Spliting data wrt data available in the columns

Question

I have one table with column id,amnt1 and amnt2 with id as primary key
WITH table_1 AS
select '1' id, '200' amnt1,'100' amnt2 from dual union all
select '2' id, '200' amnt1,'' amnt2 from dual union all
select '3' id, '' amnt1,'100' amnt2 from dual union all
select '4' id, '50' amnt1,'' amnt2 from dualunion all
select '5' id, '150' amnt1,'270' amnt2 from dualunion all
select * from table_1
Depending up on the data in amnt1 and amnt2 i need to split the record.
In first case id = 1 i need to check if the amount is available in the columns.If both columns amnt is available then split that record in to 2 as below
WITH table_1 AS
select '1' id, '200' amnt1,'' amnt2 from dual union all
select '1' id, '' amnt1, '100' amnt2 from dual
select * from table_1
in second case id =2 only one row as only one row only one amnt contains data
WITH table_1 AS
select '2' id, '200' amnt1,'' amnt2 from dual
select * from table_1
In third case one row and in fourt case 1 row and fith case again two rows.
Basically if amnt1 and amnt2 contains data it has to split in to two.So the final result will be like
WITH table_1 AS
select '1' id, '200' amnt1,'' amnt2 from dual union all
select '1' id, '' amnt1,'100' amnt2 from dual union all
select '2' id, '200' amnt1,'' amnt2 from dual union all
select '3' id, '' amnt1,'100' amnt2 from dual union all
select '4' id, '50' amnt1,'' amnt2 from dual union all
select '5' id, '150' amnt1,'' amnt2 from dual union all
select '5' id, '' amnt1,'270' amnt2 from dual
select * from table_1
Please help
WITH table_1 AS
select '200' amnt1,'2010-02-02' date1,'100' amnt2,'2010-03-08' date2 from dual union all
select '500' amnt1,'2010-02-15' date1,'300' amnt2,'2010-02-08' date2 from dual union all
select '500' amnt1,'2010-02-18' date1,'300' amnt2,'2010-04-09' date2 from dual
select * from table_1

Answer 1

user10285699 wrote:
Not correct.this is not what i need.sorryYou said the final result should be...
SQL> WITH table_1 AS
  2  (
  3  select '1' id, '200' amnt1,'' amnt2 from dual union all
  4  select '1' id, '' amnt1,'100' amnt2 from dual union all
  5  select '2' id, '200' amnt1,'' amnt2 from dual union all
  6  select '3' id, '' amnt1,'100' amnt2 from dual union all
  7  select '4' id, '50' amnt1,'' amnt2 from dual union all
  8  select '5' id, '150' amnt1,'' amnt2 from dual union all
  9  select '5' id, '' amnt1,'270' amnt2 from dual
10  )
11  select * from table_1
12  /
I AMN AMN
1 200
1     100
2 200
3     100
4 50
5 150
5     270Saad Nayef's solution gives...
SQL> WITH table_1 AS (SELECT '1' id, '200' amnt1, '100' amnt2 FROM DUAL
  2                   UNION ALL
  3                   SELECT '2' id, '200' amnt1, '' amnt2 FROM DUAL
  4                   UNION ALL
  5                   SELECT '3' id, '' amnt1, '100' amnt2 FROM DUAL
  6                   UNION ALL
  7                   SELECT '4' id, '50' amnt1, '' amnt2 FROM DUAL
  8                   UNION ALL
  9                   SELECT '5' id, '150' amnt1, '270' amnt2 FROM DUAL)
10  SELECT id, amnt1, NULL amnt2 FROM table_1
11  UNION ALL
12  SELECT id, NULL, amnt2 FROM table_1
13  MINUS
14  SELECT id, NULL, NULL FROM table_1
15  /
I AMN AMN
1 200
1     100
2 200
3     100
4 50
5 150
5     270And if I did it my way I would get...
SQL> ed
Wrote file afiedt.buf
  1  WITH table_1 AS
  2  (
  3  select '1' id, '200' amnt1,'100' amnt2 from dual union all
  4  select '2' id, '200' amnt1,'' amnt2 from dual union all
  5  select '3' id, '' amnt1,'100' amnt2 from dual union all
  6  select '4' id, '50' amnt1,'' amnt2 from dual union all
  7  select '5' id, '150' amnt1,'270' amnt2 from dual
  8  )
  9  select id, amnt1, null amnt2 from table_1 where amnt1 is not null
10  union all
11  select id, null, amnt2 from table_1 where amnt2 is not null
12* order by 1, 2, 3
SQL> /
I AMN AMN
1 200
1     100
2 200
3     100
4 50
5 150
5     270All of which are identical results.
If there's something wrong in those, you'd better explain what you want, because you've been given a correct answer (hence why I didn't answer this question myself earlier as I could see it was correct).