Shell Script gives error when run through cron job.

Question

Hi,
The following shell script runs without any problem when executed manulally.
USED=$(df -h /arch | tail -1 | awk '{print $5}' | cut -d '%' -f 1)
if [ ${USED} -gt 90 ]
then
find /arch/AUBUAT/ -type f -mtime +0 | xargs rm
find /arch/AUBMIG/ -type f -mtime +0 | xargs rm
fi
But the same gives below error when called from a cron job:
/backup/arch_test.sh: syntax error at line 1: `USED=$' unexpected
We are running following version:
bash-3.00$ uname -a
SunOS uaeaubdbdr01.aub.af 5.10 Generic_141444-09 sun4u sparc SUNW,SPARC-Enterprise
Kindly assist.
Thanks
Edited by: user13362786 on Apr 20, 2011 4:36 AM

Answer 1

Hi,
When I used #!/usr/bin/sh now even the manul execution of the script fails with the same err:
bash-3.00$ ./arch_test.sh
./arch_test.sh: syntax error at line 2: `USED=$' unexpected
And when I used #!/usr/bin/ksh the manual execution runs fine but again when the script is run from cronjob it now give dirrect err:
/backup/arch_test.sh[2]: df: not found
/backup/arch_test.sh[2]: tail: not found
/backup/arch_test.sh[2]: cut: not found
/backup/arch_test.sh[2]: awk: not found
/backup/arch_test.sh[3]: test: argument expected