Why is the wire broken in the attached program?

Cheers
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Attachments:
broken_circuit.PNG ‏10 KB

This VI is from the shipping example "Waveform and XY Plots.vi" and you are not using it right. As others have already hinted, you need an array of xy clusters. (Note the autoindexing output tunnel!).
Here's the code from the example.
What are you actually trying to do? Why don't you use a plain xy graph?
Message Edited by altenbach on 08-06-2009 02:45 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
xy.png ‏4 KB

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Im having trouble with my magsafe L adapter, i just bought my macbook pro around october-november 2011. just wondering if their still gonna replace it though i lost my receipt already. can i buy just the wire, i mean the "L" not the whole charger?

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Punch the computer's serial number here and check your coverage:
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Why is this wire broken?

Drop "New VI" onto diagram.
Right-click the terminal "type specifier VI refnum".
Select "Create -> Constant".
Right-click the constant.
Select "Select VI Server Class -> Browse...".
Browse to a VI.

jcrooke wrote:
Where is the New VI function located?
In LV9 you need to download and activate scripting to see this function.
https://decibel.ni.com/content/groups/labview-apis?view=overview
As to the original question, the Type Specifier input can be used to specify the New VI as a Generic VI, Facade VI, Method VI, etc.. A strictly typed VI refnum implies a specific connector pane and connections, this in not compatible with a New VI since this is a blank slate. The Help description is misleading, they simply copied and pasted from the Open VI Reference Function.
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I’m replicating 3 Exchange databases from our production active Exchange 2010 server across the WAN to another passive Exchange 2010 server at our DR site.
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Two things.
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on pllease
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in recent Exchange RUs aside.
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Microsoft Senior Exchange PFE
Blog:
http://blogs.technet.com/rmilne
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Note: Posts are provided “AS IS” without warranty of any kind, either expressed or implied, including but not limited to the implied warranties of merchantability and/or fitness for a particular purpose.

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http://img520.imageshack.us/img520/985/linksyswag54gx2pic1wb2.jpg
http://img442.imageshack.us/img442/395/linksyswag54gx2pic2dy5.jpg
http://img442.imageshack.us/img442/2549/linksyswag54gx2pic3ih4.jpg
http://img442.imageshack.us/img442/7159/linksyswag54gx2pic4bp3.jpg
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http://img248.imageshack.us/img248/4908/wrt110pic1tv3.jpg
http://img248.imageshack.us/img248/6950/wrt110pic2vc5.jpg
http://img248.imageshack.us/img248/5788/wrt110pic3fr1.jpg
http://img248.imageshack.us/img248/4682/wrt110pic4vd6.jpg
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I created boolean references in my main vi block diagram and copied them to my sub vi front panel. when wire my reference in my main vi to one the input node of the sub vi the wire is broken. the error says its a class conflict why?

i created boolean references in my main vi block diagram and copied them to my sub vi front panel. when wire my reference in my main vi to one the input node of the sub vi the wire is broken. the error says its a class conflict why?

Expanding and clarifying what BJD said;
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In the attached VI why does one loop coerce the data type while the other doesn't?

In the attached VI why does one loop coerce the data type while the other doesn't?
Solved!
Go to Solution.
Attachments:
AAA.vi ‏8 KB

I'm guessing you created the Enum on the front panel. If you right-click it and create an indicator, it will match the type, and be an enum. LabVIEW represents enums as U16, but because the types aren't identical (for example, your enum has 3 values, but a U16 has 65,536 values), LabVIEW automatically coerces (or converts) the smaller (enum) representation into the larger (U16) value.

Why is the wire broken in the attached program?

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