;Nr.: ;6 3 9 5 3 9 0 0 9 9 6 0 ;;
So for me it is hard to read the data because the empty lines i don't need and for some results i have to read numbers at special positions (like the last devided with space).
Is there any chance to read this file this kind of dynamically?!
br Jens

I doubt that would be possible with the default File Adapter. You can however read every line and use User Defined Functions to extract the information you require.

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Converting a single line in Input file

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and the output has to be according to the xml format ( every tag in different line ).
Thanks in advance
Divya

Hi Experts,
I tried searching the blogs and wiki in sdn. but couldnt able to find out.
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Read lines from text file to java prog

how can I read lines from input file to java prog ?
I need to read from input text file, line after line
10x !

If you search in THIS forum with e.g. read lines from file, you will find answers like this one:
Hi ! This is the answer for your query. This program prints as the output itself reading line by line.......
import java.io.*;
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if you search in THIS forum, with e.g. read lines from text file
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How can I input read a line from a file and output it into the screen?

How can I input read a line from a file and output it into the screen?
If I have a file contains html code and I only want the URL, for example, www24.brinkster.com how can I read that into the buffer and write the output into the screen that using Java?
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Hi!
This is a possible solution to your problem.
import java.io.*;
class AddressExtractor {
 public static void main(String args[]) throws IOException{
 //retrieve the commandline parameters
 String fileName = "default.html";
 if (args.length != 0) fileName =args[0];
 else {
 System.out.println("Usage : java AddressExtractor <htmlfile>");
 System.exit(0);
 BufferedReader in = new BufferedReader(new FileReader(new File(fileName)));
 StreamTokenizer st = new StreamTokenizer(in);
 st.lowerCaseMode(true);
 st.wordChars('/','/'); //include '/' chars as part of token
 st.wordChars(':',':'); //include ':' chars as part of token
 st.quoteChar('\"'); //set the " quote char
 int i;
 while (st.ttype != StreamTokenizer.TT_EOF) {
 i = st.nextToken();
 if (st.ttype == StreamTokenizer.TT_WORD) {
 if (st.sval.equals("href")) {
 i = st.nextToken(); //the next token (assumed) is the '=' sign
 i = st.nextToken(); //then after it is the href value.
 getURL(st.sval); //retrieve address
 in.close();
 static void getURL(String s) {
 //Check string if it has http:// and truncate if it does
 if (s.indexOf("http://") > -1) {
 s = s.substring(s.indexOf("http://") + 7, s.length());
 //check if not mailto: do not print otherwise
 if (s.indexOf("mailto:") != -1) return;
 //printout anything after http:// and the next '/'
 //if no '/' then print all
 if (s.indexOf('/') > -1) {
 System.out.println(s.substring(0, s.indexOf('/')));
 } else System.out.println(s);
}Hope this helps. I used static methods instead of encapsulating everyting into a class.

How to find number of lines in an input file.

Hi,
Can someone tell me, if there is a way to find out the number of lines in an input file. I do not want to read line by line and then count the number of lines read.

Then how do you think a program could determine the amount of lines in an input file? How does a human know how many lines are on a page? You're going to have to count the items that separate two lines to know how many lines are in your file.
Either read line by line and count the amount or read char by char and count the number of '\n' occurences instead.
If you have control over writing the input files, however, you can make this better. Write a header in the file that specifies the amount of lines in it. The first line of your file will then hold a number that represents the amount of lines in the file, so you need only read the first line to know how many lines are in your file.

How to upload schedule line from flat files to sap file

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so how to upload that and the fields available in flat files are more than the sap screen
we are having more than 6 items
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for one customer in every 15 day
so how to do this
is there any direct use in functional side
with out the help of any abap
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so he need a permanent solution
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Hi Subrat ,
u can upload the data either ( Master /Transaction) data with the help of lsmw. for that all u need to do is go through the lsmw and do it. in that u can go Batch input recording/ BAPI/ IDOC any of that. here i am sending the LSMW Notes go through it and do the work.
once u create the LSMW project then u can ask the data from user or u can explain the user about the program and can run the flat file to upload the data.
if u require LSMW material Just send me blank mail from u. my mail id is [email protected]
Reward if Helpful.
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How to get characters from a line in a file ?

Hello Everybody ,
I am able to read the lines from the file using readLine( ) method.
But i do not want to read anything that comes after the character '#'
Any thing that follows a '#' character is considered as a commet in my case.
The contents of my input file are,
#Character mappings for Japanese Shift-JIS character set
#ASCII character Mapped Shift-JIS character
m 227,128,133 #Half width katakana letter small m
n 227,128,134 #Half width katakana letter small n
o 227,129,129
p 227,129,130
q 227,129,131
r 227,129,132
s 227,129,133
t 227,129,134
u 227,129,135
v 227,129,136
w 227,129,137
x 227,129,138
y 227,129,139
z 227,129,142
My code to read the contents of the file is,
import java.io.*;
class Read
public static void main(String s[])
try{
int i=0,j,l;
BufferedReader in=new BufferedReader(
new InputStreamReader(
new FileInputStream("Character.txt")));
String []str=new String[100];
while(true)
str=in.readLine();
if(str[i]==null) break;
System.out.println(str[i]);
i++;
catch(Exception e)
e.printStackTrace();
System.out.println(e);
How do i store the values within a line in the file
to two different variables
Like say,
I read the line
i get the character 'm' store it in a variable say, char ch='m' ;
and the corresponding value 227,128,133 in a String variable.
String str="227,128,133";
Please offer some suggesstions and help me out .
Any suggesstions would be welcome and very useful.
Thanks and regards
khurram

It depends on whether the format of the file will ever change. If the "rules" regarding the structure of the file are predictable, then it's fairly simple.
In the sample file, if we assume that anything that starts with # should be ignored, and all relevant lines begin with single char, followed by three comma separated integers; then you can just do the following (haven't tested this)
import java.io.*;
class Read
 public static void main(String s[])
 try{
 // Create a Map to store the results..
 Map data = new HashMap();
 // We will store the actual values in an array
 int[] values = null;
 // Each valid line has a character
 char theChar;
 // Temp storage for the integer values
 String[] strValues = null;
 BufferedReader in=new BufferedReader(
 new InputStreamReader(
 new FileInputStream("Character.txt")));
 String str=null;
 while(true)
 str=in.readLine();
 if(str==null) break;
 // trim to remove any spaces
 str = str.trim();
 theChar = str.charAt(0);
 if(theChar != '#') {
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 // Split to get the int
 strValues = str.substring(1, str.length()).split(",");
 // We only want the first 3 tokens
 values = new int[3];
 for(int i = 0; i < values.length; i++) {
 values[i] = Integer.parseInt(strValues);
 // Now, add the results to the map
 data.put(String.valueOf(theChar, values);
 System.out.println(str);
 catch(Exception e)
 e.printStackTrace();
 System.out.println(e);
This will leave you with a Map of the character mappings, keyed on the String value of the character (just because you can't store a char in a Map)

The file size of selected file in input file control is shown as 0 for multiple file selection in Safari 5.1

The file size of selected file in input file control is shown as 0 for multiple file selection in Safari 5.1. If you select single file, then it is able to return file size correctly. However, if you select multiple files, then the file size of each of the selected file is always returned as 0 from javascript. This works correctly in Safari 4.0 but it does not work in Safari 5.1.
How do I get the correct file size in Safari 5.1 ?

If you want to post (or send me) a link to the lrcat file, I'd take a look at it for you, and give you a break-down what's consuming all the bytes. But it might be fun to learn how to do that yourself (e.g. using SQL). I use SQLiteSpy, but other people have their favorites.. (or you can use a command-line client if you prefer..). One way: just run "drop table "{table-name}" on each table then look at filesize (do this to a copy, not the real thing).
Anyway, it's hard to imagine keywords and captions etc. taking much of the space, since even if you had 1000 10-character words of text metadata per photo average that still only adds up to 117MB, which isn't a substantial portion of that 8G you're seeing occupied.
Anyway, if you've painted the heck out of most of them and not cleared dev history, that'll do it - that's where I'd put my money too...
One thing to consider to keep file-size down:
===================================
* After reaching a milestone in your editing, take a snapshot then clear edit history, or the top part of it anyway (e.g. leave the import step), using a preset like:
Clear Edit History.lrtemplate
s = {
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    value = {
        settings = {
            NoEdit = true,
        uuid = "34402820-B470-4D5B-9369-0502F2176B7F",
    version = 0,
(that's my most frequently used preset, by far ;-})
PS - I've written a plugin called DevHistoryEditor, which can auto-consolidate steps and reduce catalog size - it's a bit cumbersome to use a.t.m. but in case you're interested...
Rob

Need some Help ( formating strings vs formatting input files)

I have a program that reads in a text file and stores each line as a string. The input file has no delimiters and varying amounts of white space. The problem is, I am trying to display each line of the file the same way. Here is an example of what the string looks like when I read it in and then output the strings.
(I am using the underline to represent white space just in this message post.)
1.Fred Smith____GA_____23_______42______23.5_____3____5
2.Jon Doe____SC___42_______3_______39.2_____6_____12
Now here is is how I would like the output to look like.
1.Fred Smith_______GA_______23_____42_____23.5_____3_____5
2.Jon Doe__________SC_______42_____33_____39.2_____6_____12
Any thoughts or insight on how to achieve this would be great. Thanks for the time.

Hi, before I'd do anything more complicated, I'd replace some spaces with tabs and see if that does the trick.
Cheers, HJK

Input file should be deleted only after the output file is successful.

Hi Experts,
Could you pleas solve the below issue.
In a file to file scenario, the input file will be picked from a directory location and after processing output file will be placed in the output directory location specified in the receiver communication channel.
In the sender communication channel for the scenario mentioned above, if the processing mode is given as delete, the input file will be delete as soon as the file was successfully read by the adapter, but this will not ensure that the file processing is complete and the output file is being created.
If we have a scenario in such as way that the input file should be deleted from the input folder only if the complete process is successful and the output is generated. how can we achieve this functionality?.
And one more thing if we got the successful output the output file should be placed in one folder. and the if the output file is having errors it should be placed in other folder.

Hi,
In Receiver communication channel I have used the below command in Run Operating System
.And I have kept the processing mode of sender communication channel as test.
cmd.exe: /C "del /Leela/test.xml"
You are running the comman line program configured in the receiver File Adapter,but in command line you mentioned the Sender File Folder , So i guess it's not getting processed.
Try this:
Try to run the command line in the Sender File Adapter Side
"Place this in " --> Run OS Command After Message Processing.
Hope this would work and get in parrallel with u r requirement.
regards
Srini

How to know a line of text file is ending with line feed or return?

hi all, i have a program that read log file that generated by other service (apache http server for example), i want to know that each line is ending with "\r", "\n" or "\r\n" so i can skip them in the next time, like this:
int char_counter=0;
BufferedReader reader = new BufferedReader(new FileReader(logFileName));
while((line=reader.readLine())!=null){
 char_counter+=line.length()+x_value;
}and the next time read the log file, i will skip all the lines that read in previous time.
BufferedReader reader = new BufferedReader(new FileReader(logFileName));
reader.skip(char_counter);
while((line=reader.readLine())!=null){
 char_counter+=line.length()+x_value;
}with x_value is 1 or 2 depended on line end with "\n" or "\r\n".
so, how to know which is the char line ending with?
Edited by: secmask on Feb 21, 2009 5:46 AM

Alright, the BufferedReader method readLine() reads all text until it finds a \n character. And then next time you call it it will automatically continue from where it left out.
try this out it should show it as an example
import java.io.*;
public class readLineTest {
 static FileOutputStream filename;
 static BufferedReader input;
 public static void main(String[] args)
 try
 filename = new FileOutputStream("logFile.txt", false);
 catch (IOException e)
 //blank
 PrintStream output = new PrintStream(filename);
 output.println("this is the first line");
 output.println("this is the second line");
 output.println("this is the third line");
 try
 input = new BufferedReader(new FileReader("logFile.txt"));
 catch(IOException e)
 //blank
 for(int i = 0; i < 3; i++)
 try
 System.out.println(input.readLine());
 catch(IOException e)
 //blank
}

Input file size limition in File Reader Adapter

Hi,
We have a File Read Activity(using File Reader Adapter) which works on a Polling model. Whenever a input file is found in a designated directory it invokes our BPEL web service. During load testing we found out that if input file size exceeds 7 MB then we get "insufficient heap space" error. We found a reference to this size limitation in http://download.oracle.com/docs/cd/E11036_01/integrate.1013/b28994.pdf which has below lines..
"Files that are 7MB or larger in size cannot be delivered. As an alternative, you can debatch large files (if they have multiple messages), and publish these files in messages of size less than 7 MB. This alternative is applicable only to structured files (comma-delimited or fixed position), which contain more than one message. It is not applicable to binary or XML files."
Our customer will have the data in XML format and the size of the files will be pretty huge(running into 49, 69 MBs). Do we have any workaround here or we are left with no option but to ask the customer to split the files and load it? The later option is currently difficult one for the customer since when split there is a possibility of XML becoming invalid. Any pointers in this issue is appreciated.
Thanks!
Balaji

Hi,
BPEL can not process more than 7 MB size xml structred file. but,debatching will work for xml files also provided if the file has repeated multiple structures (means multiple repeated root elements).
Regards,
Dhanumjay

File adapter input file format

Here the communication scenario is as follows: read a file and send a message via XI to an inbound interface.
A file adapter service has been defined. Message protocol 'file content conversion' has been chosen for the file adapter service. Next the file format has to be defined in communiction channel settings.
Is it possible to define the input record structure in the file to be red itself?
The first line will list all column names. The data records will follow in line two up till end of file.
Regards
Klaus

Now I can add some more information to the facts.
In XI 2.0 the adapter engine was used to connect the integration engine to external systems. The adapter engine converted input file contents to a XML message. The structure of the records in the input file has to be defined. There was one option to read this structure from the first line of the file itself. This option was called 'fromFile'.
Now the current situation in XI 3.0 is that the integration engine reads the input file. Conversion of file contents is still available but the option to read the record structure from the input file doesn't exist anymore.
Does anybody know whether I am right and this functionality isn't available anymore or how to achieve the desired system function in XI 3.0.
Regards
Klaus

New lines in a file

I'm trying to find a good way to get new lines in a file, and while this works it also uses 100% CPU and is driving me nuts. At least the profiler says this is .run is using the most, and taskmanager gives it 100%. The file name changes every day.
package net.st0rm.ss.loghandlers;
import java.io.*;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Timer;
import java.util.TimerTask;
import net.st0rm.ss.Log;
import net.st0rm.ss.gamecmdhandlers.GameCommandHandler;
import net.st0rm.ss.irc.IRC;
public abstract class LogHandler {
 public static ArrayList<GameCommandHandler> gameCmdHandlers = new ArrayList<GameCommandHandler>();
 private BufferedReader reader = null;
 private File directory = null;
 private LogReadThread thread = null;
 private String thisLine = null;
 private boolean skip = true;
 * Time to wait between reads
 private Long delay = 100L;
 * Creates a new instance
 * @param directory Directory of the files used
 * @param skip Should the reader skip lines already existing?
 public LogHandler(File directory, boolean skip) {
 this.directory = directory;
 this.skip = skip;
 public String getFileName() { return ""; };
 private class LogReadThread extends Thread {
 public boolean stop = false;
 public void run() {
 Calendar c = Calendar.getInstance();
 c.set(Calendar.HOUR_OF_DAY, 23);
 c.set(Calendar.MINUTE, 59);
 c.set(Calendar.SECOND,59);
 StringBuilder sb = new StringBuilder(1000);
 new Timer("Restart Timer").schedule(
 new TimerTask() {
 public void run() {
 try {
 Thread.sleep(3000);
 } catch (InterruptedException e) {
 // TODO Auto-generated catch block
 e.printStackTrace();
 IRC.getInstance().msg("Restarting reader \"" + this.getClass().getSimpleName() + "\" for the new day.");
 LogHandler.this.restartReader();
 ,c.getTime(), 3600000*24);
 try {
 reader = new BufferedReader(new FileReader(directory.getAbsolutePath() + "/" + getFileName()));
 if (skip) while ((reader.readLine()) != null);
 while (!stop) {
 try {
 Thread.sleep(delay);
 } catch (InterruptedException e) { System.out.println("Thread Interupted!"); }
 while ((sb.append(reader.readLine())).toString() != null) { onNewLine(sb.toString()); sb.delete(0, sb.length()); }
 reader.close();
 } catch (IOException e) {
 Log.log(e);
 * Call to re-start the file stream
 public void restartReader() {
 if (thread != null) thread.stop = true;
 thread = new LogReadThread();
 thread.start();
 * Called when a new line is added to the file
 * @param line The line added
 public void onNewLine(String line) { }
}

I don't know what anybody can say other than "debug and profile your code".
It's weird that you have a Thread.sleep in the run method of a TimerTask. Why not just change the scheduling of the task?
This:
while ((sb.append(reader.readLine())).toString() != null) {
 onNewLine(sb.toString());
 sb.delete(0, sb.length());
}(reindented to make it easier to read) is fishy. Even when you reach the end of reader's input, I think it will just loop forever. That's because appending null to a string buffer and calling toString results in the string "null", not the value null. So that while loop will never end.
Good luck.

Having Troubles Gettin Lines Of Input!?!?!?!!?

I'm trying to build a command line application (named Assemble) which will read (from standard in) a tagged "discussion" stream and print a (somewhat) organized version of the tagged part of the discussion (to standard out).... but i'm having trouble getting multiple lines of input.. i tried a while statement that looked like this... while ( (input = in.readline()) != null ) and all i got was every other line of input to get displayed to the screen or to a file... how can i fix this??? i had the while statement above input = in.readLine();
 BufferedReader in = new BufferedReader (new InputStreamReader( System.in ));
 String input;
 input = in.readLine();
 System.out.println( input );

thanks.. i have the input coming in.. but how can i redirect input to output within the program.. i'm trying to move the input lines to either a file called head.txt, body.txt, or foot.txt... once the files are in there.. i want to read them out to the screen... how can i do this? at the moment..i'm moving them just to the screen..
import java.io.*;
import java.lang.*;
import java.util.*;
public class Assemble
public static void main(String args[]) throws IOException
if (args.length > 0)
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("Assemble.class is a small program that");
System.out.println("takes in as input a body of text and then");
System.out.println("outputs the text in an order according to");
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else
System.out.println("");
System.out.flush();
BufferedReader in = new BufferedReader (new InputStreamReader( System.in ));
String input;
while (true)
input = in.readLine();
if (input == null)
break;
else if ( (input.compareTo("<HEAD>")) == 0)
do
input = in.readLine();
if ( (input.compareTo("</HEAD>")) != 0)
System.out.println(input);
while ( (input.compareTo("</HEAD>")) != 0);
else if ( (input.compareTo("<BODY>")) == 0)
do
input = in.readLine();
if ( (input.compareTo("</BODY>")) != 0)
System.out.println(input);
while ( (input.compareTo("</BODY>")) != 0);
else if ( (input.compareTo("<FOOT>")) == 0)
do
input = in.readLine();
if ( (input.compareTo("</FOOT>")) != 0)
System.out.println(input);
while ( (input.compareTo("</FOOT>")) != 0);

Overread lines in input file

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