Simple Max date pull from several rows with the same employee numbers.
Ok so I'm hoping this is flying over my head because it's almost 3am, but I haven't been able to figure this query out for the last 2hrs, but I like to figure stuff out on my own. I'm wondering why the following statement works fine:
select emp_num, to_char(max(end_date)) as newestdate
from bank_history
where emp_num in ('22964', '21667', '20758', '12739', '12731', '20929', '22795', '20594', '23077', '12588', '21294', '20618', '21204', '22952', '19990', '20632', '03093', '19991', '22951', '07779', '20014', '11981', '06149', '20364', '21103')
and bank_type = 'P' group by emp_num
BUT! When I start to add more columns that I need to see it starts adding the multiple employee numbers again.
select emp_num, bank_type, earn_hrs, used_paid_hrs, used_paid_hrs, to_char(max(end_date)) as newestdate
from bank_history
where emp_num in ('22964', '21667', '20758', '12739', '12731', '20929', '22795', '20594', '23077', '12588', '21294', '20618', '21204', '22952', '19990', '20632', '03093', '19991', '22951', '07779', '20014', '11981', '06149', '20364', '21103')
and bank_type = 'P' group by emp_num, bank_type, earn_hrs, used_paid_hrs, used_unpaid_hrs
The orginal table looks something like this:
EMP_NUM BANK_TYPE EARN_HRS USED_PAID_HRS END_DATE
60393 P 0.58 0 3-Aug-2004
60394 P 7.48 1 28-Oct-2003
60394 P 40 40 28-Oct-2004
60394 P 40 12.4 28-Oct-2005
60395 P 40 40 21-Oct-2004
60395 P 0 0 21-Oct-2003
60395 P 40 40 21-Oct-2005
60397 P 40 39.85 21-Oct-2004
60397 P 0.97 0.97 21-Oct-2003
Much thanks for any direction you can give to help guide me on my way to a solution. If you can help it please don't give me the answer, but try to give me the reason it's not working. I'll never learn if you give it to me right up front lol. Thanks again.
Luke
Message was edited by: trying to fix the table formating sorry it's so unreadable
Luke22
I just give you a prompt:
SQL> with t as (select 1 emp_num, 'A' bank, date '2007-08-01' dt from dual union all
2 select 1 emp_num, 'B' bank, date '2007-08-02' dt from dual union all
3 select 1 emp_num, 'C' bank, date '2007-08-03' dt from dual union all
4 select 2 emp_num, 'A' bank, date '2007-08-05' dt from dual union all
5 select 2 emp_num, 'B' bank, date '2007-08-04' dt from dual union all
6 select 3 emp_num, 'A' bank, date '2007-08-07' dt from dual union all
7 select 3 emp_num, 'C' bank, date '2007-08-08' dt from dual)
8 --
9 select emp_num, max(dt) from t
10 group by emp_num
11 /
EMP_NUM MAX(DT)
1 03.08.2007
2 05.08.2007
3 08.08.2007
SQL>
SQL> with t as (select 1 emp_num, 'A' bank, date '2007-08-01' dt from dual union all
2 select 1 emp_num, 'B' bank, date '2007-08-02' dt from dual union all
3 select 1 emp_num, 'C' bank, date '2007-08-03' dt from dual union all
4 select 2 emp_num, 'A' bank, date '2007-08-05' dt from dual union all
5 select 2 emp_num, 'B' bank, date '2007-08-04' dt from dual union all
6 select 3 emp_num, 'A' bank, date '2007-08-07' dt from dual union all
7 select 3 emp_num, 'C' bank, date '2007-08-08' dt from dual)
8 --
9 select emp_num, bank, max(dt) from t
10 group by emp_num, bank
11 /
EMP_NUM BANK MAX(DT)
1 A 01.08.2007
1 B 02.08.2007
1 C 03.08.2007
3 A 07.08.2007
2 A 05.08.2007
2 B 04.08.2007
3 C 08.08.2007
7 rows selected
SQL>
SQL> with t as (select 1 emp_num, 'A' bank, date '2007-08-01' dt from dual union all
2 select 1 emp_num, 'B' bank, date '2007-08-02' dt from dual union all
3 select 1 emp_num, 'C' bank, date '2007-08-03' dt from dual union all
4 select 2 emp_num, 'A' bank, date '2007-08-05' dt from dual union all
5 select 2 emp_num, 'B' bank, date '2007-08-04' dt from dual union all
6 select 3 emp_num, 'A' bank, date '2007-08-07' dt from dual union all
7 select 3 emp_num, 'C' bank, date '2007-08-08' dt from dual)
8 --
9 select emp_num, max(bank) keep (dense_rank last order by dt) bank, max(dt) from t
10 group by emp_num
11 /
EMP_NUM BANK MAX(DT)
1 C 03.08.2007
2 A 05.08.2007
3 C 08.08.2007
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