RegisterOutParam doesn't recognize types that are defined between quotes.

Suppose one defines a type as below:
create or replace type "VectorOfInt" as varray(300) of number(10);
in the C++ program, when using statement -> registerOutParam (...), the fourth argument is the type.
If one passes ... registerOutParam(..., "MYSCHEMA.\"VectorOfInt\""), that is, escaping the type name between double quotes, to indicate that the case should be respected, doesn't work. Everywhere else this construct seems to work fine.
If, however, one defines:
create or replace type VectorOfInt as varray(300) of number(10);
and one passes... registerOutParam (...,"MYSCHEMA.VECTOROFINT"), that works fine.
Is that a bug... or am I misunderstanding the concepts?

Shaun,
Don't know if this is the problem or not, but I had the same thing happen and my problem was that I had signed in to one device with my @mac.com address and the other device with my @me.com address. Both were recognized by Apple & I never got any errors (I only have one Apple ID account), but my data would never sync. Once I signed in with the same addy on both, it worked fine.

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Edited by: WhoCares357 on Feb 16, 2010 5:17 PM

A user on another forum h(http://preview.tinyurl.com/yjqx4a9) helped me find the problem. I had to create the head and tail first and then point them at each other. Thanks for all the help here.
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RegisterOutParam doesn't recognize types that are defined between quotes.

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