Show Previous Balance value in Report.

Hi,
I'm using Crystal Reports with Visual Studio 2010. I'm generating a report which shows columns Debit and Credit and SUM values on the buttom of each column. The report is filtered using a date range, which I specify in my connection via C# code (below).
string sqlString = "";
sqlString = "SELECT * FROM Ledger WHERE ([Payment Date] >= #" + FromDate + "#) AND ([Payment Date] <= #" + ToDate + "#)";
Now I need a "Previous Balance" value, which would be the SUM of Credit and Debit columns, which are prior to "Payment Date". How do I accomplish this? I've attached a sample of the report I'm looking for. Please be specific with your reply, because I'm new to Crystal Reports.
Thank you so much for your help.
Aron

Hi Aron,
Crystal is database agnostic, meaning it will run a report against any database. If you create a report using AS/400 it's possible to use that same report against an Oracle or SQL Server database as long as the recordset Crystal is expecting is the same.
So having a report run from a Stored Procedure will work on different databases as long as the metadata for the Stored Procedures between the databases match.
For the subreport, when you drop the subreport into the Group Footer. Right-click on the subreport and you have the option to Link Subreport. You can select the OwnerID from the main report and link it to the OwnerID in the subreport.
Your c# suggestion may be going the long way around the barn. If you link the subreport in your Group Footer 1, you should be able to get the Previous Balance for that OwnerID. When you link the subreport, it creates a Record Selection Formula in the subreport that should return only the records for that OwnerID.
Once you have the subreport linked, edit the subreport and go to Report | Selection Formula | Edit Record Selection Formula. You'll see what the linking created. You can now edit that formula to include your date range that is outside the current period.
Hope this helps,
Brian

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Show Previous Balance value in Report.

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