Regular Expressions and java

hi everybody i have a little question:
Does anybody have an idea how i can accomplish the following task:
I want to have a regex that excludes words that contain a ++, --, __ but any word contains single occurence of these characters (+,-,_) should be matched.
I tried anything that i could think of but i can't seem to be able to find a working regex. Anybody have an idea

It took me a while to get my head around possessive
quantifiers and atomic groups, and what they're good
for. They can be a little tricky--Friedl
himself got burned by them in the third edition of
MRE, as shown in the errata for pages 481-2:
http://regex.info/errata3.html
It's good to see that even those living on Mt. Olympus can get it wrong sometimes.
My version of Friedl is a correction on the first edition and is dated Nov 1997. In my version, 'possessive quantifiers' are proposed as a possible solution to a problem but Friedl does not mention any implementations. It may be time to fork out some cash and buy the latest version.

Similar Messages

3 regular expression and java crash WHY?? / HOW to SOLVE IT?

Hi, i hava problem on my program there is 3 regex after another.
The JAVA crash down idona know why
want to solve it how i think i have to clear the regex so they not be in the memory after proccessing
help needed >> Please

asfdal-qsa wrote:
contents = contents.replaceAll("(?i)(<\\s*\\w*[^>]*?>((?:.*?\\s*?)+)<\\s*?/\\s*?\\w*\\s*?>)", " ");if i use replaceAll or not it is the same output
Java crash down and give me this
Exception in thread "main" java.lang.StackOverflowError
at java.util.regex.Pattern$Curly.match(Pattern.java:3746)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4168)
at java.util.regex.Pattern$Loop.match(Pattern.java:4295)
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4227)
at java.util.regex.Pattern$Curly.match1(Pattern.java:3797)
at java.util.regex.Pattern$Curly.match(Pattern.java:3746)
at java.util.regex.Pattern$Curly.match1(Pattern.java:3797)
at java.util.regex.Pattern$Curly.match(Pattern.java:3746)
and still continue
Edited by: asfdal-qsa on Apr 12, 2009 7:14 AMWhat's wrong with my suggestion:
"<[^<>]++>"?

Rhino, Regular Expression and Java \r\n

Hi guys,
I have an application that allow the user to create some regex to compare values by using scripting, basically I am using the test code
        ScriptEngineManager mgr = new ScriptEngineManager();
        ScriptEngine engine = mgr.getEngineByName("rhino");
        String[] scripts = {"/[abc]+/.test(\"giscaaard\")",
                                  "/[abc]+/.test(\"giscaaard\r\")"};
        for(String script : scripts){
            Object result = engine.eval(script);
            System.out.println(script + ":" + result);
        }//end forSo I run a simple test
The output is
/[abc]+/.test("giscaaard"):true
Exception in thread "main" javax.script.ScriptException: sun.org.mozilla.javascript.internal.EvaluatorException: unterminated string literal (<Unknown source>#1) in <Unknown source> at line number 1
at com.sun.script.javascript.RhinoScriptEngine.eval(RhinoScriptEngine.java:110)
at com.sun.script.javascript.RhinoScriptEngine.eval(RhinoScriptEngine.java:124)
at javax.script.AbstractScriptEngine.eval(AbstractScriptEngine.java:247)
at threads.Threads.main(Threads.java:34)
Java Result: 1
Any idea why rhino doesn't accept \r\n? If there is a standard for this where I can get how it handles other characters?
PS: In fact my first idea was to use only java classes for perform such things, however when I try to importClass(java.lang.String) I get an exception saying rhino already has one. Is there anyway on how I can give up rhino default classes and use the java one?
Thanks and Regards

Hi guys,
I just figure out something else
The code:
ScriptEngineManager mgr = new ScriptEngineManager();
        ScriptEngine engine = mgr.getEngineByName("rhino");
        String[] scripts = {/*"\"giscard\" == \"giscard\"",
                            "\"giscard\" == \"giscard\"",
                            "\"gff\" < \"giscard\"",
                            "\"gff\" > \"giscard\"",
                            "5 == 1",
                            "27 > 9",*/
                            "'Giscard'\n'SecondLine'",
                            "\"Giscard\tFaria\"",
                            "'Giscard\tFaria'",
                            "'Giscard\nFaria'"
        for(String script : scripts){
            Object result = engine.eval(script);
            System.out.println(script + ":" + result);
        }//end forGives the output
'Giscard'
'SecondLine':SecondLine
"Giscard Faria":Giscard Faria
'Giscard Faria':Giscard Faria
Exception in thread "main" javax.script.ScriptException: sun.org.mozilla.javascript.internal.EvaluatorException: unterminated string literal (<Unknown source>#1) in <Unknown source> at line number 1
at com.sun.script.javascript.RhinoScriptEngine.eval(RhinoScriptEngine.java:110)
at com.sun.script.javascript.RhinoScriptEngine.eval(RhinoScriptEngine.java:124)
at javax.script.AbstractScriptEngine.eval(AbstractScriptEngine.java:247)
at threads.Threads.main(Threads.java:36)
Java Result: 1
So, the \r\n has nothing to do with regex, it seems that javascript doesn't support string variables that has the \r \n inside it, however other special characters like \t are supported. Any idea on how to handle that?
Regards

Regular Expressions with Java Regex

Hi,
I'm playing around with regex and there's something I can't get to work. What I need, is to capture words between 2 other words and the words captured has to be higher than 5 characters, so for example:
Pattern "Just testing on something with regular expressions" and suppose I'll try to match all the words between "testing" and "regular", then only the word "something" should come out because "on" and "with" are not larger than 5 chars.
Now I'm quite new to regexps and I know that ((?<=\btesting\b).*(?=\bregular\b)) will return " on something with "
But I can't seem to come up with an expression that would only output the word "something". I've tried a few expressions like ((?<=\btesting\b)((?:[\s\w{1,3}])*(\b\w{4,}\b)*(?:[\s\w{1,3}])*)*(?=\bregular\b)) which also returns " on something with " The others I tried would either return the whole " on something with " or return "Not Found!"
Does anyone have a tip for me? I'm well aware that it's not too hard to do something like this in Java, but I'm really looking to study regular expressions and would like to accomplish this using a regular expression.
The Java program I use is the following:
C:\Program Files\Java\jdk1.5.0_16\bin>java RegexTest "((?<=\btesting\b).*(?=\bregular\b))" "Just testing on something with regular expressions"
public class RegexTest {
     public static void main(String[] args) {
          Pattern RegexCompile = Pattern.compile(args[0]);
          Matcher m = RegexCompile.matcher(args[1]);
          boolean found = m.find(); // Perhaps there's another function to find () that would do the job?
          if (found)
          System.out.println(m.group()); // Perhaps group() is not the right function for this case?
          else
          System.out.println("Not Found!");
Edited by: dli2k3 on Sep 19, 2008 11:32 AM
Edited by: dli2k3 on Sep 19, 2008 11:33 AM

You're talking about a two-stage operation: find everything between those two words, then filter out anything that's less than five letters long. There's no single regex that will accomplish all that in one step.
By the way, please use {code} tags when you post source code.

Regular expression and XML

Hello,
I have an XML file containing regular expressions and i parse the file, extract the pattern from it and search for it using java regex package. The problem is it works fine when patterns are words but when the pattern is something like
write \\d+ (write followed by a space followed by one or mre digits) it doesn't work.
I wrote the same code but with the pattern embedded in it,ie. without using XML and it worked. But when extracting with XML it fails.
Also if the pattern is write[0-9] it only extracts write[0-9 and gives an error of no closing bracket.
Could anyone please tell me what i am missing out
Thank you

thank you for your replies. Well i have still no got over the problem so i am posting my code here and hoping it can get solved
import org.xml.sax.*;
import org.xml.sax.helpers.*;
import java.io.*;
import java.util.regex.*;
class textextractor extends DefaultHandler{
     boolean regex=false;
public void startElement(String namespaceURI,String localName,String qn,Attributes attr)
          if(localName.equals("REGEX"))
           regex=true;
public void characters(char [] text,int start,int length)throws SAXException {
          String t=new String(text,start,length);
          boolean flag=false;
          if(regex==true)
            Pattern pattern;
            String w=new String(t);
          pattern = Pattern.compile(w);
          Matcher matcher;
          matcher=pattern.matcher("there is a bat   read write 13    error at line ");
          while(matcher.find())
           flag=true;
           System.out.println("I found the text \"" + matcher.group() +"\" starting at index "
           + matcher.start() +"and ending at index " + matcher.end() + ".");
         if(!flag)
           System.out.println("not found");
         regex=false;
public class saxt2 {
     public static void main(String args[]) {
          try {
                XMLReader parser= XMLReaderFactory.createXMLReader();
                ContentHandler handler=new textextractor();
                parser.setContentHandler(handler);
                                parser.parse("d:\\regex.xml");
              }catch (Exception e) {
               System.err.println(e);
}The xml file is
                  <RegularExpression>
                  <REGEX>write</REGEX>
                  <REGEX>write \\d+</REGEX>
                  <REGEX>read[0-9]</REGEX>
                  </RegularExpression>by running the code you can see that write is found,write \\d+ doesn't match write 13 in the string and read[0-9] gives and error.
Any help will be greatly appreciated

Regular expression and line break problem

Hi friends,
I was trying out one regular expression in java but, for some reasons its not working. The test string looks something like this in the eclipse watch window:-
Test string:-*
Content-Disposition: form-data; name="name"\n\nOmkar\n|
In the above test string the last character is a pipe symbol.
And the java code i have written is: -
code:
    public static void getParameterValue(String paramName, String testParameter) {
              String parameterRegex = "name=\""+paramName+"\"(.*)|";
              Pattern pattern = Pattern.compile(parameterRegex,Pattern.DOTALL);
              Matcher matcher = pattern.matcher(testParameter);
              boolean isFound = matcher.find();
              if (isFound) {
                   System.out.println("The parameter value is : "+matcher.group(1));
         }After, the debug line moves over the first line in this method, the value contained in the "parameterRegex" string variable is:-
Regex:-*
name="name"(.*)|
However, my SOP statement, prints null....even though, "isFound" variable is true....can someone please explain me what could be the problem, where i am going wrong ?....
I have even, set the DOTALL option for the regex.
please some one help me!
Thanks and Regards
Omkar Patkar

zomkar wrote:
Sorry, folks, i did not mention the fact that i had posted the my query, in Java ranch also. But my problem lead to another problem of CROSS - POSTING !
Apologies, for that !....but please, does any one have a solution to my regex ? .... any one ? please ?
The value i get in paramaname is :- name
which is present in double quotes in test string.
is my regex incorrect ?The discussion at JavaRanch seems to be pretty alive, so why not leave this thread and continue there? That way, people won't have to first read two different threads on two different forums before trying to help you.

Java parser for regular expression to java program

Hi All,
I am very new to parser technologies .I am looking for a (java)parser which can read the "regular expression" and can convert it into "java program".Please let me know is there any thing related to this.
Thanks in advance.
Your will be appriciate.
Regards,
Sai.

Hi Jos,
Thank you for your quick response .You're welcome.
If you have any sample code or simple example for how to use those
classes (Pattern,Match) ,will you please send me .It will be helpful for me.Jverd gave you two nice links already in his reply #3
If there is any "open source" for parsering regular expressions.
Please send me I am very new to parser technologies.Note that that Pattern class take care of all the parsing of REs, i.e. there's
nothing 'interesting' left for you to do any parsing whatsoever. Can you
elaborate a bit on what you exactly want to do and learn?
kind regards,
Jos

Regular expressions and sql

I have working regular expressions and a working sql connection, but I don�t know how to stop the info from getting into the database when input doesent match the regular expression.
For instans, you put in an e-mail without an "@" and my program writes and error message. But the info still gets in to the database.
Any help would be much apreciated as I dont know where to start. If you have links or code examples that would be great to.
Thanx.

Well, the obvious answer is "only write the data to the database if the input doesn't match the regular expression."
Presumably you're really asking how to do that - but it depends upon how your application is structured in the first place, and you haven't told us anything at all about that.

Regular Expression and PL/SQL help

I am using Oracle 9i, does 9i support regular expression? What functions are there?
My problem is the birth_date column in my database comes from teleform ( a scan program that reads what people wrote on paper), so the format is all jacked up.... 50% of them are 01/01/1981, 10% are 5/14/1995, 10% are 12/5/1993, 10% are 1/1/1983, 10% are 24-JUL-98. I have never really used regular expression and pl/sql, can anybody help me convert all of them to 01/01/1998?
Does Oralce 9i support regular expression? What can I do if oralce 9i does not support regular expression? Thank you very much in advance.

9i doesn't support regular expressions (at least not in the 10g regular expressions sense. There is an OWA_PATTERN_MATCH package that has some facilities for regular expressions). But it doesn't look like this is a regular expressions problem.
Instead, this is probably a case where you need to
- enumerate the format masks you want to try
- determine the order you want to try them
- write a small function that tries each format mask in succession until one matches.
Of course, there is no guarantee that you'll ever be able to convert the data to the date that the user intended because some values will be ambiguous. For example, 01/02/03 could mean Feb 1, 2003 or Jan 2, 2003 or Feb 3, 2001 depending on the person who entered the data.
Assuming you can define the order, your function would just try each format mask in turn until one generated a valid date, i.e.
BEGIN
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_1 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_2 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_3 );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
BEGIN
    l_date := TO_DATE( p_string_value, format_mask_N );
    RETURN l_date;
EXCEPTION
    WHEN OTHERS THEN
      NULL;
END;
RETURN NULL;
END;Justin

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Regular expressions and backreference

Hello!
I am trying to use backreferences in REGEXP in the PERL-style, where I want to match my regular expression and later refer to the grouped values. I can read that those are referecenced with \1 .. \9, but I simply cant get it to work. Here is an example in PL/SQL:
SELECT REGEXP_SUBSTR(l_users.adresse,'([A-Z]+)\s+(\d+)')
INTO l_dummy_varchar2
FROM dual;
OR I could do things like:
l_dummy_varchar2 := REGEXP_SUBSTR(l_users.adresse,'([A-Z]+)\s+(\d+)');
It seems to work, but I cant figure out how to get the backreferenced value.
I would love to do things like:
dbms_output.put_line('my value ='||\1)
but this doesnt work.
Help is very much appreciated.
Best regards
Dannie

Likewise you can extract things using the
REGEXP_SUBSTR, but you don't need back
referencing...backreferencing is better than additional function (ltrim) use, and BTW be careful with this "ltrims":
SQL> set serveroutput on
SQL>
SQL> DECLARE
2       v_txt VARCHAR2(100);
3     BEGIN
4       v_txt := ltrim(regexp_substr('HERE IS AN ASCII CHARACTER', 'IS AN [[:alnum:]]*'),'IS AN ');
5       DBMS_OUTPUT.PUT_LINE('Word after IS AN: '||v_txt);
6 END;
7 /
Word after IS AN: CII
PL/SQL procedure successfully completed
SQL>
SQL> DECLARE
2       v_txt VARCHAR2(100);
3     BEGIN
4       v_txt := regexp_replace('HERE IS AN ASCII CHARACTER', 'IS AN ([[:alnum:]]*)|.','\1');
5       DBMS_OUTPUT.PUT_LINE('Word after IS AN: '||v_txt);
6 END;
7 /
Word after IS AN: ASCII
PL/SQL procedure successfully completed
SQL> -----------
VB
http://volder-notes.blogspot.com/

Regular expression in java -- specifically email

Does anyone know how I can do a regular expression with java that is going to retrieve an email address pattern.
For example, let's say i have a huge string
this is a sample test. perhaps someoen can tell me how to retrieve my [email protected] from this string. sincerely yours [email protected]
could someone explain to me how to retrieve these emai addresses most efficiently using java's regular expressions
thanks
stev

A citing (http://jregex.sourceforge.net/examples-email.html):
String someValidChars="[\\w.\\-]+";
String someAlphaNums="\\w+";
String dot="\\.";
Pattern email=new Pattern(someValidChars + "@" + someValidChars + dot + someAlphaNums);

Juniper MX Regular expressions and user permissions ACS 5.4

Hi everyone!
Im having some trouble with regular expressions and permissions on our Juniper MX routers through ACS 5.4, and i would like some insight/help/poitners!!
We have a team of engineers that should only have read only permissions (important: show configuration) and also be able to just change the description on interfaces.
Thus far with the following regular expressions set for the shell profile they are going through i have managed the above, however the problem is when an engineer inputs "Show configuration", only the interfaces descriptions configuration is shown! The rest of the configuration will not be printed.
deny-commands1=.*.
allow-commands1=configure
deny-configuration1=.*.
allow-commands2=interfaces .*. description .*$
allow-configuration1=interfaces .*. description .*$
allow-commands2=show configuration.*
allow-commands3=show configuration
(some of these regex i know that are not needed, i was just playing around to check everything before posting)
Any pointers as to why or how to resolve this?
example output with the above:
show configuration
## Last commit: 2014-01-09 09:34:44 EET by someone
interfaces {
    xe-0/0/0 {
    xe-0/0/1 {
        description xxxx;
    xe-0/1/0 {
        description xxxx;
    xe-0/1/1 {
        description xxxx;
    xe-0/2/0 {
        disable;
    xe-0/2/1 {
        description xxxx;
    xe-0/3/0 {
        description xxxx;
    xe-0/3/1 {
        description xxxx;
    ae0 {
        description "xxxx";
    ae1 {
        description xxxx;
    demux0 {
    lo0 {
{master}
Thanks in advance!
Spyros

You are absolutely right!! I was doing research online after posting the above. The correct RADIUS attribute to use is actually CVPN3000/ASA/PIX7.x-Group-Based-Address-Pools. Then create the pool in ASA, and call that pool's name in ACS under that RADIUS attribute. Someone explained this perfectly in this community before. Much appreciate your answer!
Here's from another post last year:
ACS 5 does not have the feature of IP pools. Logically its always good to setup pools locally on vpn server and if you want user to pick ip from specific local pool you can configure acs to push that attribute.
On ACS Go to > Policy Elements -> Network Access ->   Authorization Profiles -> Create ->
Name of the Policy ->Dictionary Type: Radius-Cisco VPN 3000/ASA/PIX7.x
Attribute Type : CVPN3000/ASA/PIX7.x-Group-Based-Address-Pools
Attribute Type: String
Attribute Value : Static MYPOOL (Name of the Pool which is defined on the ASA)
Access Policies ->Default Network Access -> Authorization -> Create -> Under result section call the Authorization p

Can somebody help me in getting some good material for Regular Expressions and IP Community list

can somebody help me in getting some good material for Regular Expressions and IP Community list

I'm not sure what you mean by "IP Community list", but here are 3 reference sites for Regular Expressions:
Regular Expression Tutorial - Learn How to Use Regular Expressions
http://www.regular-expressions.info/tutorial.html
Regular Expressions Cheat Sheet by DaveChild
http://www.cheatography.com/davechild/cheat-sheets/regular-expressions/
Regular Expressions Quick Reference
http://www.autohotkey.com/docs/misc/RegEx-QuickRef.htm

Find text using regular expression and add highlight annotation

Hi Friends
Is it possible to find text using regular expression and add highlight annotation using plugin

A plugin can use the PDWordFinder to get a list of the words on a page, and their location. That's all that the API offers for searching. Of course, you can use a regular expression library to work with that word list.

Regular Expressions and java

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