Very Important (Query to display the output in required format)

Question

CREATE TABLE TEMP(X VARCHAR2(10),Y VARCHAR2(100));
INSERT INTO TEMP('RIDER1','2001-12;2002-32;2003-42');
INSERT INTO TEMP('RIDER2','2001-52;2003-72');
SELECT * FROM TEMP
Initial Out Put in 2 columns X/Y_
X Y
RIDER1 2001-12;2002-32;2003-42
RIDER2 2001-52;2003-72
Write a Query to display the above data in the format below in 3 columns A/B/C*
A B C
Rider1 2001 12
Rider1 2002 32
Rider1 2003 42
Rider2 2001 52
Rider2 2003 72

Answer 1

So your old version doesn't support Regular expression. It will be very easy and efficient if you could use regular expression.
SQL> SELECT x,TRIM(REGEXP_SUBSTR(col2,'[^-]+', 1, 1)) col2,
  2           TRIM(REGEXP_SUBSTR(col2,'[^-]+', 1, 2)) col3
  3   FROM (
  4     SELECT DISTINCT x,regexp_substr (y, '[^;]+', 1, level) col2 
  5     FROM temp 
  6     CONNECT BY LEVEL <= LENGTH (REGEXP_REPLACE (y, '[^;]+'))  + 1
  7     ORDER BY 1,2
  8        );
X          COL2
COL3
RIDER1     2001
12
RIDER1     2002
32
RIDER1     2003
42
X          COL2
COL3
RIDER2     2001
52
RIDER2     2003
72But for your version you can use something like
SQL> /* By curtesy Frank Kulash */
SQL> SELECT x,SUBSTR(the_value,1,INSTR(the_value,'-',1)-1) col2,
  2           SUBSTR(the_value,INSTR(the_value,'-',1)+1)col3
  3  FROM (
  4        SELECT DISTINCT x,SUBSTR(y,
  5                            DECODE(level,
  6                                   1,
  7                                   1,
  8                                   INSTR(y, ';', 1, level - 1) + 1),
  9                            DECODE(INSTR(y, ';', 1, level),
10                                   0,
11                                   length(y),
12                                   instr(y, ';', 1, level) -
13                                   DECODE(level,
14                                          1,
15                                          0,
16                                          INSTR(y, ';', 1, level - 1)) - 1)) the_value
17                FROM temp
18              CONNECT BY level <=
19                         LENGTH(y) - LENGTH(REPLACE(y, ';')) + 1
20          )
21  ORDER BY 1,2,3                     
22       ;
X          COL2
COL3
RIDER1     2001
12
RIDER1     2002
32
RIDER1     2003
42
X          COL2
COL3
RIDER2     2001
52
RIDER2     2003
72
SQL>