Pls Help about counting the lines of the file in java

Question

private int GrepPBArequestLog(String STRexpression) throws IOException
int totalnum = 0;
try {
String[] cmd = {"grep", "-ic", STRexpression, src};
System.out.println("grep, cmd " STRexpression" "+src);
Process grepProc = Runtime.getRuntime().exec(cmd);
String line = "";
BufferedReader br = new BufferedReader(new InputStreamReader(grepProc.getInputStream()));
line = br.readLine();
System.out.println("read: "+line);
while (line != null)
System.out.println("Line: "+line);
line = line.substring(line.indexOf(":") + 1, line.length());
System.out.println("Substring: "+line);
try
int temp = Integer.parseInt(line);
totalnum = totalnum + temp;
catch(NumberFormatException e)
System.out.println("String: "+line);
System.out.println("NumberFormatException Occured"+e.getMessage());
}//end while
the output is:
service No: 209
Wapdate: 07/Jul/2003
Went inside: GrepPBArequestLog
grep cmd .*07/Jul/2003.*GET.*209.* /var/log/httpd/access_log*
Line:
read: null
totalnum: 0
wap 07/Jul/2003:
wap 209:
total hits 209: 0
+++++++++++++++++++++++++++++++++
the read: should not be null because there is a number of lines and
totalnum shouldn't be 0.

Answer 1

You don't want to simply:
import java.io.*;
public class CountEm {
  private static BufferedReader br;
  private static int count;
  private static String fileName, record;
  public static void main(String[] argv) {
    switch(argv.length) {
      case 1:  { fileName = argv[0]; break; }
      default: { System.out.println("Usage: java CountEm [filename]"); System.exit(-1); }
    try { countEm(); }
    catch(IOException ioe) { System.out.println("ERROR doing countEm()\n"+ioe); }
    finally { System.out.println("Count: "+count); }
  public static void countEm()  throws IOException {
    br = new BufferedReader(new FileReader(fileName));
    while ( ( record = br.readLine() ) != null ) { count++; }
}~Bill