The Document Information Panel was unable to load.

Question

Platform: SharePoint 2013, Office 2013.
Background: When you open an Office document from SharePoint users get this error:
The Document Information Panel was unable to load. The document will continue to load. For more information, contact your system administrator."
"The form cannot be opened. To fix this problem, contact the form designer. Form template:
http://<site address>/../proppanel.xsn. The XML Schema for the form template has an invalid value for the following attribute: location." 
I tried running this fix: http://www.cb-net.co.uk/microsoft-articles/2063-sharepoint-2010-templates-and-document-information-panel-errors, but it kept saying that it couldn’t see the url that
I specified (I did check this carefully); think it might only apply to SharePoint 2010 – perhaps the shell syntax is different in 2013.
Can anyone help me out?

Answer 1

Hi Alex,
According to your description, my understanding is that the error occurred when opening a document from SharePoint.
Is this document information panel customized?
I recommend to re-edit the document information panel template to see if the issue still occurs.
Please go to the Library setting > click the corresponding content type(need to enable managed of content types in Advanced settings) > click Document Information Panel settings.
If the issue still occurs, please check if the command below can help(change the site URL and the library name in the code):
Apply-Fix -siteUrl "http://your site URL "
function Apply-Fix($siteUrl)
clear
Add-PSSnapin "Microsoft.SharePoint.Powershell" -ErrorAction SilentlyContinue # -EA 0
[Environment]::CurrentDirectory=(Get-Location -PSProvider FileSystem).ProviderPath
foreach ($spwTarget in (Get-SPSite $siteUrl).RootWeb.Webs) {
Write-Host "Checking Web: " $spwTarget.Url
$list = $spwTarget.Lists["your library name"]
$fields = $list.fields
foreach($field in $fields)
if($field.SourceId -eq '{$ListId:your library name;}')
$schemaxml = $field.SchemaXML
$schemaxmldata = [xml]$schemaxml
$schemaxmldata.Field.SetAttribute("SourceID", $list.ID)
$schemaxml = $schemaxmldata.get_InnerXml()
$field.SchemaXML = $schemaxml
$field.Update()
Write-Host "Fixed" $field.Title "field in the library"
Write-Host "Done."
Best regards.
Thanks
Victoria Xia
TechNet Community Support