Slideshow from randomly selected picture out of selected keywords

Hey dear friends
I wish I would find a function in Aperture or even iPhoto, wherein I can set keywords and a timeslot and the application would give me back a randomly selected set of picture accordingly. At the end it is a feature like GENIUS in iTunes.
This would be very nice for family or friends session to have a look at picture normally forgotten, because not part of a print out or excisting perfectly styled slideshow
Can you share some ideas with me or even stimulate APPLE to create such a feature
Thanks and greetings here from Frankonia waiting for the Spring
Franz-Josef

The only way to get images randomly in Aperture is to use an AppleScript, Aperture has no built in random functionality.
If you search the list here for random images restricted to the Aperture community you'll find a number of posts discussing this.
regards

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If anybody has stumbled across this thread, having a similar problem to mine, you might be interested in how things finally turned out.
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How to efficiently get hold of N randomly selected keys out of X?

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Hi Magnus,
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Best regards,
Robert
Edited by: robvarga on Aug 7, 2009 11:55 AM
Added some more ideas and method implementation.

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Go to Solution.

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Oracle 11g:Query to return only 1 to 1 relationship & random selection

Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
create table s_test(sub_building_id number not null,building_id number ,invalid varchar2(1),sequence_no number);
insert into b_test values (1000,'N');
insert into b_test values(2000,'N');
insert into b_test values(3000,'N');
commit;
insert into s_test values(1,1000,'N',90);
insert into s_test values(2,1000,'N',91);
insert into s_test values(3,1000,'N',92);
insert into s_test values(4,1000,'Y',93);
insert into s_test values(5,NULL,'N',NULL);
insert into s_test values(1,2000,'N',94);
insert into s_test values(2,2000,'N',95);
insert into s_test values(3,2000,'N',96);
insert into s_test values(4,2000,'N',97);
insert into s_test values(5,2000,'N',98);
insert into s_test values(6,NULL,'N',NULL);
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);
commit;The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID      SUB_BUILDING_ID     SEQUENCE_NO
1000              N     1                     90
1000             N     2                     91
1000             N     3                     92
2000             N     1                     94
2000             N     2                     95
2000             N     3                     96
2000             N     4                     97
2000             N     5                     98
3000             N     10                      99
3000             N     11                     100Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query)
The results would be like
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000               N     1                      90
2000               N     1                      94
3000               N     11                     1002)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
The results will be:
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000             N     1                       90
1000             N     2                       90
1000             N     3                       90
2000             N     1                       94
2000              N     2                       94
2000             N     3                       94
2000             N     4                       94
2000             N     5                       94
3000             N     10                       99
3000             N     11                       99Many thanks!
Edited by: Krithi on 08-Nov-2012 08:48
Edited by: Krithi on 08-Nov-2012 08:55

Krithi wrote:
Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
Thanks for posting the CREATE TABLE and INSERT statements, and your existing query; that's very helpful.
The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID      SUB_BUILDING_ID     SEQUENCE_NO
1000              N     1                     90
1000             N     2                     91
1000             N     3                     92
2000             N     1                     94
2000             N     2                     95
2000             N     3                     96
2000             N     4                     97
2000             N     5                     98
3000             N     10                      99
3000             N     11                     100
When I run your query, I get NULL for sequence_no on the last 2 rows, where building_id=3000. The numbers 99 and 100 don't seem to occur in either table. Did you post the worng sample data and/or results?
>
Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query) Here's one way:
WITH       got_r_num AS
     SELECT sub_building_id
     ,     building_id
     ,     sequence_no
     ,     ROW_NUMBER () OVER ( PARTITION BY building_id
                               ORDER BY         sequence_no
                       )         AS r_num
     FROM    s_test
     WHERE     invalid     = 'N'
SELECT    b.building_id
,       b.invalid
,       r.sub_building_id
,       r.sequence_no
FROM             b_test     b
LEFT OUTER JOIN      got_r_num r ON r.building_id = b.building_id
WHERE     NVL ( r.r_num
           , 1
           )          = 1
ORDER BY b.building_id
;This is called a Top-N Query , because we're picking N items (N = 1 in this case) from the top of an ordered list. What makes one item the "top", and another one "lower"? That's determined by the analytic ORDER BY clause, in this case
ORDER BY      sequence_noThat means the row with the lowest sequence_no (for each building_id) will get r_num=1. If you want a random row from that building_id to be chosen as #1, then you can change the analytic ORDER BY clause to
ORDER BY      dbms_random.valueYou can ORDER BY anything you like, even a constant, but you must have an analytic ORDER BY clause. ROW_NUMBER requires an analytic ORDER BY clause.
The results would be like
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000               N     1                      90
2000               N     1                      94
3000               N     11                     100
Again, I don't see where the 100 comes from. The results I get are:
BUILDING_ID I SUB_BUILDING_ID SEQUENCE_NO
       1000 N               1          90
       2000 N               1          94
       3000 N              11
2)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
SELECT    b.building_id
,       b.invalid
,       s.sub_building_id
,       MIN (s.sequence_no) OVER ( PARTITION BY s.building_id)
                        AS seq_no
FROM             b_test b
LEFT OUTER JOIN      s_test s ON s.building_id = b.building_id
                            AND s.invalid      = 'N'
The results will be:
BUILDING_ID INVALID     SUB_BUILDING_ID     SEQUENCE_NO
1000             N     1                       90
1000             N     2                       90
1000             N     3                       90
2000             N     1                       94
2000              N     2                       94
2000             N     3                       94
2000             N     4                       94
2000             N     5                       94
3000             N     10                       99
3000             N     11                       99
Again, I don't see where you get sequence_no = 99. The results I get are:
BUILDING_ID I SUB_BUILDING_ID     SEQ_NO
       1000 N               1         90
       1000 N               2         90
       1000 N               3         90
       2000 N               1         94
       2000 N               2         94
       2000 N               5         94
       2000 N               3         94
       2000 N               4         94
       3000 N              10
       3000 N              11Edited by: Frank Kulash on Nov 8, 2012 12:12 PM
Added explanation and results
Edited by: Frank Kulash on Nov 8, 2012 12:28 PM
It looks like you cahnged your sample data from
insert into s_test values(10,3000,'N',NULL);
insert into s_test values(11,3000,'N',NULL);to
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);The queries I posted are niow getting 99, like you requested.

Recently I downloaded photos from an sd card. When the download was complete all photos were loaded in a random fashion completely out of order.This is the first time it has ever happened this way. downloaded same card to iPhoto and all photos were in ord

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JGG
edited by the Jolly Green Giant (where Green stands for environmentally friendly)

Is it possible to start slideshow from current picture?

Hi,
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There is possibility to select bunch of images and than start slideshow and slideshow will use only selected pictures but this is not what I want:
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Slideshow from randomly selected picture out of selected keywords

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