The Shift operator Question

Question

Dear sir/madam
I having question for the shift operator.
What different between >>> and >> ?
I have refer to sun tutorial, it state >>> is unsign, what does it mean?
and last is
if integer is 13
what anwer for 13>>8
is it move for 8 right by position? pls told me in detail
is it answer same with the 13>>>8 ?
Thanks for ur solutions

Answer 1

You can play with the following for a while.
final public class BinaryViewer{
  final static char[] coeffs = new char[]{(char)0x30,(char)0x31};
public static String toBinary(int n) {
  char[] binary = new char[32];
  for(int j=0;j<binary.length;j++) binary[j]=(char)0x30;
  int charPointer = binary.length -1;
  if(n==0) return "0";
  while (n!=0){
      binary[charPointer--] = coeffs[n&1];
      n >>>= 1;
return new String(binary);
public static void print(int n){
    System.out.print(BinaryViewer.toBinary(n));
    System.out.print("   ");
    System.out.println(String.valueOf(n));
public static void main(String[] args) throws Exception{
   int n=Integer.MIN_VALUE;//Integer.parseInt(args[0]);
   int m=Integer.MAX_VALUE;//Integer.parseInt(args[1]);
   BinaryViewer.print(n);
   BinaryViewer.print(n>>8);
   BinaryViewer.print(n>>>8);
   System.out.println();
   BinaryViewer.print(m);
   BinaryViewer.print(m>>8);
   BinaryViewer.print(m>>>8);
  System.out.println();
    n=1024;
    m=-1024;
   BinaryViewer.print(n);
   BinaryViewer.print(n>>8);
   BinaryViewer.print(n>>>8);
   System.out.println();
   BinaryViewer.print(m);
   BinaryViewer.print(m>>8);
   BinaryViewer.print(m>>>8);
  System.out.println();
   n=2048;
   m=-2048;
   BinaryViewer.print(n);
   BinaryViewer.print(n>>8);
   BinaryViewer.print(n>>>8);
   System.out.println();
   BinaryViewer.print(m);
   BinaryViewer.print(m>>8);
   BinaryViewer.print(m>>>8);
  System.out.println();
}